Elements Of Electromagnetics
7th Edition
ISBN: 9780190698614
Author: Sadiku, Matthew N. O.
Publisher: Oxford University Press
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- 6) The y phase in steel can transform into Pearlite and through diffusional processes.arrow_forwardQuenching is a process used to preserve at room temperature a phase which exists in equilibrium at high temperature but which would decompose during equilibrium cooling. Explain the basis of this process in the precipitation process and martensitic transformation. Use phase diagrams when necessary.arrow_forward(a) Figure 5 shows a phase diagram for the Nb-80 wt% W alloy which is solidified under under the nonequilibrium condition. Evaluate (i) the liquidus temperature (ii) the non-equilibrium solidus temperature (iii) the freezing range (iv) the composition of the first solid form during solidification (v) the composition of the last liquid to solidify (vi) the phase(s) present, the composition of the phase(s) and the amount of the phase(s) at 3000 °C (vii) the phase(s) present, the composition of the phase(s) and the amount of the phase(s) at 2800 °C.arrow_forward
- Construct the hy pothetical phase diagram for metal A and B between temperature of 600 C° and 1000 C° given the following information: The melting point of A is 940 Cº. The solubility of B in A is negligible at all temperatures The melting point of metal B is 830 Cº. The maximum solubility of A in B is 12%A, which occurs at 700 Co. At 600 C°, the solubility of A in B is 8%A. One eutectic occurs at 700 C° and 75%B. A second eutectic occurs at 730 C° and 60%B. A third eutectic occurs at 755 C° and 40%B. One congruent melting point occurs at 780 C° and 51%B. A second congruent melting point occurs at 755 C° and 67%B. There exist two intermetallic compounds: AB at 51%B and AB2 at 67%B. Note all composition are in weight percent.arrow_forwardPlease explain carefullyarrow_forward3. The figure below shows the phase diagram for a hypoeutectoid plain carbon steel. Assume that point c is slightly above 723 °C and point d is slightly below 723 °C. i. ii. iii. Explain the structure at points a, b, c, and d on the diagram. Determine the wt% of proeutectoid ferrite at point c. Determine the wt% of eutectoid ferrite at point d. Temperature (°C) 1000 900 800 700 600 500 400 0 100% Fe y+ a 0.02 a + Fe, C b 0.4 723°C y + Fe, C Pearlite 0.8 Weight percent carbon Fe₂C 6.67arrow_forward
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