No software is required. I just need a explaintion of what is happening to this truss. Educational License - For Educational and Training Use OnlyV: 10.001198L: 1C: 10.-5.-15.-20.-25.-30.༠༠༤༠༠ནྟ123456-10.34563456Top34560. 5. 10. 15. 20. 25. 30. 33456Output Set: Simcenter NASTRAN Case 1Deformed (0.001198): Total TranslationNodal Contour: Total Translation0.0011230.0010480.00097330.00089840.00082360.00074870.00067380.0005990.0005241134560.00044920.000374365. 70. 75. 0. 85. 90. 5.100.10 110.115.1 0.34560.0002995345634560.0002246134660.0001497200.200.0.00007487FEMAP

The figure shows the translation or the movement of the truss with respect to its original position.…

Answered: Educational License - For Educational…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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ZVA @ e SIM a A moodle1.du.edu.om Solve the second order homogeneous differential equation y " -6y'-7y = 0 with intial values y(0) = 0; y'(0) = 1 %3D Maximum file size: 200MB, maximum number of files: 1 Files II
f Facebook (60) Binary operation (Mather x b Answered: Some states have x M Item shared with you: "Proble x 4 Problem Set 2-2_Axial Load- + A drive.google.com/file/d/1n5tC5BPOCKLLBIVXPMF8h9X3FCxLCHKu/view?ts=6153bb21 submissions. Do not attempt to submit others work as your own, rules agreed on course orientation will apply. 1.0 The post weighs 8 kN/m. Determine the internal normal force in the post as a function of x. 2 m 2.0 The rigid beam supports the load of 60 kN. Determine the displacement at B. Take E = 60 GPa, and ABC = 2 x 10-3 m2 60 kN -2 m- 4 m B 2 m 3 m D ENGG 410 | Fundamentals of Deformable Bodies 09:07 P Type here to search 28°C Partly sunny 29/09/2021
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otINote: The notation from this problem is from Understanding Cryptography by Paar and Pelzl. We conduct a known-plaintext attack against an LFSR. Through trial and error we have determined that the number of states is m = 4. The plaintext given by when encrypted by the LFSR produced the ciphertext 01011000 = yo yı y2 ys Yo Y %3D What are the tap bits of the LFSR? Please enter your answer as unspaced binary digits (e.g. 0101 to represent py = 0, P = 1, P = 0, Po= 1).
Given the following discrete time system where y[n] is the system output and x[n] is the input, indicate which of the provided options are the discrete poles of the system. yln] = 0.7y[n – 1] – 0.4y[n – 2] + 2x[n – 1] + 4x[n – 3] Select one: O a. 0.5 + j0.9634 O b. 0.35 + j0.52 O c. -0.25 + j0.45 O d. 0.35 + j0.152
DOM 1500 N A327197870 X SA LPU Live C MCQ (Mult x Creative Steal X Battlefield haX 97870 133937_2022_G2CA3MEC107.pdf 6 News [OFFICIAL]Filmora. Hillm Clipmaker - Online... INTROANIME- Pan... Adventure Archives... Free Download PC.. |E Readin- %001 Q 回 ictioniesS. OSIV tension in the cables. DULL N 09 Q3: As shown in figure, find that at what distance body A will attain a velocity of 3 m/s 4. B. when starts from rest. N 000 3. Assume coefficient frietion as 0.2 for block and of surface and pulleys are frictionless and weightless. 2. 20:07 14-01-2022 NI
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7:22 ull || 34% ENS 161: STATICS OF RIGID BODIES PROBLEM SET 1 Due: Oct. 20, 2021, 12nn Instructions: 1. Copy and answer the problems. Handwritten. Make sure you write legibly and orderly. 2. Take photographs of your solution. Please provide a readable photo. 3. Upload image files of your photographs as submission. Make sure you have successfully sent your files before leaving the page. 1 P= 70N at 0. and Q intersects Determine B if the resultant of these forces is 10ON. Also, determine the direction, 0, of the resultant. Forces P a = 40° Q= 50N 2 250 T2 B A telephone cable is clamped at A to the pole AB. Knowing that the tension in the right-hand portion of the cable is T, = 1000 īb, deter- mine by trigonometry (a) the required tension T¡ in the left-hand portion if the resultant R of the forces exerted by the cable at A is to be vertical, (b) the corresponding magnitude of R. 1 of 6 A steel tank is to be nositioned in an excavation. Knowing that the ||
T FL %24 E Tradi G 0.169 iGen selec + Launc - SIS S 25 (25) V Teleg 3 Drop do, -bf M Inbc heducation.com/ext/map/index.html?_con%3Dcon&lexternal_browser%3D0&launchUrl=https%253A%252F%252Fnewconnect.mheducation.com%252F#/activity/c Help Save & Saved Required information A cylindriçal fuel rod (k 30 W/m K) of 2 cm in diameter is encased in a concentric tube and cooled by water. The fuel rod generates heat uniformly at a rate of 100 MW/m, and the average temperature of the cooling water is 80°C with a convection heat transfer coefficient of 2500 W/m4-K. The operating pressure of the cooling water is such that the surface temperature pf the fuel rod must be kept below 200°C to avoid the cooling water from reaching the critical heat flux (CHF). The crițical heat flux is a thermal limit at which a boiling crisis can occur that cause overheating on the fuel rod surface and lead to damage. ė ren = 100 MW/m3 %3D Cooling water Fuel rod D=2 cm 2500 W/m2-K Determine the temperature of the fuel rod…
Fantastick. of 6) A Microsoft PowerPoint - chapter 2 x O Rotational system.pdf O Essay on Life in a Big City for Stu x 10 Advantages of Living A https://moodle1.du.edu.om/mod/quiz/attempt.php?attempt340840&cmid%3D2247468&page=D4 - Moodle English (en) - 01(1) 18 N-m-s/rad 1 N-m-s/rad T(1) 02(1) $ kg-m2 3 kg-m2 3 N-m/rad 9 N-m/rad (a) Figure P2.16a John Wiley & Sons, Inc. All rights reserved. The transfer function where the output Theta, is 0,(s) H(s) = T(s) s² +5s +1 s* +30s` +80s² +s +15 a. %3D S 0,(s) b. H(s)=- s´+5s +1 %3D 25s +30s +80s² +s+15 4. T(s) 0,(s) H(s)= - T(s) 5s² +9s +9 15s* +30s+95s² + s+ 27 c. 4. 5s +9s +9 0,(s) d. H(s)= T(s) 15s +32s +95s² +99s+ 27
8086 Microprocessor lab. | 9 Discussion: Two word - wide unsigned integers are stored at the memory addresses OA00 H and OA02 H respectively, Write an instruction sequence that computes and stores their sum, difference, product, and quotient then Store these results at consecutive memory locations starting at address 0A10 H in memory. To obtain the difference, subtract the integer at OA02 H from the integer at OA00 H. For the division, divide the integer at OA00H by the integer at OA02 H. Use register indirect relative addressing mode to store the various result.
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