Chapter SH, Problem 8.6EP

To determine

To simlplify

  $3(a-3)+a(a-1)+12=a(a-2)+3(a-2)+4$

Answer to Problem 8.6EP

  $a=-5$

Explanation of Solution

Given information:

  $3(a-3)+a(a-1)+12=a(a-2)+3(a-2)+4$

Calculation:

  $3(a-3)+a(a-1)+12=a(a-2)+3(a-2)+4$

Open brackets

  $(3)(a)+(3)(-3)+(a)(a)+(a)(-1)+12=a(a)+(a)(-2)+(3)(a)+(3)(-2)+4$

On solving,

  $3a-9+a^2-a+12=a^2-2a+3a-6+4$

Place right hand side terms to left hand side

  $3a-9+a^2-a+12-a^2+2a-3a+6-4=0$

Rearranging like terms

  $3a-a+2a-3a+a^2-a^2+12-9+6-4=0$

On solving,

  $a+5=0$

On solving,

  $a=-5$