Drag conversion units onto the boxes in the equation to make conversions. Some boxes can be left empty. Click on a unit to remove it from its position. 1 cm³ Cu 1 kg 1 L 1.30 x 108 atoms X = = = 9 g Cu 1000 g 1000 cm³ X 9.5 x 1021 atoms Cu 1 cm³ = 1 g Cu = 1 mL A piece of copper contains 1.3x108 atoms. What is the mass of the sample, in units of grams? In the boxes above, enter the correct setup that would be used to solve this problem. X

A 0.755-g sample of hydrated copper(II) sulfate CuSo4xH2O was heated carefully until it had changed completely to anhydrous copper(II) sulfate (CuSO4 ) with a mass of 0.4183 g. Determine the value of x. [This number is called the number of waters of hydration of copper(II) sulfate. It specifies the number of water molecules per formula unit ofCuSO4 in the hydrated crystal.]

Find the item in column 2 that best explains or completes the statement or question in column 1. l type="a"> Column 1 i>1 amu 1008 amu mass of the “average” atom of an element number of carbon atoms in 12.01 g of carbon 6.0221023 molecules total mass of all atoms in 1 mole of a compound smallest whole-number ratio of atoms present in a molecule formula showing actual number of atoms present in a molecule product formed when any carbon-containing compound is burned in O2 i>have the same empirical formulas, but different molecular formulas Column 2 msp;6.0221023 i>atomic mass mass of 1000 hydrogen atoms benzene, C6H6 , and acetylene, C2H2 i>carbon dioxide empirical formula 1.661023g i>molecular formula molar mass 1 mole

With the advent of techniques such as scanning tunneling microscopy, it is now possible to write with individual atoms by manipulating and arranging atoms on an atomic surface. a. If an image is prepared by manipulating iron atoms and their total mass is 1.05 1020 g, what number of iron atoms were used? b. If the image is prepared on a platinum surface that is exactly 20 platinum atoms high and 14 platinum atoms wide, what is the mass (grams) of the atomic surface? c. If the atomic surface were changed to ruthenium atoms and the same surface mass as determined in part b is used, what number of ruthenium atoms is needed to construct the surface?