Chapter SR17, Problem 8P

Solution

Find the perimeter and area of the given figure.

Perimeter of rectangle $=42mm$

Area of rectangle $=108m{m}^2$

Given:

The given figure.

  

Concept Used:

• Formula of Perimeter of rectangle $=2(l+b)$
• Formula of Area of rectangle $=l\cdot b$

Calculation:

The given figure is -

  

As the both opposite sides are equal and angles are ${90}^0$ . So the given figure will be rectangle.

The Perimeter of rectangle $=2(l+b)$

  $\begin{array}{l}=2(12+9)\\ =2(21)\\ =42\end{array}$

So, Perimeter of rectangle $=42mm$

The Area of rectangle $=l\cdot b$

  $\begin{array}{l}=(12\cdot 9)\\ =108\end{array}$

So, Area of rectangle $=10m{m}^2$