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Consider the circuit in Figure 1.28. Let
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MICROELECT. CIRCUIT ANALYSIS&DESIGN (LL)
- Find DC analysis parameter and lower cutoff frequency due to C,? Assume re' = 2.5 ohm and Beta = 100. %3D +Vcc +12 V Rc C3 R1 10 k 1 ka Vas C1 10 μF 2N3904 1 μF 1002 4,7 ka 330 a 47 µF a) Find ib in DC analysis= b) Find ic in DC analysis= c) Find Vce in DC analysis= d) Find Vcb in DC analysis= e) Rin(Total)= f) fcl=arrow_forwardAll are a part of one problem. (a.)Reduce to a minimum sum of products (three terms): (X+W)(Y xor Z)+XW'(b.)Reduce to a minimum sum of products (four terms): (A xor BC)+BD+ACD(c.)Reduce to a minimum product of sums (three terms): (A'+C'+D')(A'+B+C)(A+B+D)(A+C+D)arrow_forwardVarious parameters of Schering bridge are given as follows. The voltage supply of 2 kHz is connected to terminals A and C and detector to points B and D. Arm AB comprises the unknown Resistor R1 and capacitor C1. Arm BC consists of resistor R2 of 18k 2. Arm DA consists of capacitor C2 of 0.06 µf. Arm CD has R3 of 1.5kſN and C3 of 2nf are in parallel. Calculate (i) the capacitance (C1) (ii) the equivalent series resistance (R1) and (iii) dissipation factor. Also draw the schematic diagram.arrow_forward
- For the circuit in the given figure, V2(s)/V1(s) R V2 1 1+ RCs 1+ RCS2 2 J O 4 1+ RCs 1+ RCsarrow_forwardCompute the effective value of current. 9 TIP: Use your CASIO's INTEGRATE function. i(t) A ... a T/2 b a = 13 A b = -15 A T= 4 sarrow_forward16. An RTD has α0 = 0.0035 /oC at T0= 50o C and Resistance R(T0)= 300 Ω . Determine the resistance at 20oC.arrow_forward
- 1. (s+0.2) G(s) = 5 (s+0.04) 19 - The compensator circuit (passive if possible) will be made, which is given the function at the bottom. If R1=50 MOhm is C, which of the following is it? A) 0.04 mikroF OB) 0.4 mikroF OC) 4 mikroF D) 0.4 milliF E) 40 microFarrow_forwardFind DC analysis parameter and lower cutoff frequency due to C,? Assume re = 2.5 ohm and Beta = 100. +Vcc +12 V Rc C3 1 ka R1 10ka 10 μF 2N3904 1 μF 100a R2 4,7 ka 330 a 47 µF Find ib in DC analysis= Find ic in DC analysis= a) b) c) Find Vce in DC analysis= d) Find Vcb in DC analysis= e) Rin(Total)= f) fcl=arrow_forwardQ4/ for the following figure : a) write the difference equation b) find h(n) X(n) y(n)arrow_forward
- (a) What is the function of the circuit given below (i.e. what does the circuit do)? (b) Calculate the value of [H(f)| evaluated at a frequency of 5 kHz taking into consideration the frequency response of this circuit. R1 Vs 80 kQ Vc Input sine C1 OUTPUT 1 nFarrow_forwardIt is known that the equivalent impedance of R=5 kiloOhm, L=4 H and Zab in the circuit given below is pure real (the imaginary part is zero). In this case, what is the operating frequency of the circuit in Hertz? a ict ir İR 5 - + D is)=10cos(500t+30°) mA Vo L R b O A) 500 Hz O B) 79.6 Hz 250 Hz O D) 50 Hz O E) 100 Hzarrow_forward12V L1 R1 1.2m 330 Vo Rc 500 Rb Q1 Vi NPN 10k The input voltage vi=5V for t Os h) iL(t) for t> Os i) vo(t) for t> Osarrow_forward
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