Whether in the model of 1,2-dimethylcyclopentane, the molecule in the left box is same as the molecule in the right box or not needs to be determined. Concept Introduction : The cis and trans isomerism concept will be applied here. Any molecule will be called cis if it follows the conditions for itthat is the same groups attached either above the plane or below the plane.For trans isomer,same groups are attached where one is above the plane and other group is below the plane or vice versa.

Question

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Answer 1

Question

Chapter 7, Problem 1CTQ

Interpretation Introduction

Interpretation:Whether in the model of 1,2-dimethylcyclopentane, the molecule in the left box is same as the molecule in the right box or not needs to be determined.

Concept Introduction:

The cis and trans isomerism concept will be applied here. Any molecule will be called cis if it follows the conditions for itthat is the same groups attached either above the plane or below the plane.For trans isomer,same groups are attached where one is above the plane and other group is below the plane or vice versa.

Expert Solution & Answer

Answer to Problem 1CTQ

The given both structures of isomers of 1,2 dimethylcyclopentane are similar to each other. This is because when the bonds of the groups interchanges with each other, the bond’s spatial character changes. As a result of which these structures can be converted to each other without breaking of bonds.

Explanation of Solution

It is given that the left box and right box contain two molecules of 1,2-dimethylcyclopentane.Thus, it is very easy to conclude that the 2 different molecules are isomers of 1,2-dimethylcyclopentane. This is because both the molecules have same number of atoms in it.

Both the molecules are similar toeach other. Thiscan be explained as, if the interchanging of bonds takes place, similar structure can be obtained. In the interchanging of structure in left box and right box, there is no breaking of bonds takes place. For example, if the methyl group attached to the bond below the planeis interchanged with other group attached to the same atom, then the position of methyl group will be converted to above the plane from below the plane. In this process, no breaking of bond takes place then similar structure will be obtained.

Conclusion

Thus, the structure on the left box is similar to that on the right box.

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Consider 3,3-dimethylpentane. Using a Newman projection formula, draw the most stable conformation, sighting along the C2-C3 bond. Compute the total strain energy for this conformation. Refer to strain energy values given below .............................................................................. Strain energies with respect to atoms/groups bonded to C-C (one atom/group bonded to each C) H <---> H eclipsed : 4 kJ/mol CH3 <---> H eclipsed: 6 kJ/mol CH3 <----> CH3 eclipsed: 11 kJ/mol CH3 <----> CH3 gauche staggered: 3.8 kJ/mol

Answer 2

Question

Chapter 7, Problem 1CTQ

Interpretation Introduction

Interpretation:Whether in the model of 1,2-dimethylcyclopentane, the molecule in the left box is same as the molecule in the right box or not needs to be determined.

Concept Introduction:

The cis and trans isomerism concept will be applied here. Any molecule will be called cis if it follows the conditions for itthat is the same groups attached either above the plane or below the plane.For trans isomer,same groups are attached where one is above the plane and other group is below the plane or vice versa.

Expert Solution & Answer

Answer to Problem 1CTQ

The given both structures of isomers of 1,2 dimethylcyclopentane are similar to each other. This is because when the bonds of the groups interchanges with each other, the bond’s spatial character changes. As a result of which these structures can be converted to each other without breaking of bonds.

Explanation of Solution

It is given that the left box and right box contain two molecules of 1,2-dimethylcyclopentane.Thus, it is very easy to conclude that the 2 different molecules are isomers of 1,2-dimethylcyclopentane. This is because both the molecules have same number of atoms in it.

Both the molecules are similar toeach other. Thiscan be explained as, if the interchanging of bonds takes place, similar structure can be obtained. In the interchanging of structure in left box and right box, there is no breaking of bonds takes place. For example, if the methyl group attached to the bond below the planeis interchanged with other group attached to the same atom, then the position of methyl group will be converted to above the plane from below the plane. In this process, no breaking of bond takes place then similar structure will be obtained.

Conclusion

Thus, the structure on the left box is similar to that on the right box.

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Answer 3

Question

Chapter 7, Problem 1CTQ

Interpretation Introduction

Interpretation:Whether in the model of 1,2-dimethylcyclopentane, the molecule in the left box is same as the molecule in the right box or not needs to be determined.

Concept Introduction:

The cis and trans isomerism concept will be applied here. Any molecule will be called cis if it follows the conditions for itthat is the same groups attached either above the plane or below the plane.For trans isomer,same groups are attached where one is above the plane and other group is below the plane or vice versa.

Expert Solution & Answer

Answer to Problem 1CTQ

The given both structures of isomers of 1,2 dimethylcyclopentane are similar to each other. This is because when the bonds of the groups interchanges with each other, the bond’s spatial character changes. As a result of which these structures can be converted to each other without breaking of bonds.

Explanation of Solution

It is given that the left box and right box contain two molecules of 1,2-dimethylcyclopentane.Thus, it is very easy to conclude that the 2 different molecules are isomers of 1,2-dimethylcyclopentane. This is because both the molecules have same number of atoms in it.

Both the molecules are similar toeach other. Thiscan be explained as, if the interchanging of bonds takes place, similar structure can be obtained. In the interchanging of structure in left box and right box, there is no breaking of bonds takes place. For example, if the methyl group attached to the bond below the planeis interchanged with other group attached to the same atom, then the position of methyl group will be converted to above the plane from below the plane. In this process, no breaking of bond takes place then similar structure will be obtained.

Conclusion

Thus, the structure on the left box is similar to that on the right box.

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Answer 4

Question

Chapter 7, Problem 1CTQ

Interpretation Introduction

Interpretation:Whether in the model of 1,2-dimethylcyclopentane, the molecule in the left box is same as the molecule in the right box or not needs to be determined.

Concept Introduction:

The cis and trans isomerism concept will be applied here. Any molecule will be called cis if it follows the conditions for itthat is the same groups attached either above the plane or below the plane.For trans isomer,same groups are attached where one is above the plane and other group is below the plane or vice versa.

Expert Solution & Answer

Answer to Problem 1CTQ

The given both structures of isomers of 1,2 dimethylcyclopentane are similar to each other. This is because when the bonds of the groups interchanges with each other, the bond’s spatial character changes. As a result of which these structures can be converted to each other without breaking of bonds.

Explanation of Solution

It is given that the left box and right box contain two molecules of 1,2-dimethylcyclopentane.Thus, it is very easy to conclude that the 2 different molecules are isomers of 1,2-dimethylcyclopentane. This is because both the molecules have same number of atoms in it.

Both the molecules are similar toeach other. Thiscan be explained as, if the interchanging of bonds takes place, similar structure can be obtained. In the interchanging of structure in left box and right box, there is no breaking of bonds takes place. For example, if the methyl group attached to the bond below the planeis interchanged with other group attached to the same atom, then the position of methyl group will be converted to above the plane from below the plane. In this process, no breaking of bond takes place then similar structure will be obtained.

Conclusion

Thus, the structure on the left box is similar to that on the right box.

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Answer 5

Chapter 7, Problem 1CTQ

Interpretation Introduction

Interpretation:Whether in the model of 1,2-dimethylcyclopentane, the molecule in the left box is same as the molecule in the right box or not needs to be determined.

Concept Introduction:

The cis and trans isomerism concept will be applied here. Any molecule will be called cis if it follows the conditions for itthat is the same groups attached either above the plane or below the plane.For trans isomer,same groups are attached where one is above the plane and other group is below the plane or vice versa.

Expert Solution & Answer

Answer to Problem 1CTQ

The given both structures of isomers of 1,2 dimethylcyclopentane are similar to each other. This is because when the bonds of the groups interchanges with each other, the bond’s spatial character changes. As a result of which these structures can be converted to each other without breaking of bonds.

Explanation of Solution

It is given that the left box and right box contain two molecules of 1,2-dimethylcyclopentane.Thus, it is very easy to conclude that the 2 different molecules are isomers of 1,2-dimethylcyclopentane. This is because both the molecules have same number of atoms in it.

Both the molecules are similar toeach other. Thiscan be explained as, if the interchanging of bonds takes place, similar structure can be obtained. In the interchanging of structure in left box and right box, there is no breaking of bonds takes place. For example, if the methyl group attached to the bond below the planeis interchanged with other group attached to the same atom, then the position of methyl group will be converted to above the plane from below the plane. In this process, no breaking of bond takes place then similar structure will be obtained.

Conclusion

Thus, the structure on the left box is similar to that on the right box.

Answer 6

Chapter 7, Problem 1CTQ

Interpretation Introduction

Interpretation:Whether in the model of 1,2-dimethylcyclopentane, the molecule in the left box is same as the molecule in the right box or not needs to be determined.

Concept Introduction:

The cis and trans isomerism concept will be applied here. Any molecule will be called cis if it follows the conditions for itthat is the same groups attached either above the plane or below the plane.For trans isomer,same groups are attached where one is above the plane and other group is below the plane or vice versa.

Expert Solution & Answer

Answer to Problem 1CTQ

The given both structures of isomers of 1,2 dimethylcyclopentane are similar to each other. This is because when the bonds of the groups interchanges with each other, the bond’s spatial character changes. As a result of which these structures can be converted to each other without breaking of bonds.

Explanation of Solution

It is given that the left box and right box contain two molecules of 1,2-dimethylcyclopentane.Thus, it is very easy to conclude that the 2 different molecules are isomers of 1,2-dimethylcyclopentane. This is because both the molecules have same number of atoms in it.

Both the molecules are similar toeach other. Thiscan be explained as, if the interchanging of bonds takes place, similar structure can be obtained. In the interchanging of structure in left box and right box, there is no breaking of bonds takes place. For example, if the methyl group attached to the bond below the planeis interchanged with other group attached to the same atom, then the position of methyl group will be converted to above the plane from below the plane. In this process, no breaking of bond takes place then similar structure will be obtained.

Conclusion

Thus, the structure on the left box is similar to that on the right box.

Answer 7

Chapter 7, Problem 1CTQ

Interpretation Introduction

Interpretation:Whether in the model of 1,2-dimethylcyclopentane, the molecule in the left box is same as the molecule in the right box or not needs to be determined.

Concept Introduction:

The cis and trans isomerism concept will be applied here. Any molecule will be called cis if it follows the conditions for itthat is the same groups attached either above the plane or below the plane.For trans isomer,same groups are attached where one is above the plane and other group is below the plane or vice versa.

Answer 8

Expert Solution & Answer

Answer to Problem 1CTQ

The given both structures of isomers of 1,2 dimethylcyclopentane are similar to each other. This is because when the bonds of the groups interchanges with each other, the bond’s spatial character changes. As a result of which these structures can be converted to each other without breaking of bonds.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

It is given that the left box and right box contain two molecules of 1,2-dimethylcyclopentane.Thus, it is very easy to conclude that the 2 different molecules are isomers of 1,2-dimethylcyclopentane. This is because both the molecules have same number of atoms in it.

Both the molecules are similar toeach other. Thiscan be explained as, if the interchanging of bonds takes place, similar structure can be obtained. In the interchanging of structure in left box and right box, there is no breaking of bonds takes place. For example, if the methyl group attached to the bond below the planeis interchanged with other group attached to the same atom, then the position of methyl group will be converted to above the plane from below the plane. In this process, no breaking of bond takes place then similar structure will be obtained.

Answer 12

Conclusion

Thus, the structure on the left box is similar to that on the right box.

Answer 13

Ch. 7 - Prob. 1CTQ Ch. 7 - Prob. 2CTQ Ch. 7 - Prob. 3CTQ Ch. 7 - Draw wedge and dash skeletal representations of...Ch. 7 - Label each ring in Figure 7.2 cis or trans.Ch. 7 - Prob. 6CTQ Ch. 7 - Prob. 7CTQ Ch. 7 - Prob. 8CTQ Ch. 7 - a model of cyclohexane in a chair conformation,...Ch. 7 - Prob. 10CTQ

Concept explainers

Answer to Problem 1CTQ

Explanation of Solution

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Chapter 7 Solutions