A culture is incubated for 10 hours.1 hours after inoculation it reachedthe exponential growth phase. Atthis time point the cell density was1x10^4 cells/ml. 5 hours afterinoculation (still during theexponential growth phase) the celldensity was 1x10^7 cells. CalculateK and g(t).The growth constant (k) isminute. (round to 3 decimal points)The generation time (gt) isminutes. (round to whole number) I have diluted my culture 9x10^(-5)times. What was the volume of thestock and the volume of the mediafor dilution 3 if the total volume ofeach sub-dilution was 10 ml? Roundto 2 decimal places; do not write inscientific notation.PS: I may not have followed thelaboratorial principle of using atleast 100μl of stock for eachdilution (In truth: the numbers areproduced by a random numbergenerator).Dilution 1: v(stock) = 0.2 ml,v(media) = 9.8 mlDilution 2: v(d1) = 0.1 ml, v(media) =9.9 mlDilution 3: v(d2) =v(media) =ml,3

This question involves the calculation of the growth constant (k) and generation time (g(t)) for a…

A culture is incubated for 10 hours. 1 hours after inoculation it reached the exponential growth phase. At this time point the cell density was 1x10^4 cells/ml. 5 hours after inoculation (still during the exponential growth phase) the cell density was 1x10^7 cells. Calculate K and g(t). The growth constant (k) is 1 minute. (round to 3 decimal points) The generation time (gt) is minutes. (round to whole number)

A culture is incubated for 10 hours. 1 hours after inoculation it reached the exponential growth phase. At this time point the cell density was 1x10^4 cells/ml. 5 hours after inoculation (still during the exponential growth phase) the cell density was 1x10^7 cells. Calculate K and g(t). The growth constant (k) is 1 minute. (round to 3 decimal points) The generation time (gt) is minutes. (round to whole number)

Aquaculture Science

3rd Edition

ISBN:9781133558347

Author:Parker

Publisher:Parker

Chapter2: Aquatic Plants And Animals

Section: Chapter Questions

Problem 2KA

See similar textbooks

Similar questions

The culture you are working has a doubling time of 2 hours and a cell density of 3 x 106 cells per mL. For your experiment, you first dilute the culture 100 fold. Assuming that there is no lab phase and that the cells remain in exponential growth the entire time, what is the cell density (cells/mL) after 10 hours?
If you have a 15 mg/100 ml stock solution of GA3 and you need a 1 mg GA3 in 25 ml, how much stock solution would you add to 125 ml of medium? how to calculate these kind of question in tissue culture media preperation
As shown in this diagram, you perform a ten-fold serial dilution of a culture to determine the number of colony forming units (CFU) per mL it contains. You do a plate count with these growth results (no. of colonies for each dilution): 1:10 too many to count; 1:100 too many to count; 1:1,000 174; 1:10,000 23; 1:100,000 no growth. The number of CFU per mL in the original culture was: 1 ml 1 ml Original inoculum Dilutions 9 ml broth in each tube 1:10 1 ml 174,000 1:100 1 ml 1 ml 1 ml 1:1000 1 ml 1:10,000 1 ml None of the other four answers (Correct answer not given) 1,000 230,000 174 1 ml 1:100,000 1 ml
wwwwww The total number of cells in a culture is counted using dye trypan blue and is found to be 3.8 x 106 cells/mL. The culture is diluted 1:22 and then 200μl seeded per well into a 96 well plate. What is the final cell density per well? ssibility: Good to go MacBook Air
Assume an inoculum with a cell density of 108 cells per mL. The entire generation time takes 30 minutes. How many hours would it take to grow a culture to 108/mL if you started with a 10–2 dilution? helpful formula: g (generation time) = 0.301 (time)/ log x – log xo
As shown in this diagram, you perform a ten-fold serial dilution of a culture to determine the number of colony forming units (CFU) per mL it contains. You do a plate count with these growth results (no. of colonies for each dilution): 1:10 too many to count; 1:100 too many to count; 1:1,000 312; 1:10,000 38; 1:100,000 no growth. The number of CFU per mL in the original culture was: A. 38 B. 380,000 C. 38,000 D. None of the other four answers (Correct answer not given) E. 10,000
Explain the expressions of primary culture, cell haH, and continuous cell haH. Explain the reason why some cells grow in suspension in culture and some grow by adhering. Give examples of these two cell types.
Imagine you have been given a liquid culture of yeast with a starting concentration of 3.67 x 10' cells/ml and are asked to carry out the sample dilution process shown in the figure below. 100μl 100μl 100μl 100μl 100μl 0.9ml 0.9ml 0.9ml H2O H₂O 6.9ml 0.9ml H₂O H₂O H₂O Original 10-1 102 10-3 104 Culture 105 100μl 100μl 100μl Plate A Plate B Plate C a. How many colonies should have been present on Plate A in this example? - Answers must be whole numbers as partial colonies are not expected. b. Imagine you carried out the same dilution scheme shown in the figure above, but now, you do not know the concentration of the original culture. If you counted 163 colonies on Plate B, what is the concentration of cells/ml in the original culture?
Describe how you would prepare a dilution series of a 1 x 107 CFU/mL culture to the 10-8 dilution using only 4.5 mL diluents in tubes. What would be the theoretical cell count if 0.1 mL of the 2nd and 4th dilutions were each plated?
Plateau Phase Death Lag Phase Exponential Growth Phase Phase Fen ve cels Many ive cets Dead cells 10 15 20 25 30 35 40 45 Hours Consider the above figure which depicts the growth curve of microorganisms such as Saccharomyces cerevisiae. Now, reflect upon the components which make up the growth medium used to cultivate yeast. Whilst the growth medium was being made, the component which provides a source of energy for yeast was omitted. VWhat component was left out? What effect will this have on the growth curve phases and the rate at which they occur, especially in regard to the 'Exponential Growth' phase of the yeast? Loganmm/10of Vahie Cels
Calculate the growth rate and generation time of a culture that increases in the exponential phase from 5x102 to1x108 cells in 12 hours
Beginning with 10 grams of plant tissue, order the following procedures (as steps 1-4) that you will use to obtain a cell fraction that consists of mostly large cell organelles: collect pellet, collect supernatant, high-speed centrifugation for 10 min., low-speed centrifugation for 5 min, filter homogenate, grind plant tissue Step 1 grind plant tissue | Choose collect supernatant low-spccd centrifugation for 5 min high-speed centrifugation for 10-min collect pellet grind plant tissue filter homogenate Step Step 3 Step 4 high-speed contrifugation fo v