for the population mean p? hg

A fitness center is interested in finding a 95% confidence interval for the mean number of days per week that Americans who are members of a fitness club go to their fitness center. Records of 238 members were looked at and their mean number of visits per week was 3.1 and the standard deviation was 2.8. Round answers to 3 decimal places where possible.   a. With 95% confidence the population mean number of visits per week is between  and   visits. b. If many groups of 238 randomly selected members are studied, then a different confidence interval would be produced from each group. About  percent of these confidence intervals will contain the true population mean number of visits per week and about  percent will not contain the true population mean number of visits per week.

Can you answer part d and e for 7.8

A sample of 10 networking sites for a specific month has a mean of 26.1 and a standard deviation of 4.2. Prompt Find the value of ta Answer Choose a match O 3.25 1.83 ta/2 with 99% confidence level. O 20.5 μ<31.5 O21.78 <μ< 30.42

If an observation has a z-score of -1.5, how many standard deviations is it above or below the mean? O 0.066 standard deviations above the mean O 1.5 standard deviations above the mean O 1.5 standard deviations below the mean O 0.066 standard deviations below the mean

A fitness center is interested in finding a 90% confidence interval for the mean number of days per week that Americans who are members of a fitness club go to their fitness center. Records of 225 members were looked at and their mean number of visits per week was 2.1 and the standard deviation was 1.9. Round answers to 3 decimal places where possible.   a. With 90% confidence the population mean number of visits per week is between  and   visits. b. If many groups of 225 randomly selected members are studied, then a different confidence interval would be produced from each group. About  percent of these confidence intervals will contain the true population mean number of visits per week and about  percent will not contain the true population mean number of visits per week.

How much money does the average professional hockey fan spend on food at a single hockey game? That question was posed to 10 randomly selected hockey fans. The sampled results show that sample mean and standard deviation were $12.00 and $2.80, respectively. Use this information to create a 95% confidence interval for the mean. Express the answer in the form x+ t/2 (s/ Vn). O A. 12+ 1.833(2.80//10) O B. 12+2.262(2.80//10 OC. 12+2.228(2.80//10) O D. 12+2.201(2.80//10)

This is for statistics and probability

Using techniques from an earlier section, we can find a confidence interval for ?d. Consider a random sample of n matched data pairs A, B. Let d = B − A be a random variable representing the difference between the values in a matched data pair. Compute the sample mean  d  of the differences and the sample standard deviation sd. If d has a normal distribution or is mound-shaped, or if n ≥ 30, then a confidence interval for ?d is as follows. d − E < ?d < d + E where  E = tc  sd   n c = confidence level (0 < c < 1) tc = critical value for confidence level c and d.f. = n − 1 B: Percent increasefor company 16 24 8 18 6 4 21 37 A: Percent increasefor CEO 18 16 18 14 −4 19 15 30 (a) Using the data above, find a 95% confidence interval for the mean difference between percentage increase in company revenue and percentage increase in CEO salary. (Round your answers to two decimal places.) lower limit upper limit  (b) Use the confidence interval…

Use these statements for 8-10. Suppose x has a distribution with a mean of 13.9 and a standard deviation of 2.1. Random samples of size n=49 are drawn  What would be the mean and standard deviation of the distribution?