Al body temperature (37 "C), what is the actual free energy change for the reaction in kimol ?
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- Acetyl CoA + 2H* + 2e = pyruvate + COASH E = -0.48 V Ubiquinone + 2H* + 2e = Ubiquinol E" = +0.04 V Consider the redox rxn wherein a pair of e passes from pyruvate to ubiquinone. Calculate the change in standard Gibbs free energy (kJ/mol). Report answer to two decimal places.The enzyme aldolase catalyzes the reaction shown in the glycolytic pathway: Fructose 1,6-bisphosphate dihydroxyacetone phosphate + glyceraldehyde 3-phosphate The AG" for the reaction is +23.8 kJ mol¯¹ (+5.7 kcal mol−¹), whereas the AG in the cell is −1.3 kJ mol¯¹ (−0.3 kcal mol¯¹). Calculate the ratio of products to reactants under standard (equilibrium) conditions at 37°C. [products] [reactants] 7 x10-5 [products] [reactants] Incorrect Aldolase ===== Calculate the ratio of products to reactants under intracellular conditions at 37°C. 4 ×10-5 Incorrect Complete the statement using your results. under standard conditions under intracellular conditions A reaction that is endergonic under standard conditions can be converted into an exergonic reaction by maintaining the ratio of products to reactants below the equilibrium value.The glucose/glucose-6-phosphate substrate cycle involves distinct reactions of glycolysis and gluconeogenesis that interconvert these two metabolites. Assume that under physiological conditions, [ATP] = [ADP]; [P;] = 1 mM. Consider the glycolytic reaction catalyzed by hexokinase: ATP + glucose ADP + glucose-6-phosphate AG = - 16.7 kJ/mol (a) Calculate the equilibrium constant (K) for this reaction at 298°K, and from that, calculate the maximum [glucose-6-phosphate]/ Iglucose] ratio that would exist under conditions where the reaction is still thermodynamically favorable. (b) Reversal of this interconversion in gluconeogenesis is catalyzed by glucose-6-phosphatase: glucose-6-phosphate + H20 = glucose + P AG" = -13.8 kJ/mol
- The inilial reactions in the biosynthesis of the amino acid aspartate at 298 K are: Carbamoyphoephate Cartamoyi + phosphate ADP + phoaphate - ATP AO=-12,300 calmol AG-T800 calimol Which of the following statements is gorrect? A) The energy which is released fron the conversion of 1 mole of carbamoyphosphate to carbamoyl+ phosphate (P) in reaction I is sufficient to drive the synthesis of 1 mole of ATP in reaction II. B) AG for the reaction Carbamoyphosphate + Carbamoyl + phosphate is +123 kcalimol. c) AHP for reaction I cannot be detemined trom the information given. D) Al of the above. E) None of the above.When grown anaerobically on glucose, yeast (S. cerevisiae) converts pyruvate to acetaldehyde, then reduces acetaldehyde to Pethanol using electrons from NADH. Write the chemical equation for the reaction that reduces acetaldehyde (CH3CHO) to ethanol (CH3CH2OH). The table provides the standard reduction potential, E', of the relevant half-reactions. Half-reaction Acetaldehyde + 2 H+ + 2e¯ → ethanol NAD+ + 2H+ + 2e¯ → NADH + H+ E'° (V) -.197 -.320 Calculate the equilibrium constant, K'eq, at 25.0 °C for the reaction that reduces acetaldehyde to ethanol. K'e ×10 = eqAcetyl-CoA is formed from acetate by coupling two reactions: ATP + H20 = ADP + P; AG" = -36.03 kJ/mol %3D acetate + CoA acetyl CoA + H20 AG" = +33.21 kJ/mol %3D 1. Calculate the overall AG' (reported up to two decimal places) for the net reaction. kJ/mol 2. Calculate the Keg (reported up to two decimal places and do not use scientific notation) for the net reaction at 298.15K. NOTE: R= 8.314 x 103 kJ/mol-K
- The degradation of glycogen is catalyzed by the enzyme phosphorylase and has AGO" equal to +3.1 kJ · mol1. The equation for this reaction is shown below. glycogen (n residues) + P;→ glycogen (n-1 residues) + G1P What is the ratio of [P;]/[G1P] under standard conditions? Use 2 significant figures. [P;] : [G1P] = i :1 What is the value of AG under cellular conditions when the [P;/[G1P] ratio is 50/1? Use 2 significant figures. AG = i kJ. mol-1A sample of glycogen from a patient with liver disease is incubated with Pi, normal glycogen phosphorylase, and normal debranching enzyme. The ratio of G1P to glucose formed in the reaction mixture is 100. What is the patient’s most probable enzymatic defi ciency?In a major metabolic pathway involving the monosaccharide glucose, one of the reactions involve the conversion of glucose to glucose-6-phosphate summarized below together with accompanying free energy change: glucose + phosphate = glucose-6-phosphate + H,0 AG = 13.8 kJ · mol-1 (Reaction 1) In cells, the production of G6P (Reaction 1 above) is coupled to a reaction that involves the hydrolysis of ATP to ADP (shown below, Reaction 2) which makes the overall reaction much more favorable to the production of glucose-6-phosphate. ATP + H,O = ADP + phosphate (Reaction 2) Why do you think coupling the production of glucose-6-phosphate to the hydrolysis of ATP makes the overall reaction spontaneous? What can you say about the free energy change accompanying the hydrolysis of ATP (Reaction 2)?
- The ΔG°’ for the aldolase reaction of glycolysis in muscle is +22.8 kJ/mol. Why does the aldolase reaction proceed in the direction of glyceraldehyde-3-phosphate and dihydroxyacetone phosphate during glycolysis?The glutamate dehydrogenase (GDH) catalyses the following reaction: *H₂N- H CH₂ CH₂ COO™ acide glutamique COO™ Time (min) A340 + NAD+ + H₂O The answer: GDH 2 1 1.760 1.718 [ammonium sulphate] = 0.33 M [NADH] = 0.205 mg.mL-¹ = 2.9.10-4 M [a-ketoglutarate] = 0.07 M [Protein] = 0.05 mg.mL-¹ COO™ CH₂ The activity of GDH is monitored in the sense of the formation of glutamate using the following conditions: 0.2 mL of 5 M ammonium sulphate 2.4 mL of buffer at pH 8 0.1 mL of NADH at 6.15 mg.mL-¹ (M = 709 g.mol-¹) 0.2 mL of 1 M a-ketoglutarate solution Warm mixture at 25 °C for 5 min Add 0.1 mL of GDH solution containing 1.6 mg.mL-¹protein to start the reaction. 5 3 4 1.675 1.635 1.595 !- Calculate ammonium sulphate, NADH, concentrations in the reaction medium at t = 0. CH₂ The change in absorbance at 340 nm is monitored, in a 1-cm cuvette, every minute for 10 min. Results are given in the table below: Data ENADH at 340 nm = 6220 M-¹.cm-¹ COO acide x-cétoglutarique O + NH4+ + NADH + H* 6 1.550…G6P(ag) F6P(aq) AG°=+1.7kJ/mol at 25 °C Consider the reaction: Estimate the fraction of F6P (Fructose 6 Phosphate) in equilibrium with G6P (Glucose 6 Phosphate) at 25 °C, where the fraction is defined as [F6P]/([F6P]+[G6P]). Show ALL your work.