Steel Design (Activate Learning with these NEW titles from Engineering!)
6th Edition
ISBN: 9781337094740
Author: Segui, William T.
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Question
Chapter 5, Problem 5.10.2P
To determine
(a)
The most economical W-shape for the given beam by using LRFD.
To determine
(b)
The most economical W-shape for the given beam by using ASD
Expert Solution & Answer
Trending nowThis is a popular solution!
Students have asked these similar questions
The beam shown in Figure has lateral support only at the ends. The uniform load is a superimposed dead load, and the concentrated load is a live load. Use A992 steel and select a W shape. The live load deflection must not exceed L/360.
a. Use LRFD.b. Use ASD.
Use A 992 Steel and Select the most economical W shape for the beam shown
in the figure below. The beam weight is not included in the service
loads shown. Do not check deflection. Assume continuous Lateral support.
K
6
IPD = lok
PL=20k
*
161
1
WD= 3-33 K/F+
WL=6-67 k/Ft
-xhul
The beam shown is simply supported and has lateral support only at its ends. The only service
dead load is the weight of the beam. Determine whether it is satisfactory for the load shown.
A992 steel (E= 345 MPa and F= 450 MPa) is used, and the 30 KN/m is a service live load.
Use LRFD
30 KN/m
WiL = 30 KN/m
W16x 40
-Centroid
W16 x 40
3m
Chapter 5 Solutions
Steel Design (Activate Learning with these NEW titles from Engineering!)
Ch. 5 - Prob. 5.2.1PCh. 5 - Prob. 5.2.2PCh. 5 - Verify the value of Zx for a W1850 that is...Ch. 5 - Prob. 5.2.4PCh. 5 - Prob. 5.4.1PCh. 5 - Prob. 5.4.2PCh. 5 - Determine the smallest value of yield stress Fy,...Ch. 5 - Prob. 5.5.1PCh. 5 - Prob. 5.5.2PCh. 5 - Prob. 5.5.3P
Ch. 5 - Prob. 5.5.4PCh. 5 - Prob. 5.5.5PCh. 5 - Prob. 5.5.6PCh. 5 - Prob. 5.5.7PCh. 5 - Prob. 5.5.8PCh. 5 - Prob. 5.5.9PCh. 5 - If the beam in Problem 5.5-9 i5 braced at A, B,...Ch. 5 - Prob. 5.5.11PCh. 5 - Prob. 5.5.12PCh. 5 - Prob. 5.5.13PCh. 5 - Prob. 5.5.14PCh. 5 - Prob. 5.5.15PCh. 5 - Prob. 5.5.16PCh. 5 - Prob. 5.6.1PCh. 5 - Prob. 5.6.2PCh. 5 - Prob. 5.6.3PCh. 5 - Prob. 5.6.4PCh. 5 - Compute the nominal shear strength of an M107.5 of...Ch. 5 - Compute the nominal shear strength of an M1211.8...Ch. 5 - Prob. 5.8.3PCh. 5 - Prob. 5.8.4PCh. 5 - Prob. 5.10.1PCh. 5 - Prob. 5.10.2PCh. 5 - Same as Problem 5.10-2, except that lateral...Ch. 5 - Prob. 5.10.4PCh. 5 - The given beam is laterally supported at the ends...Ch. 5 - Prob. 5.10.6PCh. 5 - Prob. 5.10.7PCh. 5 - Prob. 5.11.1PCh. 5 - Prob. 5.11.2PCh. 5 - Prob. 5.11.3PCh. 5 - Prob. 5.11.4PCh. 5 - Prob. 5.11.5PCh. 5 - Prob. 5.11.6PCh. 5 - Prob. 5.11.7PCh. 5 - Prob. 5.11.8PCh. 5 - Prob. 5.11.9PCh. 5 - Prob. 5.12.1PCh. 5 - Prob. 5.12.2PCh. 5 - Prob. 5.12.3PCh. 5 - Prob. 5.13.1PCh. 5 - Prob. 5.13.2PCh. 5 - Prob. 5.14.1PCh. 5 - Prob. 5.14.2PCh. 5 - Prob. 5.14.3PCh. 5 - Prob. 5.14.4PCh. 5 - Prob. 5.15.1PCh. 5 - Prob. 5.15.2PCh. 5 - Prob. 5.15.3PCh. 5 - Prob. 5.15.4PCh. 5 - Prob. 5.15.5PCh. 5 - Prob. 5.15.6PCh. 5 - Prob. 5.15.7PCh. 5 - Same as Problem 5.15-7, except that the sag rods...
Knowledge Booster
Similar questions
- The beam shown in the figure has continuous lateral support of bothflanges. The uniform load is a service load consisting of 50% deadload and 50% live load. The dead load includes the weight of thebeam. If A992 steel is used, is a W16 × 31 adequate?a. Use LRFD.b. Use ASD.arrow_forwardThe member shown in Figure has lateral support at points A, B, and C. Bending is about the strong axis. The loads are service loads, and the uniform load includes the weight of the member. A992 steel is used. Is the member adequate? a. Use LRFD. b. Use ASD.arrow_forwardA simply supported beam is subjected to a uniform service dead load of 15kN/m(including the weight of the beam), a uniform service live load of 30kN/m. the beam is 12 meters long and is laterally supported at the midspan, and A572 Gr.50 steel is used. Is W30x108 adequate? Assume Cb=1 by 4 d fore k h h Z S Ly 267 TH mm 19.3 757 13.8 min m 35.8 685.4 54.6 737.7 5670 x10^3 4900 x103 mm 60.8 x10 6 mm 2080 x10 3 8300 x10^9 mm wwwarrow_forward
- Q3) The beam shown in Figure below has lateral support at the ends only. The concentrated loads are live loads. Use A992 steel and select a W shape. (Do not check deflections. Use C-1). 23 k 25 k ttstarrow_forwardA column is built up from four (4)- 125 x 125 x 18 angle shapes as shown. The plates are not continuous but are spaced at intervals along the column length and function to maintain the separation of the angles. They do not contribute to the cross-sectional properties. The effective length is 4 m. Compute the allowable design compressive strength based on flexural buckling. E= 250 MPa. Use ASD. k 375 mm 125mm, HPlate 125mm 4 - 4 125 × 125× l8 section 下好业arrow_forwardProblem 4: Use A992 steel and select a W shape. The service dead load is 142 kips, and the service live load is 356 kips. ↑ a 10' wwww Do wwwwww y-axis 16' x-axisarrow_forward
- 2. The beam shown in Figure P5.8-3 is a W16 × 31 of A992 steel and has continuous lateral support. The two concentrated loads are service live loads. Neglect the weight of the beam and determine whether the beam is adequate for flexure and shear. a. Use LRFD. b. Use ASD.arrow_forwardQ2) The members of the truss structure shown below is plain concrete. The compressive strength of the concrete is 25 MPa. Compute the maximum load P that can be carried by the structure. (Cross section of each member of the truss is 200 x 200 mm and don't use material factors and do not consider slenderness) Comment on your results briefly. P A& 2m SC 2 m 1380 2m Darrow_forward2. Determine whether the compression member shown in Figure P4.3-7 is adequate to support the given service loads. a. Use LRFD. b. Use ASD. D = 560 kips L = 68 kips W12 × 79 A992 steel 20'arrow_forward
- Assuming A36 steel, select the most economical W8 section. Check the shear stress, and determine the deflection at the free end.arrow_forwardA built-up section shown, 30 feet long, is fixed at both ends and braced in the weak direction at the midheight. A992 steel is used. Determine the following: 11. Ix 12. Ky 13. effective slenderness ratio 14. Fe 15. LRFD design strength 16. ASD allowable strength 18 4 W10 × 49 A 14.4 in² bf 10 in d. 10 in tw 0.340 in tf 0.560 in Ix= 272 in¹ Iy=93 4in¹ W10×54 A 15-3 in² bf 10 in d = 10 lin tw0-370 in tf 0.615 in Ix= 303 in 4 Ty = 103 in 1arrow_forwardSelect an A992 W shape for beam AB of the floor system shown in Figure. In addition to the weight of the beam, the dead load consists of a 41⁄2-inch-thick reinforced concrete slab (normal-weight concrete). The live load is 95 psf. The total deflection must not exceed L/240. a. Use LRFD.b. Use ASD..arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Steel Design (Activate Learning with these NEW ti...Civil EngineeringISBN:9781337094740Author:Segui, William T.Publisher:Cengage Learning
Steel Design (Activate Learning with these NEW ti...
Civil Engineering
ISBN:9781337094740
Author:Segui, William T.
Publisher:Cengage Learning