Mendel crossed peas having round seeds and yellow cotyledons with peas having wrinkled seeds and green cotyledons. All the F1 plants had round seeds with yellow cotyledons. a. What are the genotypes of the parent plants? b. What gametes could be produced by the parent with round seeds and yellow cotyledons? C. What gametes could be produced by the parent with wrinkled seeds and green cotyledons? d. What is the genotype of the F1 plants? e. What gametes could be produced by the F1 plants?

A type of tomato (Solanum lycopersicum) produces fruit in three possible colors: red, green, and orange. You cross a true-breeding orange-fruited plant with a true-breeding green-fruited plant, and all the F1 offspring are red. You intercross the red F1s, and the resulting F2 generation consists of 108 red-, 40 orange-, and 44 green-fruited plants.   1) What type of epistasis is acting (dominant, recessive, duplicate dominant, or duplicate recessive)?    2) Assign the phenotypes to a modified 9:3:3:1 ratio. (Do not just calculate the actual ratio of the phenotypes.)  Red : _____Orange : _____Green: _____

An individual pea plant is heterozygous for two loci: height and seed shape, with the genotype TtRr. These two loci are on different chromosomes and assort independently. What gametes are produced by this plant? Select all that apply. rr RR tr Tr tR tt TR TT TtRr

Outline the basic hybridization research done by Mendel when crossing a true breading violet flowered plant with a true breeding white flowered plant? In your answer you should indicate the parental generation, the F1, and the F2 results.

Mendel performed crosses in which he used pollen from a white-flowered plant to fertilize a purple-flowered plant and pollen from a purple-flowered plant to fertilize a white-flowered plant, showing the same results with both. What did these reciprocal crosses demonstrate?     A.  That the plants were not sterile.  B.  That there was no epistasis.  C.  That the trait could be passed from either parent.  D.  B and C.

Without SRY expression, an embryo will develop ________.a. male reproductive structuresb. female reproductive structuresc. no reproductive structuresd. male reproductive structures 50 percent of thetime and female reproductive structures 50percent of the time

Mendel obtained his initial pea plant varieties from local breeders who were developing new varieties that might be useful or interesting. To generate these new varieties, breeders formed hybrids between existing varieties of different phenotypic characteristics by cross pollination, using techniques they doubtless taught to Mendel.  After producing a hybrid, they allowed several generations of self-pollination, as happens naturally if the flowers are not disturbed. a. What if a breeder were working with 7 different, independently segregating genes, as Mendel did? How many generations would it take him to have pure-breeding varieties, starting from an F1 hybrid that is heterozygous for all 7 genes?    i. What is the probability that an individual in the F2 generation would be pure-breeding (i.e. is homozygous at all 7 loci)? [Hint: this is an “and” calculation since it must be homozygous at each of the 7 loci.    ii. What is the probability that an individual in the F3 generation would…

a. 1 dominant allele will contribute 120/10 = 12 cm to the base height of the plant.b. The height of the parent plant 1 Genotype of the parent plant 1 – D1D1D2D2D3D3d4d4d5d5 The height of the parent plant 2 Genotype of the parent plant 2 – d1d1d2d2d3d3D4D4D5D5Contributing alleles – D4D4D5D5. The height of the plant without any contributing alleles would be 80 cm. The plant with genotype d1d1d2d2d3d3D4D4D5D5 has 4 contributing allele each of which contributes 12 cm to the base. Hence, the height of the plant with genotype d1d1d2d2d3d3D4D4D5D5 would be 80 + 12 + 12 + 12 + 12 = 128 cm. c. Parents –         D1D1D2D2D3D3d4d4d5d5           ×            d1d1d2d2d3d3D4D4D5D5 Gametes –               D1D­2D3d4d5                                    ×                          d1d2d3D4D5 F1 generation –                                   D1d1D2d2D3d3D4d4D5d5 The height of the plants of F1 generation = 80 + 12 + 12 + 12 + 12 + 12 = 140 cm Hence, Genotype of the F1 = D1d1D2d2D3d3D4d4D5d5 Phenotype of…