A 1.5% grade passing at station 46+20.00 at an elevation of 369.93 ft meets a -2.5% grade passing at station 46+30.00 at an elevation of 369.88 ft. Determine the station and elevation of the point of intersection of the two grades as well as the length of the curve, L, if the highest point on the curve must lie at station 45+25.00

Q: An incoming grade of +1.800% meets an exiting grade of -2.500% at a PVI having station = 27+32.20…

A: Incoming grade = +1.800% Exiting grade = -2.500% PVI station = 27+32.20 PVI elevation = 231.87…

Q: An old equal-tangent crest vertical curve was designed with a PVI at station 117+45 and elevation of…

A: An equal tangent crest vertical curve is as below The point PVC is called as the initial tangent…

Q: 1.    Consider a vertical curve with a +3/2% initial grade and -1.1% final grade. The point of…

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Q: the AASHTO method (“K” factors) (1/8 pts.) The station of the PVC/BVC (1/8 pts.) The station of the…

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Q: An equal tangent vertical curve is to be constructed between grades of -2.0% (initial) and 1.0%…

A: Solution:GradeG1=-2.0%Grade G2=1.0%Point of vertical intraction elevation=420 mPoint of vertical…

Q: A parabolic vertical curve with a grade in of 2.1%, a grade out of - 3.2%, a curve length of…

A: (Note: Since part C is asked to solve, the solution for the c part is given below.) Given: Grade in,…

Q: Q3/ A vertical curve below has a lower point (A) which exists at station (53+50) with elevation…

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Q: A sag curve is being built under an existing overpass. The point of vertical intersection (PVI) of…

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Q: A −2.50% grade meets a +1.75% grade at station 44+25 and elevation 3388.42 ft, 400-ft curve,…

A: The elevations and grades at the beginning and end of the curve need to be determined.  g1= -2.5%…

Q: PROBLEM 7 A +2 percent grade on an arterial highway intersects with a -1 percent grade at station…

A: Given- +2% grade-1% gradestationing 535+24.25elevation=300 ftdesgin speed=65 mi/hrelevation of each…

Q: A vertical curve connected +5 % grade to a +2 % grade. The elevation of the V.P.C. is 5,150 ft. Find…

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Q: Q3/ A vertical curve below has a lower point (A) which exists at station (53+50) with elevation…

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Q: Problem 2.  This is a four-part problem. A +2.5% grade intersects with a –1.5% grade at station (735…

A: Note:- Hi! Thank you for the question, As per the honor code, we are allowed to answer three…

Q: Q3/ A vertical curve below has a lower point (A) which exists at station (53+50) with elevation…

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Q: Question 3 An equal-tangent vertical curve is to be constructed between grades of -2 percent and +1…

A: Given :

Q: Q3/ A vertical curve below has a lower point (A) which exists at station (53+50) with elevation…

A: given- R.L of A= (1271.2 m) at station (53+50)back grade g1= (-4%) forward grade g2= (+3.8%)(PVI)…

Q: A vertical curve is located along the north sound bound direction at an intersection as shown below…

A: In order to check for safety of the curve in terms of stopping sight distance we need to calculate…

Q: 11. Two vertical parabolic curves have been connected to form a roadway by three gradients: -5.30 %,…

A: Given - Three Gradient  g1 = -5.30% , g2 = 4.10% , g3 = -3.70% Design speed = 70kph. Object height =…

Q: The steepest gradient on a 3º curve on a Narrow Gauge line with a stipulated ruling gradient of 1 in…

A: Given, Gradient = 1/200 Degree of curve = 3o Grande compensation = -0.02 % per degree of curve

Q: 2. A vertical parbolic curve was design in order to have a clear sight distance of 120 m. The grade…

A: Given: Sight Distance= 120 m  Grade lines intersection   Station = 9+000 Elevation = 160.50 m…

Q: 7. From the Crest Vertical Curve Chart (attached) determine the Length of the Vertic Curve for a…

A: FOR V=60mph S=475fr So USing graph

Q: Given an equal tangent vertical curve, in feet, with the following known information: STA A…

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Q: 500-m long equal tangent vertical curve has a point of vertical curvature at station 2 + 600 and…

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Q: A vertical parbolic curve was design in order to have a clear sight distance of 120 m . The grade…

A: sing relation for SSDSSD=vt+v22gf±Gf=0.35G=0.05t=2.5sec

Q: A sag curve is being built under an existing overpass. The point of vertical intersection (PVI) of…

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Q: What is the length in stations for a symmetrical vertical curve with an entering grade of +5% which…

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Q: 5. A vertical sag curve consists of an initial grade of -3.5% with a final grade of +0.5%. The…

A: Given:- An initial grade of the sag curve = -3.5% A final grade of the sag curve = +0.5% The…

Q: Determine the elevation of the middle point of the curve.

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Q: 1. A crest vertical curve connects a +1.5 % grade with a -2.5 % grade on a two-lane highway. The…

A: Data given Grades = +1.5% and -2.5 % Design speed = 90 km/hr PI  Station = 14+465 PI  Elevation =…

Q: An equal-tangent vertical curve connects a +1.5% initial grade and a -3% final grade. The PVT is at…

A: Following are the given information.Initial grade, Final grade, Station of PVT Elevation of PVT…

Q: A 600 ft equal tangent vertical The initial grade is -3.5% and the final grade is +0.5%. Determine…

A: L=600ft

Q: A crest vertical curve (equal tangent) has PVI at station 210+00 and elevation 420.75 ft. The…

A: SPVI = Stationing of PVI = 210+00EPVI = Elevation of PVI = 420.75 ftg1 = Initial grade = 2.5% =…

Q: A symmetrical parabolic commit curve connects two grades of +6% and -4%. It is to pass a point "A"…

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Q: An equal-tangent vertical curve connects an initial grade of -4% and a final grade of +1% and is…

A: The objective of the problem is to determine the station and elevation of the lowest point on an…

Q: A highway engineer must stake a symmetrical vertical curve where an entering grade of +0.80% meets…

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Q: A horizontal curve is being designed for a new four-lane roadway with 11-ft lanes. The PT is located…

A: Given;Road has four lane of 11 ft.PT is located at station 105+20Design speed = 45 mph =66…

Q: If PVI at sta 5+650 has an elevation of 122.45 m what is the elevation of the grade tangent at…

A: "Since you have asked multiple question, only first question will be solved for you. If you want any…

Q: Step by step solutionProblem 1. An existing equal-tangent sag vertical curve is designed for 60 mph.…

A: Step 1:Step 2: Step 3: Step 4:

Q: A VERTICAL PARBOLIC CURVE WAS DESIGN IN ORDER TO HAVE A CLEAR SIGHT DISTANCE OF 120 M. THE GRADE…

A: