Let's consider a rod having a solid circular cross-section with diameter of 4 mm and it is made of a material having a Young's modulus E = 200 Gpa and a Poisson's ratio of 0.3. If a tensile force F is subjected to that rod cross-section, the diameter becomes 3.995 mm. determine the applied force F. Select one:

Let's consider a rod having a solid circular cross-section with diameter of 4 mm and it is made of a material having a Young's modulus E = 200 Gpa and a Poisson's ratio of 0.3. If a tensile force F is subjected to that rod cross-section, the diameter becomes 3.995 mm. determine the applied force F. Select one:

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

Q2/B Acolumn of rainforced concrete has steel reinforcing rods running through its entire length and parallel to the column axis. If concrete has (E) of 15GPa and tensile strength of 2.8 MPa and the steel rods has (E) of (210) GPa and tensile strength of(400) GPa Determine the modulus of elasticity and tensile strength of composite if the steel rods occupy 10% of cross-sectional area of the column 021 21
SHOW ILLUSTRATION AND SOLUTION Problem 1: A steel rod with a cross - sectional area of 150 mm2 is stretched between 2 fixed supports. The tensile load at 20 oC is 5 kN. Use E = 200 GPa and  = 11.7 x 10- 6 /oC 1. At what temperature will the stress be zero?2. What will be the stress at - 20
A solid circular rod 200 mm long and 20 mm in diameter has an axial force of P. are exposed. P force and elongation of the rod when this force is applied is below the elasticity of the material, taking as the values given opposite your names in the table presented Calculate the modulus E and the shear modulus G. Take the Poisson's ratio () 0.3. P (N) δ(mm) :500 1,6
A member is formed by connecting two steel bars shown below. Assuming that the bars are prevented from buckling sideways, calculate the magnitude force "P" that will cause the total length of the member to decrease 0.24 mm the values of elastic modulus for steel is 221 MPa. Take H1 = 4 cm, H2 is 2 x 2 cm and bottom bar (Q) is 6 x 6 cm. Also, determine the stress-induced in each section of the bar. = 9 cm, top bar (R) IP Solution: R cm x RCm Steel bar i) Magnitude Force, P = H1 cm ii) Stress-induced in the top bar = Q cm x Q cm Steel bar H2 cm iii) Stress-induced in the bottom bar =
A member is formed by connecting two steel bars shown below. Assuming that the bars are prevented from buckling sideways, calculate the magnitude force "P" that will cause the total length of the member to decrease 0.89 mm the values of elastic modulus for steel is 209 MPa. Take H1 = 7 cm, H2 = 11 cm, top bar (R) is 3 x 3 cm and bottom bar (Q) is 6 x 6 cm. Also, determine the stress-induced in each section of the bar. i) Magnitude Force, P in(N) = ii) Stress-induced in the top bar in(N/mm^2) = iii) Stress-induced in the bottom bar in(N/mm^2) =
Please show complete solution and box the final answer
A solid steel bar 250 mm long is 10 mm square over part of its length, the remainder being circular with a diameter of 25 mm. A gradually applied tensile load P kN induces maximum stress in the bar of 200 MPa. The total strain energy in the bar when this stress of 200 MPa is acting is 1,3 Joule. Take E = 200 GPa Calculate : The load The length of the square portion of the bar The load that falls from a height of 8 mm and induces 1,3 Joules in the bar
A given conical bar is tapering uniformly from 4 cm diameter to 15 cm and has a length of 40 cm. An axial force of 80 KN is applied at each end if the bar, Find the elongation of the bar. Note: Take E=200 GPa
The rigid bar of negligible weight is supported as shown in the figure. If W 80 kN, compute the 2 temperature change of the assembly that will cause a tensile stress of 50 MPa in the steel rod. Use the following data: A (in-) a PF) E (GPa) Steel Rod 300 11.7 x 10 200 Bronze Rod 1400 18 х 104 83 Bronze 3 m Steel 1.5 m →| 1.0 m- 2.5 m +1.5 m W
Please explain how this was solved. I'm confused as to how the equation has been transposed to get the answer.
Let's consider a rod having a solid circular cross-section with diameter of 4 mm and it is made of a material having a Young's modulus E = 120 Gpa and a Poisson's ratio of 0.33. When a tensile force F is subjected to that rod cross-section, the diameter becomes 3.995 mm. Determine the applied force F. Consider a linear elastic behavior.