Determine the total change in the length of a copper bar having a uniform cross sectional diameter of 5 cm is subjected to axial forces shown in fig. Also, determine the value of force, P2. Take L1 = 1 m, L2 = 0.5 m, L3 = 0.75 mm and E = 120 GPa. 10 kN P2 25 kN 65 kN LI L2 L3
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- A wine of length L = 4 ft and diameter d = 0.125 in. is stretched by tensile forces P = 600 lb. The wire is made of a copper alloy having a stress-strain relationship that may be described mathematically by =18,0001+30000.03(=ksi) in which is nondimensional and has units of kips per square inch (ksi). (a) Construct a stress-strain diagram for the material. (bj Determine the elongation, of the wire due to the Forces P. (c) IF the forces are removed, what is the permanent set of the bar? (d) If the forces are applied again, what is the proportional limit?A slightly tapered bar AB of solid circular crass section and length L is supported at end B and subjected to a tensile load P at the free end A. The diameters of the bar at ends A and B are dAand dB. respectively. Determine the length of the bar if the elongation of the bar due to the load P = 45 kips is 0.02 in. Assume that E = 10,400 ksi.A spherical balloon with an outer diameter of 500 mm and thickness 0.3 mm is filled with a gas. Calculate maximum permissible pressure in the balloon if the allowable normal strain at the outer surface of the balloon is O.h Assume E = 4 MPa and v = 0,45.
- Compound axial member ABC has a uniform diameter of d-2.4 in. Segment (1) is an aluminum [E₁ - 10,000 ksi] alloy and segment (2) is a copper [E₂ - 17,000 ksi] alloy. The lengths of segments (1) and (2) are L₁ - 78 in. and L₂ - 150 in., respectively. Determine the force P required to stretch compound member ABC by a total of 0.35 in. L₁ A Part 1 Aluminum Answer: A- B Save for Later Calculate the cross-sectional area of the compound member. L2 (2) Copper in.² C P Attempts: 0 of 1 used Submit Answer Part 2 The parts of this question must be completed in order. This part will be available when you complete the part above. Part 3 The parts of this question must be completed in order. This part will be available when you complete the part above.Let's consider a rod having a solid circular cross- section with diameter of 4 mm and it is made of a material having a Young's modulus E = 120 Gpa and a Poisson's ratio of 0.33. If a tensile force F is subjected to that rod cross-section, the diameter becomes 3.995 mm. determine the applied force F. Select one: F = 3427 N F = 2856 N F = 5712 N F = 8568 N F = 7140 N F = 2285 N20 KN . 38 mm Ø 1.0 m 40 KN 40 KN B 64 mm Ø1 1.5 m C Fig.pl-01 P2. Solve Problem P1-01 if rod BC is a hollow rod whose inner diameter is 38 mm. All' other data remain the same. 4 m
- Calculate the combined stress (MPa) on the rod shown below using the principle stress method. Here, F1 = 0.35 kN, F2 = 0.12 kN, T = 428000 N-mm. Length and diameter of the rod are 75 cm and 75 mm, respectively. F2 F1 dLet's consider a rod having a solid circular cross-section with diameter of 6 mm and it is made of a material having a Young's modulus E = 200 Gpa and a Poisson's ratio of 0.3. If a tensile force F is subjected to that rod cross- section, the diameter becomes 5.995 mm. determine the applied force F. Select one: F = 6283 N F = 4189 N F = 5236 N F = 10472 N F = 15708 N O F = 13090 NLet's consider a rod having a solid circular cross-section with diameter of 4 mm and it is made of a material having a Young's modulus E = 200 Gpa and a Poisson's ratio of 0.3. If a tensile force F is subjected to that rod cross-section, the diameter becomes 3.995 mm. determine the applied force F. Select one: F = 10472 N O F = 6283N O F= 15708 N O F = 4189N O F = 5236 N O F = 13090 N Clear my choice
- Let's consider a rod having a solid circular cross-section with diameter of 5 mm and it is made of a material having a Young's modulus E = 200 Gpa and a Poisson's ratio of 0.3. If a tensile force F is subjected to that rod cross-section, the diameter becomes 4.995 mm. determine the applied force F. Select one: O F = 5236 N O F = 6283 N %3D O F= 13090N O F = 10472 N O F= 15708N OF=4189 N 9:22 PM EN ? 4/15/2021Let's consider a rod having a solid circular cross-section with diameter of 6 mm and it is made of a material having a Young's modulus E = 200 Gpa and a Poisson's ratio of 0.3. If a tensile force F is subjected to that rod cross-section, the diameter becomes 5.995 mm. determine the applied force F. Select one: O F=15708N O F= 10472 N O F=5236 N O F= 13090 N O F=6283 N O F=4189 NLet's consider a rod having a solid circular cross-section with diameter of 6 mm and it is made of a material having a Young's modulus E = 200 Gpa and a Poisson's ratio of 0.3. If a tensile force Fis subjected to that rod cross-section, the diameter becomes 5.998 mm. determine the applied force F. Select one: O F=15708 N O F= 5236 N O F= 6283 N O F=4189 N O F= 10472 N O F= 13090N Clear my choice Finish attempt. IOUS ACTIVITY 360 Test - Spring 2020-2021 Jump to. 11:21 PM 4) G ENG 4/15/2021 LEGO ort sc delete end home backspace num lock 7V home enter 4E K pause M