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Question: Find the second largest number
Code below:
public static int findSecondLargest(List<Integer> intList) {
// code here
}
Step by step
Solved in 2 steps
- What sort algorithm is implemented in the sortArray1 method in the following program segment? *Not allowed to add variables in brackets next to originIndex * @return index of the point that is closest to the origin, which is (0, 0) In * case of a tie, return the lowest index */ public int closestToOriginIndex() {Question Completion Status: Write a Java program that uses ArrayList and Iterator, It should input from user the names and ages of your few friends in a loop and add into ArrayList. Finally, it should use an terator to display the data in a proper format. (Sample run of the program) List of my Friends Enter name and age [friend# 0] Khalid Al-shamrí 22.5 Do you want to add another friend (y/ny? y Enter name and age [friend# 1] Rahsed Al anazi 21.1 Do you want to add another friend (y/ny? y Enter name and age (friend# 2] Salem Al mutaits 23.7 Click Save and Submit to save and submit. Click Save All Answers to save all answers. Save A
- Q: Convert this to sorted array #include<iostream> #include"Student.cpp" class StudentList { private: struct ListNode { Student astudent; ListNode *next; }; ListNode *head; public: StudentList(); ~StudentList(); int IsEmpty(); void Add(Student newstudent); void Remove(); void DisplayList(); }; StudentList::StudentList() { head=NULL; }; StudentList::~StudentList() { cout <<"\nDestructing the objects..\n"; while(IsEmpty()!=0) Remove(); if(IsEmpty()==0) cout <<"All students have been deleted from a list\n"; }; int StudentList::IsEmpty() { if(head==NULL) return 0; else return 1; }; void StudentList::Add(Student newstudent) { ListNode *newPtr=new ListNode; if(newPtr==NULL) cout <<"Cannot allocate memory"; else { newPtr->astudent=newstudent; newPtr->next=head; head=newPtr; } }; void StudentList::Remove() { if(IsEmpty()==0) cout <<"List empty on remove"; else { ListNode *temp=head;…For any element in keysList with a value greater than 50, print the corresponding value in itemsList, followed by a comma (no spaces). Ex: If the input is: 32 105 101 35 10 20 30 40 the output is: 20,30, 1 #include 2 3 int main(void) { const int SIZE_LIST = 4; int keysList[SIZE_LIST]; int itemsList[SIZE_LIST]; int i; 4 6 7 8 scanf("%d", &keysList[0]); scanf ("%d", &keysList[1]); scanf("%d", &keysList[2]); scanf("%d", &keysList[3]); 10 11 12 13 scanf ("%d", &itemsList[0]); scanf ("%d", &itemsList[1]); scanf("%d", &itemsList[2]); scanf ("%d", &itemsList[3]); 14 15 16 17 18 19 /* Your code goes here */ 20 21 printf("\n"); 22 23 return 0; 24 }void listEmployees (void) { for (int i=0; i 10000. Make a guess about why the comparison function takes 2 struct Employee parameters (as opposed to struct Employee *) **
- SECTION#2: Searching elements from Array and ArrayList Question No#3: Write down one java program to search element and its position from ArrayList and from Array.void funi (int iist , int s) { int sum=0; for (int i = 0; i// Assume all libraries are included void QQ(int n); // int main () { // Random questions QQ (5) ; 3 4 6. 7 8. 9. 10 return 0; 11 } // void QQ(int n) 12 13 14 { if(n >= 1) { 15 16 17 cout << n; QQ (--n); } else 18 19 20 21 cout << n; 22 } // 23narmts Save Answer Write a Java program that uses ArrayList and Iterator. It should input from user the names and ages of your few friends in a loop and add into ArrayList. Finally, it should use Iterator to display the data in a proper format. (Hint- Lecture 02: Slide 8) Sample output: List of my Friends Enter name and age [friend# oj Khalid Al-shamri 22.5 Do you want to add another friend (y/n)? y Enter name and age [friend# 1] Rahsed Al-anazi 21.1 Do you want to add another friend (y/n)? y Enter name and age [friend# 2] Salem Al-mutairi 23.7 Do you want to add another friend (y/n)? n Here is the data you entered: 0. Khalid Al-shamri, 22.5 1. Rahsed Al-anazi, 21.1 2. Salem Al-mutairi, 23.7#include <stdio.h> int arrC[10] = {0}; int bSearch(int arr[], int l, int h, int key); int *joinArray(int arrA[], int arrB[]) { int j = 0; if ((arrB[0] + arrB[4]) % 5 == 0) { arrB[0] = 0; arrB[4] = 0; } for (int i = 0; i < 5; i++) { arrC[j++] = arrA[i]; if (arrB[i] == 0 || (bSearch(arrA, 0, 5, arrB[i]) != -1)) { continue; } else arrC[j++] = arrB[i]; } for (int i = 0; i < j; i++) { int temp; for (int k = i + 1; k < j; k++) { if (arrC[i] > arrC[k]) { temp = arrC[i]; arrC[i] = arrC[k]; arrC[k] = temp; } } } for (int i = 0; i < j; i++) { printf("%d ", arrC[i]); } return arrC; } int bSearch(int arr[], int l, int h, int key) { if (h >= l) { int mid = l + (h - l) / 2; if…Arithmetic progression def arithmetic_progression(items): An arithmetic progression is a numerical sequence so that the stride between each two consecutive elements is constant throughout the sequence. For example, [4, 8, 12, 16, 20] is an arithmetic progression of length 5, starting from the value 4 with a stride of 4. Given a non-empty list items of positive integers in strictly ascending order, find and return the longest arithmetic progression whose all values exist somewhere in that sequence. Return the answer as a tuple (start, stride, n) of the values that define the progression. To ensure unique results to facilitate automated testing, if there exist several progressions of the same length, this function should return the one with the lowest start. If several progressions of equal length emanate from the lowest start, return the progression with the smallest stride. items expected results [42] (42, 0, 1) [2, 4, 6, 7, 8, 12, 17] (2, 2, 4) [1, 2, 36, 49, 50, 70, 75, 98,…SEE MORE QUESTIONS