Steel Design (Activate Learning with these NEW titles from Engineering!)
6th Edition
ISBN: 9781337094740
Author: Segui, William T.
Publisher: Cengage Learning
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Chapter 5, Problem 5.14.2P
To determine
(a)
The design of bearing plate by LRFD.
To determine
(b)
The design of bearing plate by ASD.
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The rectangular doubly reinforcement stress concrete block with the arrangement of reinforcement of 2N28
bars on top and 3N28 bars on bottom. The modulus of elasticity are Ec =23,500MPa and Es = 200,000MPa.
Dead load is 18KN/m and live load is 12KN/m.
f' = 25MPa
800
IDE
730
N12 ligs (fsv.f-500MPa)
Ast = 3N28
350
Span = 10m
Figure 3
Calculate the combination load for the reinforcement concrete beam shown in Figure 3. Unit: KN/m
with two decimal. 1.2G+1.5Q=w
Question 8
1 p
The rectangular doubly reinforcement stress concrete block with the arrangement of reinforcement of 2N28 bars on
top and 3N28 bars on bottom. The modulus of elasticity are Ec=23,500MPa and Es = 200,000MPa. Dead load is
18KN/m and live load is 12KN/m.
f'c = 25MPa
800
TE
730
N12 ligs (fsv.t-500MPa)
Ast = 3N28
350
Span = 10m
Figure 3
Calculate the concrete stresses in tension and compression of the reinforcement concrete beam shown in
Figure 3.
Compression concrete stress
Choose ]
Tension Concrete stress
Choose]
The rectangular doubly reinforcement stress concrete block with the arrangement of reinforcement of 2N28 bars on top and 3N28 bars on bottom. The
modulus of elasticity are Ec =23,500MPa and Es = 200,000MPa. Dead load is 18KN/m and live load is 12KN/m.
f'c = 25MPa
800
730
N12 ligs (fx.t-500MPa)
Ast = 3N28
350
Span = 10m
Figure 3
Use the Transformed section approach considering the presence of steel. Calculate the concrete area and transformed steel area in both
tension and compression shown in Figure 3.
n=Es/Ec
Ast=1232mm^2
Use n-1 for the transformed area to do the calculate. Unit: mm^2 with two decimal
Chapter 5 Solutions
Steel Design (Activate Learning with these NEW titles from Engineering!)
Ch. 5 - Prob. 5.2.1PCh. 5 - Prob. 5.2.2PCh. 5 - Verify the value of Zx for a W1850 that is...Ch. 5 - Prob. 5.2.4PCh. 5 - Prob. 5.4.1PCh. 5 - Prob. 5.4.2PCh. 5 - Determine the smallest value of yield stress Fy,...Ch. 5 - Prob. 5.5.1PCh. 5 - Prob. 5.5.2PCh. 5 - Prob. 5.5.3P
Ch. 5 - Prob. 5.5.4PCh. 5 - Prob. 5.5.5PCh. 5 - Prob. 5.5.6PCh. 5 - Prob. 5.5.7PCh. 5 - Prob. 5.5.8PCh. 5 - Prob. 5.5.9PCh. 5 - If the beam in Problem 5.5-9 i5 braced at A, B,...Ch. 5 - Prob. 5.5.11PCh. 5 - Prob. 5.5.12PCh. 5 - Prob. 5.5.13PCh. 5 - Prob. 5.5.14PCh. 5 - Prob. 5.5.15PCh. 5 - Prob. 5.5.16PCh. 5 - Prob. 5.6.1PCh. 5 - Prob. 5.6.2PCh. 5 - Prob. 5.6.3PCh. 5 - Prob. 5.6.4PCh. 5 - Compute the nominal shear strength of an M107.5 of...Ch. 5 - Compute the nominal shear strength of an M1211.8...Ch. 5 - Prob. 5.8.3PCh. 5 - Prob. 5.8.4PCh. 5 - Prob. 5.10.1PCh. 5 - Prob. 5.10.2PCh. 5 - Same as Problem 5.10-2, except that lateral...Ch. 5 - Prob. 5.10.4PCh. 5 - The given beam is laterally supported at the ends...Ch. 5 - Prob. 5.10.6PCh. 5 - Prob. 5.10.7PCh. 5 - Prob. 5.11.1PCh. 5 - Prob. 5.11.2PCh. 5 - Prob. 5.11.3PCh. 5 - Prob. 5.11.4PCh. 5 - Prob. 5.11.5PCh. 5 - Prob. 5.11.6PCh. 5 - Prob. 5.11.7PCh. 5 - Prob. 5.11.8PCh. 5 - Prob. 5.11.9PCh. 5 - Prob. 5.12.1PCh. 5 - Prob. 5.12.2PCh. 5 - Prob. 5.12.3PCh. 5 - Prob. 5.13.1PCh. 5 - Prob. 5.13.2PCh. 5 - Prob. 5.14.1PCh. 5 - Prob. 5.14.2PCh. 5 - Prob. 5.14.3PCh. 5 - Prob. 5.14.4PCh. 5 - Prob. 5.15.1PCh. 5 - Prob. 5.15.2PCh. 5 - Prob. 5.15.3PCh. 5 - Prob. 5.15.4PCh. 5 - Prob. 5.15.5PCh. 5 - Prob. 5.15.6PCh. 5 - Prob. 5.15.7PCh. 5 - Same as Problem 5.15-7, except that the sag rods...
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