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Organic Chemistry
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- The acid-base reaction between 2-methyl-2-butene and HI can, in principle, form two carbocations. Write chemical equations for the formation of each carbocation and use curved arrows to show the proton transfer in each reaction. CH, CH3-C=CH-CH3 2-Methyl-2-butenearrow_forwardBriefly, but clearly, explain why the –OH hydrogen in acetic acid (CH3CO2H) is more acidic than in ethanol (C2H5OH).arrow_forwardDraw HOCH2C(CH3)3arrow_forward
- Reaction of (CH3)3CH with Cl2 forms two products: (CH3)2CHCH2Cl (63%) and (CH3)3CCl (37%). Why is the major product formed by cleavage of the stronger 1° C–H bond?arrow_forwardAl+Hg(CH3COO)2arrow_forwardThe chemical reaction of 2-butene and HCl yields what product? O CH3CH₂CH₂CH3 O CI CH 3 CH 2 C HCH 3 CI CI I 1 CH3-CH-CH-CH3 CH3 I CH3 CHCH3 Cl I CH 3 C CH 2 CH 3 CH3 O Oarrow_forward
- Ethanol, C2H5OH, and propane, C3H8, have approximately the same molar mass, yet ethanol has a much higher boiling point. Briefly explain why. Ethanol, C2H5OH, and dimethyl ether, CH3OCH3, have the same molar mass, yet ethanol has a much higher boiling point. Briefly explain why. Write an equation to show the reaction between ethanol, C2H5OH and methyllithium, CH3Li. Draw all non-bonding electrons and show electron flow with curved arrows. 37. Write an equation that shows the reaction between acetic acid (CH3COOH) and triethylamine (CH3CH2)3N. Draw all non-bonding lone electron pairs and show the electron flow with curved arrows.arrow_forwardCI + (CH₂)₂CO-Na+ (CH3)3COH 100 °Carrow_forwardDraw 2‑methylpropanal. Include all hydrogen atoms. Predict the products when cyclohexanol is heated in the presence of H+.H+. Show all hydrogen atoms.arrow_forward
- OH H3C Type of Reaction: CH3 CH3 CH3 + OH Type of Reaction: + [0] НОarrow_forward2. Provide the reactant, reagents, or products for the following reactions. Br NH₂ $ Phthalimide NaOH, Br₂ H₂O Ag₂O H₂O, Aarrow_forward2. Write the equations: a) CH3 -CH-CH-COOH + Ca → CH, NH, b) CH3 -CH-CH – COOH + CH₂OH- CH, NH, c) CH3 -CH-CH-COOH + Ba(OH)₂ CH, NH, d) CH3 -CH-CH-COOH + HCI → CH, NH, e) CH3 -CH-CH-COOH- CH, NH, [0] OH [H] LIAIH4 H* +tº f) CH3 -CH-CH-COOH + CH3 -CH-CH-COOH- -H₂O CH, NH, NH₂ g) CH3 -CH-CH-COOH- CH3NH₂arrow_forward
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