According to Jean Buridan’s equation, the momentum or “impetus” of an 88 kilogram mass moving at 5 meters per second would be: 110 kilogram-meters per second 220 kilogram-meters per second 440 kilogram-meters per second 660 kilogram-meters per second 880 kilogram-meters per second
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According to Jean Buridan’s equation, the momentum or “impetus” of an 88 kilogram mass moving at 5 meters per second would be:
- 110 kilogram-meters per second
- 220 kilogram-meters per second
- 440 kilogram-meters per second
- 660 kilogram-meters per second
- 880 kilogram-meters per second
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- In terms of mass and acceleration, what is the equation for force?An airplane flying directly eastward at a constant speed travels 293 km in 2.0 h. (a) what is the average velocity of the plane? (b) what is the instantaneous velocity?Use the following information to answer questions 20 and 21. Assignment Booklet 4B Two cars, each with a mass of 1000 kg, are travelling in opposíte directionsn is car travelling to the right is travelling 30 m/s, and the car travelling to the lert is travelling 20 m/s. 1000 kg 30 m/s 1000 kg 20 m/s 20. What is the total momentum of the vehicles after they collicde? A. -50 000 kg-m/s B. 50 000 kg.m/s C. -10 000 kg.m/s D. 10 000 kg.m/s al ne 21. If the two vehicles collide and lock together, what is their velocity after the collision? A. -5 m/s Aon s quAua B. 5 m/s elg C. -10 m/s D. 10 m/s Return to page 70 of the Student Module Booklet and begin the Section 3 Review. os elomun ef et birov ort to solnied
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- The “mean-speed theorem” for calculating average velocity under constant acceleration, developed by Thomas Bradwardine and the Mertonian Calculators at Oxford University, is expressed algebraically as: density = weight/volume (m1)(v1) = (m2)(v2) C. (vm) = 1/2 (v0 + vf) s = (v0)(t) + 1/2 (a)(t2) velocity = distance/timeUsing the above “mean-speed theorem”, calculate the average velocity of a car with constant acceleration from 0 km/hour (initial speed) to 80 km/hour (final speed) over a 5-minute period of time. average velocity over 5 minutes = 16 kilometers/hour average velocity over 5 minutes = 20 kilometers/hour average velocity over 5 minutes = 24 kilometers/hour average velocity over 5 minutes = 32 kilometers/hour average velocity over 5 minutes = 40 kilometers/hourFrom the equation of a lineweaver-burke plot, calculate Km and Vmax. Show your work and include units. The equation is y=393.4x +8.4337
- You have measured the following data for enzyme X. Substrate Vo concentration (micromolar (mM) Isec) 0.05 10 0.1 60 0.5 175 1 250 350 490 10 492 20 494 50 499 100 498 200 498a toy car rolls 10 meters (m) across the floor. it takes 5 seconds (s) to cross this distance. what is the speed of this car?The “mean-speed theorem” for finding average velocity under constant acceleration, proposed by the Oxford Calculators, and demonstrated geometrically by Nicole Oresme, is expressed algebraically as: density = weight/volume (m1)(v1) = (m2)(v2) (vm) = 1/2 (v0 + vf) s = (v0)(t) + 1/2 (a)(t2) velocity = distance/time