Chapter SH, Problem 8.5EP

To determine

To simlplify

  $-4(b+3)+b(b-3)=-b(6-b)+2(b-3)$

Answer to Problem 8.5EP

  $b=-2$

Explanation of Solution

Given information:

  $-4(b+3)+b(b-3)=-b(6-b)+2(b-3)$

Calculation:

  $-4(b+3)+b(b-3)=-b(6-b)+2(b-3)$

Open brackets

  $-4(b)+(-4)(3)+(b)(b)+b(-3)=(-b)(6)+(-b)(-b)+2(b)+2(-3)$

On solving,

  $-4b-12+b^2-3b=-6b+b^2+2b-6$

Place right hand side terms to the terms left hand side

  $-4b-12+b^2-3b+6b-b^2-2b+6=0$

Rearranging like terms

  $-4b-2b+b^2-b^2-3b+6b+6-12=0$

On solving,

  $-6b+3b-6=0$

On solving,

  $-3b-6=0$

On solving,

  $-3b=6$

So,

  $b=\frac{6}{-3}$

On solving,

  $b=-2$