The reaction N2(g) + 3 H2(g) ⇀↽ 2 NH3(g), has an equilibrium constant of 4.0 × 108 at 25◦C. What will eventually happen if 44.0 moles of NH3, 0.452 moles of N2, and 0.108 moles of H2 are put in a 10.0 liter container at 25◦C?  More N2 and H2 will be formed.  Nothing; the system is at equilibrium.  More NH3 will be formed.

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