75 mL of 0.2 M NaOH were added to 100 mL of 0.1M aspartate solution, pH=pl. What is the new pH? pKa values for aspartate are 1.88, 3.65 (R-group) and 9.60. 8. A) 1.40 B) 4.13 C) 6.62 D) 2.76 E) 9.60 If we are not given the starting pH, how do we do this question?

A purified protein fraction has a total sample volume of 360 µL.  The sample has a corrected A280 of 0.484, and the blank corrected A280 was 0.052.  (Both values were measured with a path length of 1.00 cm.)  If 5.00 µL of the sample was used in a reaction, calculate the mass of protein in the reaction (in µg).

Example   The reference range for blood pH is 7.35 – 7.42.  What is this range expressed as [H+] in nmol l-1?   Calculation:     pH   =  - log [H+]       7.35  =  - log [H+]       [H+]  =  antilog  -7.35      =  4.47 x 10-8 mol.l-1  =  44.7nmol.l-1            similarly:     pH 7.42 = 38.0 nmol.l-1       Range [H+] = 38 – 44.7 nmol.l-1   If the blood pH decreases in an acidosis from 7.42 to 7.15, what is the change in [H+] in nmol.l-1?       so this is example on the worksheet, but i still understand how to answer the question.