Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Transcribed Image Text:In class, students were given the following problem:
"Aluminum satellite dishes resist corrosion because aluminum reacts with oxygen gas (0₂) to form a
coating of aluminum oxide (Al2O3) according to the following chemical equation:
4Al(s) + 302(g) →2A/203(s)
What is the mass of 9.45 moles of Al 203?
After correctly solving for the molar mass of Al2O3, Jacob set up the following conversion:
1 mole AL, Q
9.45 moles Al₂O3× 102.2 grams of Al, 0,
Is this answer correct?
= 0.0926 grams of Al2O3
Transcribed Image Text:A
1 mole = 6.02 x 10²³ particles
✓
N
6.02 x 10 particles
1 mole
C
6.02 x 10¹ particles
B 1 mole = molar mass* (grams)
"S
determined by summing the ma 1 of all elements in the formula
1 mole = 22.4 L of gas
Inde
7241
22.4 L
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