Fluoride anion and hydronium cation react to form hydrofluoric acid and water, like this: F (aq)+H₂O (aq)-HF(aq)+H₂O(1) At a certain temperature, a chemist finds that a 5.9 L reaction vessel containing an aqueous solution of fluoride anion, hydronium cation, hydrofluoric acid, and water at equilibrium has the following composition: compound amount F 0.138 g H₂O* 0.217 g HF 1.93 g H₂O 599. g Calculate the value of the equilibrium constant K for this reaction. Round your answer to 2 significant digits. S

World of Chemistry, 3rd edition
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Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
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Chapter17: Equilibrium
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Fluoride anion and hydronium cation react to form hydrofluoric acid and water, like this:
F (aq) + H₂O (aq) →HF (aq) + H₂O(l)
At a certain temperature, a chemist finds that a 5.9 L reaction vessel containing an aqueous solution of fluoride anion, hydronium cation, hydrofluoric acid, and
water at equilibrium has the following composition:
amount
0.138 g
compound
F
H₂O*
HF
H₂O
Calculate the value of the equilibrium constant K for this reaction. Round your answer to 2 significant digits.
0.217 g
K = 0
1.93 g
599. g
X
Transcribed Image Text:Fluoride anion and hydronium cation react to form hydrofluoric acid and water, like this: F (aq) + H₂O (aq) →HF (aq) + H₂O(l) At a certain temperature, a chemist finds that a 5.9 L reaction vessel containing an aqueous solution of fluoride anion, hydronium cation, hydrofluoric acid, and water at equilibrium has the following composition: amount 0.138 g compound F H₂O* HF H₂O Calculate the value of the equilibrium constant K for this reaction. Round your answer to 2 significant digits. 0.217 g K = 0 1.93 g 599. g X
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