A helical compression spring is wound using 4 mm-diameter Chrome-vanadium wire. The spring has an outside diameter of 28 mm with squared and ground ends, and 14 total coils: (a) What should the free length be to ensure that when the spring is compressed solid the torsional stress does not exceed the yield strength, that is, that it is solid-safe? (b) What force is needed to compress this spring to closure? (c) Estimate the spring rate.
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- A helical spring with a load range of from 450 N to 800 N from valve-closed to valve-open conditions is used to close the valve of a spring-set relief valve having a lift of 10 mm. Assuming the spring wire to be of chrome vanadium steel, the spring is rendering average service, determine the diameter of the wire if the spring index is 7 and Sg - 420 MPa. Use G=83GPA. Select one: O a. 2.4-mm wire O b. 5-mm wire O c. 6-mm wire O d. 7-mm wireA Helical Compression Spring is made of A232 Chrome-vanadium with squared and ground ends has wire diameter 5 mm, outer diameter 81.5 mm, free length 246.3 mm and total 10 turns. Do the analysis if the spring is safe and if not, what is the largest free length to which it can be wound using ns=1.2? Attach File Browse My ComputerA helical compression spring is used to absorb heavy vibrations. Apply mechanical engineering design theory and by using the values given in the table below, (i) Calculate the force applied on the spring. (ii) Determine the number of turns. (iii) Determine the spring stiffness. (iv) Calculate the free length. 5 maiks (v) Would you recommend to increase the number of turns and free length of the spring for this application ? Why? (answer in one/two sentences only). Spring data Туре Helical squared and ground ends Initial Compression of spring 30 mm 80 mm Further Compression of spring after applying heavy load Shear Stress Modulus of rigidity 750 N/mm2 82000 MPa Wire diameter 8 mm Spring Index
- A helical compression spring is to be used for a maximum load of 1.5 kN using the spring index of 8. The maximum permissible shear stress for the spring wire is 400 MPa. Which of the following is the wire diameter of the spring to be used?A typical compound helical spring consists of two coaxial closed coil spring having the following particulars: Outer spring 1: mean coil diameter = 100 mm Wire diameter = 12.5 mm No. of turns = 15 Inner spring 2: mean coil diameter = 75 mm No. of turns = 20Both the springs are of equal initial length when unloaded. Ifthe working stress for each spring is to be same. The modulus of rigidity for the wire material is 80 GPa. Calculate the following:a. Diameter of steel wire for inner spring. b. Stiffness of inner springc. Stiffness of the compound spring. I need answer ASAP. Thank you!An automobile engine has a valve spring is to be made of Fe, C, & Mn, to be oil-tempered, & to be designed that should not exceed to a cylindrical space of 134-in in diameter. The spring index should be 6.0, the coil-to-coil distance of 0.33in, & the maximum load it will sustain is 100lb with the corresponding compression of ½/2-in. The spring is subjected to repeated loading & fatigue must be considered by a factor of safety of 2.25. Determine: (a) the diameter of wire based on commercial sizes; (b) the total number of coils; (c) the free length of the spring. Sample image of valve spring in an assembly.
- The load on a helical spring is 1282 lb and the corresponding deflection is to be 3.4 inches. Rigidity modulus is 11 x 106 psi and the maximum intensity of safe torsional stress is 60,000 psi. If the wire diameter and the mean diameter are 0.5 in. and 3 in., respectively. Determine the number of active coils. Don't round your answer to preferred size. Round your answer to 4 significant figuresA typical compound helical spring consists of two coaxial closed coil spring having the following particulars: Outer spring 1: Mean coil diameter = 100mm Wire diameter = 12.5 mm No. of turns = 15 Inner spring 2: Mean coil diameter = 75 mm No. of turns = 20 Both the springs are of equal initial length when unloaded. If the working stress for each spring is to be the same. The modulus of rigidity for the wire material is 80 GPa. Calculate the following: a. Diameter of steel wire for inner spring b. Stiffness of inner spring c. Stiffness of the compound springA helical compression spring having 14 active coils is close coiled. It has a spring stiffness of 400lb/in. It is cut into two springs having 6 and 8 turns. Determine the spring stiffnesses of resulting springs.