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e the following method is outside the class of KWArrayList class but has access to the methods of KWArrayList class    public static void Unknown(KWArrayList list1, KWarrayList list2)              {                  if (list1.size() == 0 || list2.size() ==0) return;                  int loop;                  if (list1.size() < list2.size())                    loop= list1.size();                  else loop= list2.size();                  for (int i=0; i

e the following method is outside the class of KWArrayList class but has access to the methods of KWArrayList class    public static void Unknown(KWArrayList list1, KWarrayList list2)              {                  if (list1.size() == 0 || list2.size() ==0) return;                  int loop;                  if (list1.size() < list2.size())                    loop= list1.size();                  else loop= list2.size();                  for (int i=0; i

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Assume the following method is outside the class of KWArrayList class but has access to the methods of KWArrayList class

 

 public static void Unknown(KWArrayList<Integer> list1, KWarrayList<Integer> list2)

             {

                 if (list1.size() == 0 || list2.size() ==0) return;

                 int loop;

                 if (list1.size() < list2.size())

                   loop= list1.size();

                 else loop= list2.size();

                 for (int i=0; i<loop; i++)

                   list1.set(i,(Integer) list1.get(i) + (Integer) list2.get(i))

                }

O a. It changes the elements of list1 as each element in listl would be the summation of the old value in list1 with the corresponding value in list 2 based on the size of the larger list, list1 or list2. O b. It changes the elements of list1 as each element in list1 would be the summation of the old value in list1 with the corresponding value in list 2 based on list1 size. O.It changes the elements of list1 as each element in listl would be the summation of the old value in listl with the corresponding value in list 2 based on the size of the smaller list, list1 or list2. d. It changes the elements of listl as each element in list1 would be the summation of the old value in list1 with the corresponding value in list 2 based on list2 size.
Transcribed Image Text:O a. It changes the elements of list1 as each element in listl would be the summation of the old value in list1 with the corresponding value in list 2 based on the size of the larger list, list1 or list2. O b. It changes the elements of list1 as each element in list1 would be the summation of the old value in list1 with the corresponding value in list 2 based on list1 size. O.It changes the elements of list1 as each element in listl would be the summation of the old value in listl with the corresponding value in list 2 based on the size of the smaller list, list1 or list2. d. It changes the elements of listl as each element in list1 would be the summation of the old value in list1 with the corresponding value in list 2 based on list2 size.
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