d) This addressing mode is always used to access memory, shown here as the source operand of this instruction: LDR R1,[R0]?
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- An 8051 subroutine is shown below: SUB: RO, #20H @RO , #0 MOV LOOP: MOV INC RO CJNE RO, #80H, LOOP RET a. What does this subroutine do? b. In how many machine cycles does each instruction execute? How many bytes long is each instruction? C. d. Convert the subroutine to machine language. e. How long does this' subroutine take to execute? (Assume 12 MConsider the following assembly program MOV CX, 1100H DLY: SUBS CX, CX, #1 NOP BNE DLY NXT: --- (a) How many times does the BNE DLY instruction get executed? (b) Change the first line of the program so that BNE DLY is executed 34 times (c) Change the second line of the program so that BNE DLY is executed 34 times, while the fist line stays unchanged (MOV CX, 1100H)- The stack memory is addressed by a combination of the plus offset. The PUSH and POP instructions always transfer between segment -bit number the stack and a register or memory location in the 8086 microprocessors. For string instructions, DI always addresses data in the segment. The 8086 LOOP instruction decrements register for a 0 to decide if a jump occurs and tests it
- LDS DX, [BX] – this instruction copies - successive words from memory pointed by BX register. a. Two O b. One O c. Three O d. Four(B)- Answer the following questions: 1. After the PUSH and POP instructions, where does the stack pointer go? 2. Explain the opcode and operand in XCHG [BX||SI]+1234H, AX instruction. 3. If DX contains 81FEH and CX contains 1986H, explain the effect of the following instructions on the flag registers. Suppose that the flags are initially 0 in each statement of this question. i.SUB DX, CX ii.ХСHG DX, CхSolve the following question. You must show your work. a) What does 962F000016 represent in an IEEE single-precision floating-point number? b) Convert -151o to a 16-bit sign-magnitude representation. c) Convert-151o to a 16-bit two's complement representation. d) Define the system status register value after an instruction execution resulted the following: a. Result was a non-zero value, a negative value, had a carry and extended bits. b. Trace mode was not on and was executed in supervisor mode. C. Any higher interrupt priorities higher than level 3 will be recognized.
- 3. Suppose r0=0x20000000 and r1=0x12345678. All bytes in memory are initialized to 0x00. Suppose the following assembly program has run successfully (the three instructions will be executed in the given order). Draw a table to show the memory value if the processor uses little endian. STR r1, [r0], #4 STR r1, [r0,#4]! STR r1, [r0, # 4] Address 0x20000010 0x2000000f 0x2000000e 0x2000000d 0x2000000c 0x2000000b 0x2000000a 0x20000009 0x20000008 0x20000007 0x20000006 0x20000005 0x20000004 0x20000003 0x20000002 0x20000001 0x20000000 Data1. Write down 2- differences between Von-Neumann and Harvard architecture. 2. you are executing an instruction, SUB $s0, $s1, $s2 (address 0x20). Draw the datapath of this instruction when $s1=10, $s2=5. When are the stages in this datapath? Mark the components which are active in corresponding stages. 3. How to store(1050000)10 in register $s0? Write down the instructions that stores the data in $s0 register.Given the memory content below, fill in the table below with the register values after the execution of 3 instructions starting at instruction at address 589. Consider the initial values PC=589 and AC=0006. (all values are in Hexadecimal). address Content 13C 025A 25A 0231 589 113C 58A 7200 58B 7020 Note that you need to fill 4 digits for AC, 3 for PC, and 1 for E. AC (in Hex)= EEBE PC (in Hex)= 58C E=
- The numbers from 0-9 and a no characters is the Basic 1 digit seven segment display * .can show False True In a (CA) method of 7 segments, the anodes of all the LED segments are * "connected to the logic "O False True Some times may run out of pins on your Arduino board and need to not extend it * .with shift registers True FalseQ1. Design a circuit of General register organization in which 4 registers are there from R0 to R3. (a) Explain the control word as per the register configuration given above.You are given the following assembly language statements: MOV AX, 15225 MOV BL, 126 DIV BL SUB BL, AL Just after the CPU finishes executing the SUB instruction, calculate the following: i)The decimal values in AL, AH, and AX registers ii)The decimal value of BL iii)The values of flag bits: Sign, Carry, Auxiliary, Zero, Parity, and Overflow.