please answer and explain well and i will thumbs up may be multiple answers QUESTION 2Consider a pulley system shown below. Assume there is no slip between the cord and the pulley.kkm2RmiXWhat is the potential energy of the system? Select all that applyV=m₁gy+m28x+1-kx22V=-m₁g (2x)—m2gx+ ·8V=m₁g(2x)+m2gx+V=m₁gy+m2gx+ky'V=-m₁gy-m2gx+-kx-kx2-kx2xV=-m2-m 28x+kx²

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Answered: Consider a pulley system shown below.…

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Mechanical Engineering

Consider a pulley system shown below. Assume there is no slip between the k

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

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Concept explainers

Axial Load

When a bar of the uniform cross-section is acted by a load, such that the load acts along the longitudinal axis of the bar, such kinds of loadings are known as axial loadings. In general terms, a load is an external force acting on a component. An axial load acts perpendicular to the geometric cross-section of the component. Based on the direction of the application of the load, an axial load can be tensile or compressive. The analysis of bodies under the action of axial loads is generally studied under the branch of mechanics, known as statics.

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please answer and explain well and i will thumbs up may be multiple answers

QUESTION 2
Consider a pulley system shown below. Assume there is no slip between the cord and the pulley.
k
k
m2
R
mi
X
What is the potential energy of the system? Select all that apply
V=m₁gy+m28x+
1
-kx2
2
V=-m₁g (2x)—m2gx+ ·
8
V=m₁g(2x)+m2gx+
V=m₁gy+m2gx+ky'
V=-m₁gy-m2gx+
-kx
-kx2
-kx2
x
V=-m
2
-m 28x+kx²

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