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Calculate the CFU present in 150 mL water sample and b) dilution factor up to 5. Consider the following dilution scheme.
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- What is the minimal concentration (MIC) for disinfectant number 1? Just write the corresponding number including the decimal as written. ug/mL. Disinfectant 1 2 3 4 concentration 0.1 ug/mL +++ ++++ ++ +++ 0.2 ug/mL ++ ++ + ++ 0.5 ug/mL + + 1.0 ug/mL 5.0 ug/mL subculture 1 2 3 4 0.1 ug/mL ++++ ++++ ++++ ++++ 0.2 ug/mL ++++ ++++ ++++ ++++ 0.5 ug/mL ++++ ++++ ++++ 1.0 ug/mL ++++ 5.0 ug/mL Submit response1mL Stock #1 1mL 2000060 9mL #2 9mL wwwww #3 4. 1mL 0000000 A 9mL wooooo #4 0.1m/L O 1mL 5000000 B 9mL #5 1mL 1mL 9mL wwwwww #6 0.1mL 1mk O. D Using the picture serial dilution scheme and the following information (plate A has 276 colonies, plate B has 298, plate C has 2, and plate D has 30), calculate the average number of colony forming units per mL in the stock tube. Make sure to only use countable plates. Round your answer to the nearest one. Write only the number with any needed commas or decimals. Do not include units.Serial dilution = previous dilution x dilution 11 mL [2] 3 mL Colony count: 100 0.1 mL sample [1] 9.9 mL 5 mL 0.1 ml. Cokony count Dilution: 10-1 10-3 [3] 150 Dilution factor (DF): [4] [5] [6] Compute for the CFU/mL of the sample. Show your solution and express your final answer to 2 significant figures.
- Which of the following is the a-anomer? H но H Но H2C H ОН H2C- нн ОН со 4 1 2 1 Submit 3 -OH Н ОН -OH ОН Н there is no a-anomer ОН ОН Н Request Answer H Но НО Н H2C нн ОН 2 H2C ОН -OH 4 Н ОН н н H OH -О. ОН ОН Н ОН Н1mL Stock #1 1mL 9mL #2 9mL #3 1mL A 9mL #4 0.1mL 1mL O O B 9mL #5 1mL 1mL 9mL #6 O Using the picture serial dilution scheme and the following information (plate A has 276 colonies, plate B has 298, plate C has 2, and plate D has 30), calculate the average number of colony forming units per mL in the stock tube. Make sure to only use countable plates. Round your answer to the nearest one. Write only the number with any needed commas or decimals. Do not include units. 0.1mL 1mk D OA laboratory technician performed a series of 10 fold serial dilutions shown below. he plated 0.1 mL from each dilution tube onto NA and got the follow numbers per plate dilution 1:10 1:10 1:100 1:1000 1:10000 1:100000 colony count >1000 >1000 808 303 38 3 calculate the concentration of bacteria in the undiluted stock (in CFU/mL)
- Time point (min) Absorbance of culture at 660nm Approximate cell concentration Approximate # cells in 1mL extract 0 0.298 1.49 x 108 cells/mL 1.49 x 108 cells 10 0.316 1.58 x 108 cells/mL 1.58 x 108 cells 20 0.374 1.87 x 108 cells/mL 1.87 x 108 cells 30 0.429 2.145 x 108 cells/mL 2.145 x 108 cells 40 0.512 2.56 x 108 cells/mL 2.56 x 108 cells 50 0.544 2.72 x 108 cells/mL 2.72 x 108 cells 60 0.607 3.035 x 108 cells/mL 3.035 x 108 cells a. Using these data, prepare a growth curve of this strain ofEscherichia coli (E. coli).b. Estimate the doubling time for this strain of E. Coli. Clearly showhow you estimated this value from the empirical data presented.5 1 2 6 Testing Anti-Microbial Agents: Disk-Diffusion. Lab Report Fill out the zones of inhibition table with your data: Agent Tested Cleansing Spray 3 4 Foaming Handwash Hand Sanitizer Lysol spray Detergent Desinfecting zone of inhibition: (mm) E. coli 10mm 15 mm 20mm 0mm 9mm P. aeruginosa 8 mm 35mm 17mm 15mm 0 mm 1mm Hydrogen Peroxide Here, write a few observations about your experimental results. 25mm S. aureus 25mm 20mm 25mm 12mm 8mm 42mm What factors (at least 2) other than the identity of the agent being tested can influence the size of the zone of inhibition? NOT Were any colonies observed within the zone of inhibition? Even if you didn't have any, explain why you might see colonies in the zone of inhibition. Be specific about how that might happen? What follow up questions or conclusions do you have related to your data? (at least 2)I have another one, 1 ml of sewage water is added to 9 ml of water. 0.1 ml of this is added to 9.9 ml of water. 1 ml of this is then added to 9 ml of water. 1 ml is plated and 243 colonies form. What is the CFU/ml of the sewage water? Thanks again.
- Below is a diagram of the serial dilution of a culture with 1 x 10º cells. Fill out the missing information. 250 Culture Diluent 1 x 10° cells/mL 9 mL 9 mL 9.9 mL 9.9 mL 99.9 mL Volume to add to diluent Final Dilution level Theoretical count after plating 100 uLObservations and Results ml of Dilution Plated Final Dilution on Plate Number of Colonies Bacterial Count per ml of Sample (CFU/ml) Average Count per ml of Sample (CFU/ml) Dilution Factor Plate 1A H| 1:10 Iml 18 :100 Iml Iml 28 H41:10000Iml 3A H5:100.000iml 10 10 100 1000 103 10000104 100000 105 2A H31:1000 3B table helpbfor the missing boxesDetermine what percentage of the culture was living (viable) and what percentage was dead (mortality). Plates Plate Dilution Volume plated No.of colonies Avg No Concentration of diluted sample Cd(cells/mL) Concentration of original sample Cu(cells/mL) 1 10^-3 10ul R1=130,R2= 110,R3=210 150 150mL 1.50*10^6 Volume of cells(mL) Volume of diluent(mL) Total dilution(D) Hemocytometer count Avg cells in 1 mm^2 area Concentration of diluted sample Cd(cells/mL) Concentration of original sample Cu(cells/mL) 4.3 0.5 0.1 grid 1= 171 , grid2 = 185 178 1.78*10^5 1.78*10^6