Discuss why Mendel's hybrid offspring begin to exhibit the original traits expressed by the P1 generation or the pure-breeding parents used in the original cross. What would happen if the hybrid offspring were allowed to breed without interference from Mendel for an extended period of time and the different ways plants can breed.
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Discuss why Mendel's hybrid offspring begin to exhibit the original traits expressed by the P1 generation or the pure-breeding parents used in the original cross. What would happen if the hybrid offspring were allowed to breed without interference from Mendel for an extended period of time and the different ways plants can breed.
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- A plant geneticist is examining the mode of inheritance of flower color in two closely related species of exotic plants. The first species may have two pure-breeding lines—one produces a distinct red flower; and the other produces flowers with no color at all, or very pale yellow flowers. However, she cannot be sure. A cross of these varieties produces all pink-flowered progeny. The second species exhibits similar pure-breeding varieties; that is, one variety produces red flowers; and the other produces an albino or very pale yellow flower. A cross of these two varieties, however, produces orange-flowered progeny exclusively. Analyze the mode of inheritance of flower color in these two plant species.Mendel obtained his initial pea plant varieties from local breeders who were developing new varieties that might be useful or interesting. To generate these new varieties, breeders formed hybrids between existing varieties of different phenotypic characteristics by cross-pollination, using techniques they doubtless taught to Mendel. After producing a hybrid, they allowed several generations of self-pollination, as happens naturally if the flowers are not disturbed. i. How many generations would it take for a breeder to have produced new pure-breeding varieties using this approach? ii. What is the probability that an individual in each of these generations (F2, F3, and F10) would be homozygous for one or the other allele of this gene? [Broad hint: if they’re not heterozygous, they’re homozygous!] please answer and explain properlyIn this program, you are provided with phenotype pair counts of F2 offspring at two research institutes. The key different between this work and previous work is that now we consider two genes instead of one. The phenotype pairs are the (shape, color) of peas from a pea plant. It turns out that there are two separate genes that code for these phenotypes. We shall call them Shape and Color. Gregor Mendel originally recorded these experiments in green peas. Using the notation: R = Round (dominant) allele at Shape gene; r = Wrinkled (recessive) allele at Shape gene; Y = Yellow (dominant) allele at Color gene; y = Green (recessive) allele at Color gene; then the shape and color of any pea can be determined by studying the genotypes at each gene. It turns out that, when one mates a plant that is homozygous for the dominant alleles (RRYY) with a plant that is homozygous for the recessive alleles (rryy), the F1 generation are heterozygous at both genes, as with a single gene disorder.…
- Mendel obtained his initial pea plant varieties from local breeders who were developing new varieties that might be useful or interesting. To generate these new varieties, breeders formed hybrids between existing varieties of different phenotypic characteristics by cross pollination, using techniques they doubtless taught to Mendel. After producing a hybrid, they allowed several generations of self-pollination, as happens naturally if the flowers are not disturbed. a. How many generations would it take for a breeder to have produced new pure-breeding varieties using this approach? b. What is the probability that an individual in each of these generations (F2, F3, and F10) would be homozygous for one or the other allele of this gene?Mendel obtained his initial pea plant varieties from local breeders who were developing new varieties that might be useful or interesting. To generate these new varieties, breeders formed hybrids between existing varieties of different phenotypic characteristics by cross pollination, using techniques they doubtless taught to Mendel. After producing a hybrid, they allowed several generations of self-pollination, as happens naturally if the flowers are not disturbed. a. How many generations would it take for a breeder to have produced new pure-breeding varieties using this approach? i. First, consider just one heterozygous gene in the F1 hybrid. What is the probability that an individual of the F2 generation would be heterozygous for that gene? ii. What is the probability that an individual in the F3 generation would be heterozygous for this gene? iii. What is the probability that an individual in the F10 generation would be heterozygous for this gene? iv. What is the…Variations in Gene Expression In a cross involving polygenic inheritance, three (3) gene pairs control plant height. The shortest and tallest plants are 12 cm and 24 cm, respectively. What height should all F1s display if the shortest and tallest plants were crossed, assuming environmental factors are the same. COMPLETE SOLUTION.
- Gregor Mendel examined the inheritance of two traits in pea plants: seed coat texture and colour. Seed coat texture can be represented as S-smooth and s-wrinkled, and seed coat colour can be represented as Y-yellow and y-green. SSYY plants were crossed with ssyy plants to yield F1 pea seeds that were all smooth and all yellow. By crossing plants grown from these F1 seeds, Mendel obtained four different phenotypes of F2 seeds: • smooth and green seeds wrinkled and green seeds smooth and yellow seeds wrinkled and yellow seeds ● Use the following information to answer the next question. ● The F2 phenotypic ratio that Mendel obtained upon crossing two heterozygous smooth and yellow F1 individuals would have been: smooth and green wrinkled and green : smooth and yellow: wrinkled and yellow Record only the numeric values associated with the phenotypes. (Do not include the colons, spaces, commas, etc.)Stem length in plants is controlled by two CODOMINANT alleles of one autosomal - one allele, B, adds 2 cm to the length of the plant, and another allele, b reduces length by 0.5 cm. The base length of the plant's stem is 10 cm. A plant breeder wants to breed plants that are exactly 14.5 cm in stem length. He starts with crossing two heterozygotes, Bb x Bb. gene Assuming that you can ONLY breed plants of the same stem length, what cross(es) would the breeder have to set up in order to achieve this? Let's (i) (ii) that stem length segregates independently from flower color (also a say monogenic, autosomal, biallelic trait). If you crossed a homozygote from (i) i.e. a bb and homozygote red flowers with a plant that is homozygote BB and homozygote white flowers, intercross the F1, and observe the following numbers of progeny in the F2 generation: (iii) Height Flower Color Observed Number 14 cm Red 2 14 cm 14 cm Pink White 11.5 cm Red 7 11.5 cm Pink 13 11.5 cm White 6. 9 cm Red 9 cm Pink 6.…In a variety of newly discovered rose plant, flowers are either white or red. Two genes were discovered to control flower color. Both genes, A and B, work in tandem in a biochemical pathway, and dominant forms of both genes are required for red flowers. A doubly-homozygous red-flowered plant is crossed with a doubly-homozygous white-flowered plant. The F1 offspring all have red flowers and are self-crossed to produce the F2. Determine the ratios of phenotypes in the F2 generation.
- The text outlines some of the problems Frederick William I encountered in his attempt to breed tall Potsdam Guards. a. Why were the results he obtained so different from those obtained by Mendel with short and tall pea plants? b. Why were most of the children shorter than their tall parents?Hemophilia and color blindness are both recessive conditions caused by genes on the X chromosome. To calculate the recombination frequency between the two genes, you draw a large number of pedigrees that include grandfathers with both hemophilia and color blindness, their daughters (who presumably have one chromosome with two normal alleles and one chromosome with two mutant alleles), and the daughters sons. Analyzing all the pedigrees together shows that 25 grandsons have both color blindness and hemophilia, 24 have neither of the traits, 1 has color blindness only, and 1 has hemophilia only. How many centimorgans (map units) separate the hemophilia locus from the locus for color blindness?Perform two consecutive crosses similar to those of Mendel for the following individual plants. Plants with round seeds (RR) are crossing with plants with wrinkled seeds (rr). After the first cross, cross the offspring together to generate F2 offspring. What are the genotypic and phenotypic ration of F2?