Steel Design (Activate Learning with these NEW titles from Engineering!)
6th Edition
ISBN: 9781337094740
Author: Segui, William T.
Publisher: Cengage Learning
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Question
Chapter 5, Problem 5.15.7P
To determine
The W shape of A992 steel for the purlins by using LRFD.
Expert Solution & Answer
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Students have asked these similar questions
Select all zero-force members in the truss shown below. Check the box for zero-
force members
3 m
3 m
12 m, 8 @ 1.5 m
DE
O LK
ЕР
O HF
O BC
BM
EF
OM
CD
BN
LO
O DK
FI
O co
Which of the following best gives the purlin load wuy? See loaded purlin.
The figure shown has trusses 6m apart with midpoint
sag rods and Purlins C150x12.5 spaced 2.5m on center.
The roof truss is inclined 1 vertical to 2 horizontal. The
weight of roofing materials is 0.9 kPa (includes self
wt.), wind load is 0.8 kPa perpendicular to the roof
surface, minimum roof live load is 0.6 kPa. Consider the
roofing to provide full lateral support of the purlins.
Fy = 345 mPa. Use the NSCP 2015 specifications.
2. 5m
2.5m
2. 5m
roofing
TRUSS TOP CHORD
Wuy,
Truss Spacing = 6m
Wux
1
Purlins C150x12.5
Purlin Load
Wt
kN/m mm^2 mm
C150x12.5 0.12 11400 12.7 152 5.1
d tw by
SECTION
Ix Sx rx ly sy
Zy
ry Zx
mm mm mm^4 mm^3 mm mm^4 mm^3 mm mm^3 mm^3
mm
mm
48
8.7
143 1100 112 48.4 378 65.2 1230 574
O 4.35 kN/m
5.56 kN/m
O 25.02 kN.m
Select all zero-force members in the truss shown below. Check the box for zero-
force members
3m
12 m, 8 @ 1.5 m
O DE
LK
EP
OHF
O BC
O BM
O EF
O OM
O CD
O BN
LO
O DK
FI
O co
O O O O O O 0 0 O 0
Chapter 5 Solutions
Steel Design (Activate Learning with these NEW titles from Engineering!)
Ch. 5 - Prob. 5.2.1PCh. 5 - Prob. 5.2.2PCh. 5 - Verify the value of Zx for a W1850 that is...Ch. 5 - Prob. 5.2.4PCh. 5 - Prob. 5.4.1PCh. 5 - Prob. 5.4.2PCh. 5 - Determine the smallest value of yield stress Fy,...Ch. 5 - Prob. 5.5.1PCh. 5 - Prob. 5.5.2PCh. 5 - Prob. 5.5.3P
Ch. 5 - Prob. 5.5.4PCh. 5 - Prob. 5.5.5PCh. 5 - Prob. 5.5.6PCh. 5 - Prob. 5.5.7PCh. 5 - Prob. 5.5.8PCh. 5 - Prob. 5.5.9PCh. 5 - If the beam in Problem 5.5-9 i5 braced at A, B,...Ch. 5 - Prob. 5.5.11PCh. 5 - Prob. 5.5.12PCh. 5 - Prob. 5.5.13PCh. 5 - Prob. 5.5.14PCh. 5 - Prob. 5.5.15PCh. 5 - Prob. 5.5.16PCh. 5 - Prob. 5.6.1PCh. 5 - Prob. 5.6.2PCh. 5 - Prob. 5.6.3PCh. 5 - Prob. 5.6.4PCh. 5 - Compute the nominal shear strength of an M107.5 of...Ch. 5 - Compute the nominal shear strength of an M1211.8...Ch. 5 - Prob. 5.8.3PCh. 5 - Prob. 5.8.4PCh. 5 - Prob. 5.10.1PCh. 5 - Prob. 5.10.2PCh. 5 - Same as Problem 5.10-2, except that lateral...Ch. 5 - Prob. 5.10.4PCh. 5 - The given beam is laterally supported at the ends...Ch. 5 - Prob. 5.10.6PCh. 5 - Prob. 5.10.7PCh. 5 - Prob. 5.11.1PCh. 5 - Prob. 5.11.2PCh. 5 - Prob. 5.11.3PCh. 5 - Prob. 5.11.4PCh. 5 - Prob. 5.11.5PCh. 5 - Prob. 5.11.6PCh. 5 - Prob. 5.11.7PCh. 5 - Prob. 5.11.8PCh. 5 - Prob. 5.11.9PCh. 5 - Prob. 5.12.1PCh. 5 - Prob. 5.12.2PCh. 5 - Prob. 5.12.3PCh. 5 - Prob. 5.13.1PCh. 5 - Prob. 5.13.2PCh. 5 - Prob. 5.14.1PCh. 5 - Prob. 5.14.2PCh. 5 - Prob. 5.14.3PCh. 5 - Prob. 5.14.4PCh. 5 - Prob. 5.15.1PCh. 5 - Prob. 5.15.2PCh. 5 - Prob. 5.15.3PCh. 5 - Prob. 5.15.4PCh. 5 - Prob. 5.15.5PCh. 5 - Prob. 5.15.6PCh. 5 - Prob. 5.15.7PCh. 5 - Same as Problem 5.15-7, except that the sag rods...
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Similar questions
- A. A truss member is made with a pair of 4"x 3" x 3/8" angles with the long legs back to back. The angles are 36 ksi steel and are attached at the connection by a 3/8 in. plate running between the angles. The unbraced length is 12 feet and consider both ends fixed. What is the allowable axial load in compression? In tension? How does the compression capacity change if I connect them with a %" plate in between? Does it change tension capacity? (a) 12 C. A 28 foot column is braced top and bottom about the X-X axis and has K bracing as shown on the Y-Y axis only. It is built of A36 steel and is a W12 x 30 section. Can it support an axial load of 165 kips? State its actual capacity.arrow_forwardThe truss below is pin connected at A and E, and is acted on by the forces shown. E A D B Identify all of the ZERO-FORCE MEMBERS by checking the boxes below (if there are none, leave all boxes unchecked): BF AF BC BH CD EG -GH AB CH DG DH DE -FHarrow_forwardPart A - Identifying zero-force members Consider the truss shown below. Identify the zero-force members. A P_ E B D Check all that apply. • View Available Hint(s) ВС АВ ВЕ AE DE CD O CE Submitarrow_forward
- 3) Determine the Force in each member of the truss shown in the Figure. (Use the Method of Joints.) D B gl 12' H E 300lb 300lb goolb 9' 9'arrow_forwardExample 3.15 FIGURE 3.32 Fink trusses spaced at 20 feet on centers support W6 x 12 purlins, as shown in Figure 3.32a. The purlins are supported at their midpoints by sag rods. Use A36 steel and design the sag rods and the tie rod at the ridge for the following service loads. Metal deck: Built-up roof: Snow: Purlin weight: 46.6' 2 @ 12' = 24' 4.679 k 46.6 18.17k (b) 2 psf 5 psf 45 18 psf of horizontal projection of the roof surface 12 pounds per foot (lb/ft) of length 112 42' 90' (a) P P 2@ 12' = 24' F R R 12 (c) 45 3' 3' 3' 3' 12' 4.679 k 4.679karrow_forwardA tie member of a roof truss consists of 21SA 100 x 75 x 8 mm. The angles are connected by fillet weld as shown in figure on either side of a 10 mm gusset plate and the member is subjected to a factored pull of 450 kN. Take size of weld as 6 mm and connections are made in workshop. [Use Fe410 grade of steel] 75 m L. C. = 31mm 16A (100 x 75 x 8) mm Choose the nearest correct statements: L1 = 390.5 mm L1 = 195.25 mm Correct Option L2 = 87.75 mm Correct Option L2 = 175.5 mmarrow_forward
- Determine the forces in each member of the truss. State wether it is in tension or compression. Draw a diagram of internal forces and present a results summary list. T a 446 a a a 12/2 커arrow_forwardDetermine the force of the members for the space truss shown in the figure. Joints A and B are supported by ball-and-socket while Joint C is supported by short link along z-axis. Indicate whether member is tension (T) or compression (C). 2m y Sm Az By BX Bz PAR Ax CSXScanned with Ca canner a SISU KN 15m 1 2117arrow_forwardA plate girder must be designed for the conditions shown in Figure P10.7-4. The given loads are factored, and the uniformly distributed load includes a conservative estimate of the girder weight. Lateral support is provided at the ands and at the load points. Use LRFD for that following: a. Select the, flange and web dimensions so that intermediate stiffeners will he required. Use Fy=50 ksi and a total depth of 50 inches. Bearing stiffeners will be used at the ends and at the load points, but do not proportion them. b. Determine the locations of the intermediate stiffeners, but do not proportion them.arrow_forward
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