Chapter SR17, Problem 2P

Solution

Find the perimeter and area of the given figure.

Perimeter of right angle triangle $=40ft$

Area of right angle triangle $=60f{t}^2$

Given:

The given figure.

  

Concept Used:

• Formula of Perimeter of right angle triangle $=a+b+\sqrt{a^2+b^2}$
• Formula of Area of right angle triangle $=\frac{1}{2}(base)(height)$

Calculation:

The given figure is -

  

As the given figure is right angle triangle.

The Perimeter of right angle triangle $=8+17+15=40$

So, Perimeter of right angle triangle $=40ft$

The Area of right angle triangle $=\frac{1}{2}(base)(height)$

  $\begin{array}{l}=\frac{1}{2}(15)(8)\\ =\frac{120}{2}\\ =60\end{array}$

So, Area of right angle triangle $=60f{t}^2$