1- Identify the addressing mode for: MOV CX, [1234] 2-The instruction that subtracts 1 from the contents of th specified register/memory location is a. INC b. SUBB c. SUB d. DEC
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![1- Identify the addressing mode for: MOV CX, [1234]
2-The instruction that subtracts 1 from the contents of the
specified register/memory location is
a.
INC
b.
SUBB
C.
SUB
d. DEC](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff3e023a8-d0b2-413e-bfbe-88ea050fa9de%2Ff2d76720-28a8-4473-94bf-b060965c5fa4%2Fewmxm1i_processed.jpeg&w=3840&q=75)
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- Q4(a) Adder is divided into three types which are half adder, full adder, and parallel adder. Illustrate the implementation of full adder using half adder with necessary logic gates. (i) (ii) Figure Q4(a)(ii) shows the input timing diagram for a full adder. Illustrate the timing diagrams for output S and Cout- Cin Cout Figure Q4(a)(ii)1. Write the contents of all registers and the conditions codes registers after each execution instructions in Table Q1(a). Instructions SUBS r0, rl, 12 MOV 12,13, ASR #3 ro 11223344 Table Q1 (a) rl F7770025 12 r3 CF119856 CF119856 NZ V C 010 1Q4(a) Adder is divided into three types which are half adder, full adder, and parallel adder. Illustrate the implementation of full adder using half adder with necessary logic gates. (i) (ii) Figure Q4(a)(ii) shows the input timing diagram for a full adder. Illustrate the timing diagrams for output S and Cout- B Cin Cout Figure Q4(a)(ii) (iii) Given A = 111001 and B = 100010. Construct a 6-bit parallel adder to solve for A + B.
- 1- Identify the addressing mode for: MOV Cx, [SI] 2- The instruction that adds immediate datalcontents of memory location specified in an instruction/register to the contents of another register/memory location is a. SUB b. ADD c. MUL Share Content ParticipantsFigure 4 shows the decimal to BCD encoder logic. Assume that the 9 input and 3 inputare both HIGH.i) Determine the output code.ii) Is the value valid for BCD (8421) code?The microprocessor unit that responsible for instruction queuing is .. O EU O ALU BIU O Segment registers O None of the above
- - The stack memory is addressed by a combination of the plus offset. The PUSH and POP instructions always transfer between segment -bit number the stack and a register or memory location in the 8086 microprocessors. For string instructions, DI always addresses data in the segment. The 8086 LOOP instruction decrements register for a 0 to decide if a jump occurs and tests it8085 microprocessor went through its manipulation operation in the ALU, the results was transferred on the data bus and status of the results was stored in the flag register for indications . With your knowledge and understanding illustrate a complete bit configuration of 8085 flag register and show the functions of the represented bits in the register.3- what is the advantages of memory segment. 4- state the purposes of segment registér. 5- what is the different between general purpose register and segment register and flag register.
- Suppose we have two registers, Rl and R2, and between them we have a combinational logic circuit. The tpcg = 0.5 ns, tccq = 0.25 ns, tpd = 4 ns, tcd = 2.5 ns, tsetup = 0.5 ns and thold = 0.2 ns. What is the maximum value of fc? Select one: a. 0.2 ps O b. 200 MHz O c. 2 GHz O d. 200 KHz6. i) For the circuit shown in Figure Q16, Find the logic functions of X and Y Figure Q1 ii) Simplify X and Y using Boolean algebra. hp ort deleteQ2. Write assembly language program to substrate two 8-bit numbers and store the result on memory location 3500H. Also show data considered and result of program.