Assume an inoculum with a cell density of 108 cells per mL. The entire generation time takes 30 minutes. How many hours would it take to grow a culture to 108/mL if you started with a 10–2 dilution?

As shown in this diagram, you perform a ten-fold serial dilution of a culture to determine the number of colony forming units (CFU) per mL it contains.  You do a plate count with these growth results (no. of colonies for each dilution): 1:10 too many to count; 1:100 too many to count; 1:1,000 312; 1:10,000 38; 1:100,000 no growth.   The number of CFU per mL in the original culture was:   A. 38 B. 380,000  C. 38,000 D. None of the other four answers (Correct answer not given) E. 10,000

As shown in this diagram, you perform a ten-fold serial dilution of a culture to determine the number of colony forming units (CFU) per mL it contains. You do a plate count with these growth results (no. of colonies for each dilution): 1:10 too many to count; 1:100 too many to count; 1:1,000 174; 1:10,000 23; 1:100,000 no growth. The number of CFU per mL in the original culture was: 1 ml 1 ml Original inoculum Dilutions 9 ml broth in each tube 1:10 1 ml 174,000 1:100 1 ml 1 ml 1 ml 1:1000 1 ml 1:10,000 1 ml None of the other four answers (Correct answer not given) 1,000 230,000 174 1 ml 1:100,000 1 ml

Given a log phase bacterial culture with 1 x 10^6  cells per ml and a generation time of 30 minutes how long does it take the culture to reach a density of 6.4 x 10^7 cells per ml?

The culture you are working has a doubling time of 2 hours and a cell density of 3 x 106 cells per mL. For your experiment, you first dilute the culture 100 fold. Assuming that there is no lab phase and that the cells remain in exponential growth the entire time, what is the cell density (cells/mL) after 10 hours?

Solve the following problem: 34,000 bacteria/l have been measured 4 hours after inoculating a medium. After 24 hours, the number of bacteria increased to 5.2x10^6/l. Assuming that the lag phase is negligible, calculate: The specific speed of growth. The number of bacteria that were inoculated.

The number of bacterial cells in a culture broth is to be determined by a culture technique. Serial dilutions were performed and a 1 mL aliquot from each dilution was mixed with warm molten agar and poured into a Petri dish. The numbers of bacterial colony forming units (CFU) after overnight incubation are shown in the table below. What is the number of colony forming units per mL of the culture broth? Choose only the most appropriate plate for your calculation. Give your answer as the number only (do not add text for the units). You may use scientific notation with the format 1.12e+6 (that is, 1.12 x 106 cfu/mL). (Note: Canvas will then display your answer a whole number.) Plate Dilution -3 Plate 1 10 dilution Plate 2 10-4 dilution Plate 3 10-5 dilution Plate 4 10 dilution Plate 5 10 dilution -8 Plate 6 100 dilution *Too many to count Number of colony forming units (CFU) TMTC* 1,957 65 21 1 0 m

The number of bacterial cells in a culture broth is to be determined by a culture technique. Serial dilutions were performed and a 1 mL aliquot from each dilution was mixed with warm molten agar and poured into a Petri dish. The numbers of bacterial colony forming units (CFU) after overnight incubation are shown in the table below. What is the number of colony forming units per mL of the culture broth? Choose only the most appropriate plate for your calculation. Give your answer as the number only (do not add text for the units). You may use scientific notation with the format 1.12e+6 (that is, 1.12 x 106 cfu/mL). (Note: Canvas will then display your answer a whole number.) Plate Dilution Plate 1 10 dilution Plate 2 10 dilution -5 Plate 3 10 dilution Plate 4 10 dilution Plate 5 107 dilution -8 Plate 6 100 dilution *Too many to count Number of colony forming units (CFU) TMTC* TMTC* TMTC* 867 154 18

With a plate count average of 297 and a final dilution on the plate of 1:1,000 ; what is the viable number of cells in original culture (CFU/ml)?

A culture is incubated for 10 hours. 1 hours after inoculation it reached the exponential growth phase. At this time point the cell density was 1x10^4 cells/ml. 5 hours after inoculation (still during the exponential growth phase) the cell density was 1x10^7 cells. Calculate K and g(t). The growth constant (k) is minute. (round to 3 decimal points) The generation time (gt) is minutes. (round to whole number)