Using techniques from an earlier section, we can find a confidence interval for ?d. Consider a random sample of n matched data pairs A, B. Let d = B − A be a random variable representing the difference between the values in a matched data pair. Compute the sample mean d of the differences and the sample standard deviation sd. If d has a normal distribution or is mound-shaped, or if n ≥ 30, then a confidence interval for ?d is as follows. d − E < ?d < d + E where E = tc sd n c = confidence level (0 < c < 1) tc = critical value for confidence level c and d.f. = n − 1 B: Percent increase for company 16 24 28 18 6 4 21 37 A: Percent increase for CEO 22 14 18 14 −4 19 15 30 (a) Using the data above, find a 95% confidence interval for the mean difference between percentage increase in company revenue and percentage increase in CEO salary
Using techniques from an earlier section, we can find a confidence interval for ?d. Consider a random sample of n matched data pairs A, B. Let d = B − A be a random variable representing the difference between the values in a matched data pair. Compute the sample mean d of the differences and the sample standard deviation sd. If d has a normal distribution or is mound-shaped, or if n ≥ 30, then a confidence interval for ?d is as follows. d − E < ?d < d + E where E = tc sd n c = confidence level (0 < c < 1) tc = critical value for confidence level c and d.f. = n − 1 B: Percent increase for company 16 24 28 18 6 4 21 37 A: Percent increase for CEO 22 14 18 14 −4 19 15 30 (a) Using the data above, find a 95% confidence interval for the mean difference between percentage increase in company revenue and percentage increase in CEO salary
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Using techniques from an earlier section, we can find a confidence interval for ?d. Consider a random sample of n matched data pairs A, B. Let d = B − A be a random variable representing the difference between the values in a matched data pair. Compute the sample mean
normal distribution or is mound-shaped, or if n ≥ 30, then a confidence interval for ?d is as follows.
d
of the differences and the sample standard deviation sd. If d has a d − E < ?d < d + E
where
E = tc
sd | ||
|
c = confidence level (0 < c < 1)
tc = critical value for confidence level c and d.f. = n − 1
B: Percent increase for company |
16 | 24 | 28 | 18 | 6 | 4 | 21 | 37 |
---|---|---|---|---|---|---|---|---|
A: Percent increase for CEO |
22 | 14 | 18 | 14 |
−4
|
19 | 15 | 30 |
(a)
Using the data above, find a 95% confidence interval for the mean difference between percentage increase in company revenue and percentage increase in CEO salary. (Round your answers to two decimal places.)
lower limitupper limit
(b)
Use the confidence interval method of hypothesis testing to test the hypothesis that population mean percentage increase in company revenue is different from that of CEO salary. Use a 5% level of significance.
Since ?d = 0 from the null hypothesis is in the 95% confidence interval, do not reject H0 at the 5% level of significance. The data do not indicate a difference in population mean percentage increases between company revenue and CEO salaries.Since ?d = 0 from the null hypothesis is not in the 95% confidence interval, reject H0 at the 5% level of significance. The data indicate a difference in population mean percentage increases between company revenue and CEO salaries. Since ?d = 0 from the null hypothesis is in the 95% confidence interval, reject H0 at the 5% level of significance. The data do not indicate a difference in population mean percentage increases between company revenue and CEO salaries.Since ?d = 0 from the null hypothesis is not in the 95% confidence interval, do not reject H0 at the 5% level of significance. The data indicate a difference in population mean percentage increases between company revenue and CEO salaries.
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