CHEM PRINCIPLES LL W/ACHIEVE ONE-SEM
7th Edition
ISBN: 9781319420994
Author: ATKINS
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter F, Problem M.3BST
Interpretation Introduction
Interpretation:
Percentage yield of nitric acid has to be calculated.
Concept Introduction:
The yield that can be obtained to the maximum from the given quantity of the reactant is known as theoretical yield. This does not consider the side reactions or impurities in the product formation. Percentage yield is the yield of the product that is formed expressed in terms of percentage. This can be given by the equation given below;
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionChapter F Solutions
CHEM PRINCIPLES LL W/ACHIEVE ONE-SEM
Ch. F - Prob. A.1ASTCh. F - Prob. A.1BSTCh. F - Prob. A.2ASTCh. F - Prob. A.2BSTCh. F - Prob. A.3ASTCh. F - Prob. A.3BSTCh. F - Prob. A.4ASTCh. F - Prob. A.4BSTCh. F - Prob. A.5ASTCh. F - Prob. A.5BST
Ch. F - Prob. A.1ECh. F - Prob. A.2ECh. F - Prob. A.3ECh. F - Prob. A.4ECh. F - Prob. A.5ECh. F - Prob. A.6ECh. F - Prob. A.7ECh. F - Prob. A.8ECh. F - Prob. A.9ECh. F - Prob. A.10ECh. F - Prob. A.11ECh. F - Prob. A.12ECh. F - Prob. A.13ECh. F - Prob. A.14ECh. F - Prob. A.15ECh. F - Prob. A.16ECh. F - Prob. A.17ECh. F - Prob. A.18ECh. F - Prob. A.19ECh. F - Prob. A.20ECh. F - Prob. A.21ECh. F - Prob. A.22ECh. F - Prob. A.23ECh. F - Prob. A.24ECh. F - Prob. A.25ECh. F - Prob. A.26ECh. F - Prob. A.27ECh. F - Prob. A.28ECh. F - Prob. A.29ECh. F - Prob. A.30ECh. F - Prob. A.31ECh. F - Prob. A.32ECh. F - Prob. A.33ECh. F - Prob. A.34ECh. F - Prob. A.35ECh. F - Prob. A.36ECh. F - Prob. A.37ECh. F - Prob. A.38ECh. F - Prob. A.39ECh. F - Prob. A.40ECh. F - Prob. A.41ECh. F - Prob. A.42ECh. F - Prob. B.1ASTCh. F - Prob. B.1BSTCh. F - Prob. B.2ASTCh. F - Prob. B.2BSTCh. F - Prob. B.3ASTCh. F - Prob. B.3BSTCh. F - Prob. B.1ECh. F - Prob. B.2ECh. F - Prob. B.3ECh. F - Prob. B.4ECh. F - Prob. B.5ECh. F - Prob. B.6ECh. F - Prob. B.7ECh. F - Prob. B.8ECh. F - Prob. B.9ECh. F - Prob. B.10ECh. F - Prob. B.11ECh. F - Prob. B.12ECh. F - Prob. B.13ECh. F - Prob. B.14ECh. F - Prob. B.15ECh. F - Prob. B.16ECh. F - Prob. B.17ECh. F - Prob. B.18ECh. F - Prob. B.19ECh. F - Prob. B.20ECh. F - Prob. B.21ECh. F - Prob. B.22ECh. F - Prob. C.1ASTCh. F - Prob. C.1BSTCh. F - Prob. C.2ASTCh. F - Prob. C.2BSTCh. F - Prob. C.1ECh. F - Prob. C.2ECh. F - Prob. C.3ECh. F - Prob. C.4ECh. F - Prob. C.5ECh. F - Prob. C.6ECh. F - Prob. C.7ECh. F - Prob. C.8ECh. F - Prob. C.9ECh. F - Prob. C.10ECh. F - Prob. C.11ECh. F - Prob. C.12ECh. F - Prob. C.13ECh. F - Prob. C.14ECh. F - Prob. C.15ECh. F - Prob. C.16ECh. F - Prob. C.17ECh. F - Prob. C.18ECh. F - Prob. C.19ECh. F - Prob. C.20ECh. F - Prob. C.21ECh. F - Prob. C.22ECh. F - Prob. D.1ASTCh. F - Prob. D.1BSTCh. F - Prob. D.2ASTCh. F - Prob. D.2BSTCh. F - Prob. D.3ASTCh. F - Prob. D.3BSTCh. F - Prob. D.4ASTCh. F - Prob. D.4BSTCh. F - Prob. D.5ASTCh. F - Prob. D.5BSTCh. F - Prob. D.1ECh. F - Prob. D.2ECh. F - Prob. D.3ECh. F - Prob. D.4ECh. F - Prob. D.5ECh. F - Prob. D.6ECh. F - Prob. D.7ECh. F - Prob. D.8ECh. F - Prob. D.9ECh. F - Prob. D.10ECh. F - Prob. D.11ECh. F - Prob. D.12ECh. F - Prob. D.13ECh. F - Prob. D.14ECh. F - Prob. D.15ECh. F - Prob. D.16ECh. F - Prob. D.17ECh. F - Prob. D.18ECh. F - Prob. D.19ECh. F - Prob. D.20ECh. F - Prob. D.21ECh. F - Prob. D.22ECh. F - Prob. D.23ECh. F - Prob. D.24ECh. F - Prob. D.25ECh. F - Prob. D.26ECh. F - Prob. D.27ECh. F - Prob. D.28ECh. F - Prob. D.29ECh. F - Prob. D.30ECh. F - Prob. D.31ECh. F - Prob. D.32ECh. F - Prob. D.33ECh. F - Prob. D.34ECh. F - Prob. D.35ECh. F - Prob. D.36ECh. F - Prob. E.1ASTCh. F - Prob. E.1BSTCh. F - Prob. E.2ASTCh. F - Prob. E.2BSTCh. F - Prob. E.3ASTCh. F - Prob. E.3BSTCh. F - Prob. E.4ASTCh. F - Prob. E.4BSTCh. F - Prob. E.5ASTCh. F - Prob. E.5BSTCh. F - Prob. E.6ASTCh. F - Prob. E.6BSTCh. F - Prob. E.1ECh. F - Prob. E.2ECh. F - Prob. E.3ECh. F - Prob. E.4ECh. F - Prob. E.5ECh. F - Prob. E.6ECh. F - Prob. E.7ECh. F - Prob. E.8ECh. F - Prob. E.9ECh. F - Prob. E.10ECh. F - Prob. E.11ECh. F - Prob. E.12ECh. F - Prob. E.13ECh. F - Prob. E.14ECh. F - Prob. E.15ECh. F - Prob. E.16ECh. F - Prob. E.17ECh. F - Prob. E.18ECh. F - Prob. E.19ECh. F - Prob. E.20ECh. F - Prob. E.21ECh. F - Prob. E.22ECh. F - Prob. E.23ECh. F - Prob. E.24ECh. F - Prob. E.25ECh. F - Prob. E.26ECh. F - Prob. E.27ECh. F - Prob. E.28ECh. F - Prob. E.29ECh. F - Prob. E.30ECh. F - Prob. E.31ECh. F - Prob. E.32ECh. F - Prob. E.33ECh. F - Prob. E.34ECh. F - Prob. F.1ASTCh. F - Prob. F.1BSTCh. F - Prob. F.2ASTCh. F - Prob. F.2BSTCh. F - Prob. F.3ASTCh. F - Prob. F.3BSTCh. F - Prob. F.4ASTCh. F - Prob. F.4BSTCh. F - Prob. F.1ECh. F - Prob. F.2ECh. F - Prob. F.3ECh. F - Prob. F.4ECh. F - Prob. F.5ECh. F - Prob. F.6ECh. F - Prob. F.7ECh. F - Prob. F.8ECh. F - Prob. F.9ECh. F - Prob. F.10ECh. F - Prob. F.11ECh. F - Prob. F.12ECh. F - Prob. F.13ECh. F - Prob. F.14ECh. F - Prob. F.15ECh. F - Prob. F.16ECh. F - Prob. F.17ECh. F - Prob. F.18ECh. F - Prob. F.19ECh. F - Prob. F.20ECh. F - Prob. F.21ECh. F - Prob. F.22ECh. F - Prob. F.23ECh. F - Prob. F.24ECh. F - Prob. F.25ECh. F - Prob. F.26ECh. F - Prob. F.27ECh. F - Prob. F.28ECh. F - Prob. G.1ASTCh. F - Prob. G.1BSTCh. F - Prob. G.2ASTCh. F - Prob. G.2BSTCh. F - Prob. G.3ASTCh. F - Prob. G.3BSTCh. F - Prob. G.4ASTCh. F - Prob. G.4BSTCh. F - Prob. G.1ECh. F - Prob. G.2ECh. F - Prob. G.3ECh. F - Prob. G.4ECh. F - Prob. G.5ECh. F - Prob. G.6ECh. F - Prob. G.7ECh. F - Prob. G.8ECh. F - Prob. G.9ECh. F - Prob. G.10ECh. F - Prob. G.11ECh. F - Prob. G.12ECh. F - Prob. G.13ECh. F - Prob. G.14ECh. F - Prob. G.15ECh. F - Prob. G.16ECh. F - Prob. G.17ECh. F - Prob. G.18ECh. F - Prob. G.19ECh. F - Prob. G.20ECh. F - Prob. G.21ECh. F - Prob. G.22ECh. F - Prob. G.23ECh. F - Prob. G.24ECh. F - Prob. G.25ECh. F - Prob. G.27ECh. F - Prob. G.28ECh. F - Prob. G.30ECh. F - Prob. H.1ASTCh. F - Prob. H.1BSTCh. F - Prob. H.1ECh. F - Prob. H.2ECh. F - Prob. H.3ECh. F - Prob. H.4ECh. F - Prob. H.5ECh. F - Prob. H.6ECh. F - Prob. H.7ECh. F - Prob. H.8ECh. F - Prob. H.9ECh. F - Prob. H.10ECh. F - Prob. H.11ECh. F - Prob. H.12ECh. F - Prob. H.13ECh. F - Prob. H.14ECh. F - Prob. H.15ECh. F - Prob. H.16ECh. F - Prob. H.17ECh. F - Prob. H.18ECh. F - Prob. H.19ECh. F - Prob. H.20ECh. F - Prob. H.21ECh. F - Prob. H.22ECh. F - Prob. H.23ECh. F - Prob. H.24ECh. F - Prob. H.25ECh. F - Prob. H.26ECh. F - Prob. I.1ASTCh. F - Prob. I.1BSTCh. F - Prob. I.2ASTCh. F - Prob. I.2BSTCh. F - Prob. I.3ASTCh. F - Prob. I.3BSTCh. F - Prob. I.1ECh. F - Prob. I.2ECh. F - Prob. I.3ECh. F - Prob. I.4ECh. F - Prob. I.5ECh. F - Prob. I.6ECh. F - Prob. I.7ECh. F - Prob. I.8ECh. F - Prob. I.9ECh. F - Prob. I.10ECh. F - Prob. I.11ECh. F - Prob. I.12ECh. F - Prob. I.13ECh. F - Prob. I.14ECh. F - Prob. I.15ECh. F - Prob. I.16ECh. F - Prob. I.17ECh. F - Prob. I.18ECh. F - Prob. I.19ECh. F - Prob. I.20ECh. F - Prob. I.21ECh. F - Prob. I.22ECh. F - Prob. I.23ECh. F - Prob. I.24ECh. F - Prob. I.25ECh. F - Prob. I.26ECh. F - Prob. J.1ASTCh. F - Prob. J.1BSTCh. F - Prob. J.2ASTCh. F - Prob. J.2BSTCh. F - Prob. J.1ECh. F - Prob. J.2ECh. F - Prob. J.3ECh. F - Prob. J.4ECh. F - Prob. J.5ECh. F - Prob. J.6ECh. F - Prob. J.7ECh. F - Prob. J.8ECh. F - Prob. J.9ECh. F - Prob. J.10ECh. F - Prob. J.11ECh. F - Prob. J.12ECh. F - Prob. J.13ECh. F - Prob. J.14ECh. F - Prob. J.15ECh. F - Prob. J.16ECh. F - Prob. J.17ECh. F - Prob. J.18ECh. F - Prob. J.19ECh. F - Prob. J.20ECh. F - Prob. J.21ECh. F - Prob. J.22ECh. F - Prob. J.23ECh. F - Prob. J.24ECh. F - Prob. K.1ASTCh. F - Prob. K.1BSTCh. F - Prob. K.2ASTCh. F - Prob. K.2BSTCh. F - Prob. K.3ASTCh. F - Prob. K.3BSTCh. F - Prob. K.4ASTCh. F - Prob. K.4BSTCh. F - Prob. K.5ASTCh. F - Prob. K.5BSTCh. F - Prob. K.1ECh. F - Prob. K.2ECh. F - Prob. K.3ECh. F - Prob. K.4ECh. F - Prob. K.5ECh. F - Prob. K.6ECh. F - Prob. K.7ECh. F - Prob. K.8ECh. F - Prob. K.9ECh. F - Prob. K.10ECh. F - Prob. K.11ECh. F - Prob. K.12ECh. F - Prob. K.13ECh. F - Prob. K.14ECh. F - Prob. K.15ECh. F - Prob. K.16ECh. F - Prob. K.17ECh. F - Prob. K.18ECh. F - Prob. K.19ECh. F - Prob. K.20ECh. F - Prob. K.21ECh. F - Prob. K.22ECh. F - Prob. K.23ECh. F - Prob. K.24ECh. F - Prob. K.25ECh. F - Prob. K.26ECh. F - Prob. L.1ASTCh. F - Prob. L.1BSTCh. F - Prob. L.2ASTCh. F - Prob. L.2BSTCh. F - Prob. L.3ASTCh. F - Prob. L.3BSTCh. F - Prob. L.1ECh. F - Prob. L.2ECh. F - Prob. L.3ECh. F - Prob. L.4ECh. F - Prob. L.5ECh. F - Prob. L.6ECh. F - Prob. L.7ECh. F - Prob. L.8ECh. F - Prob. L.9ECh. F - Prob. L.10ECh. F - Prob. L.11ECh. F - Prob. L.12ECh. F - Prob. L.13ECh. F - Prob. L.14ECh. F - Prob. L.15ECh. F - Prob. L.16ECh. F - Prob. L.17ECh. F - Prob. L.18ECh. F - Prob. L.19ECh. F - Prob. L.20ECh. F - Prob. L.21ECh. F - Prob. L.22ECh. F - Prob. L.23ECh. F - Prob. L.24ECh. F - Prob. L.25ECh. F - Prob. L.29ECh. F - Prob. L.30ECh. F - Prob. L.31ECh. F - Prob. L.32ECh. F - Prob. L.33ECh. F - Prob. L.34ECh. F - Prob. L.35ECh. F - Prob. L.37ECh. F - Prob. L.38ECh. F - Prob. L.39ECh. F - Prob. L.40ECh. F - Prob. L.41ECh. F - Prob. L.42ECh. F - Prob. M.1ASTCh. F - Prob. M.1BSTCh. F - Prob. M.2ASTCh. F - Prob. M.2BSTCh. F - Prob. M.3ASTCh. F - Prob. M.3BSTCh. F - Prob. M.4ASTCh. F - Prob. M.4BSTCh. F - Prob. M.1ECh. F - Prob. M.2ECh. F - Prob. M.3ECh. F - Prob. M.4ECh. F - Prob. M.5ECh. F - Prob. M.6ECh. F - Prob. M.7ECh. F - Prob. M.8ECh. F - Prob. M.9ECh. F - Prob. M.10ECh. F - Prob. M.11ECh. F - Prob. M.12ECh. F - Prob. M.13ECh. F - Prob. M.14ECh. F - Prob. M.15ECh. F - Prob. M.16ECh. F - Prob. M.17ECh. F - Prob. M.18ECh. F - Prob. M.19ECh. F - Prob. M.20ECh. F - Prob. M.21ECh. F - Prob. M.22ECh. F - Prob. M.23ECh. F - Prob. M.25ECh. F - Prob. M.26ECh. F - Prob. M.27ECh. F - Prob. M.28E
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- Nitric acid is produced commercially by the Ostwald process, represented by the following equations: 4NH3(g)+5O24NO(g)+6H2O(g)2NO(g)+O2(g)2NO2(g)3NO2(g)+H2O(l)2HNO3(aq)+NO(g) What mass of NH3 must be used to produce 1.0 106 kg HNO3 by the Ostwald process? Assume 100% yield in each reaction, and assume that the NO produced in the third step is not recycled.arrow_forwardThe balanced equation for the reduction of iron ore to the metal using CO is Fe2O3(s) + 3 CO(g) 2 Fe(s) + 3 CO2(g) (a) What is the maximum mass of iron, in grams, that can be obtained from 454 g (1.00 lb) of iron(III) oxide? (b) What mass of CO is required to react with 454 g cot Fe2O3?arrow_forwardA solution of scandium chloride was treated with silver nitrate. The chlorine in the scandium compound was converted to silver chloride, AgCl. A 58.9-mg sample of scandium chloride gave 167.4 mg of silver chloride. What are the mass percentages of Sc and Cl in scandium chloride? What is its empirical formula?arrow_forward
- 4.69 The pictures below show a molecular-scale view of a chemical reaction between H2 and CO to produce methanol, CH3OH. The box on the left represents the reactants at the instant of mixing, and the box on the right shows what is left once the reaction has gone to completion. Was there a limiting reactant in this reaction? If so, what was it? Write a balanced chemical equation for this reaction. As usual, your equation should use the smallest possible whole number coefficients for all substances.arrow_forwardWhat mass of HCI, in grams, is required to react with 0.750 g of Al(OH)3? What mass of water, in grams, is produced? Al(OH)3(s) + 3 HCI(aq) AlCl3(aq) + 3 H2O(l)arrow_forwardBoron forms an extensive series of compounds with hydrogen, all with the general formula BxHy. To analyze one of these compounds, you burn it in air and isolate the boron in the form of B2O3 and the hydrogen in the form of water. You find that 0.1482 g BxHy gives 0.4221 g B2O3 when burned in excess O2. Determine the empirical I formula of BxHy.arrow_forward
- Many cereals are made with high moisture content so that the cereal can be formed into various shapes before it is dried. A cereal product containing 58% H2O by mass is produced at the rate of 1000. kg/h. What mass of water must be evaporated per hour if the final product contains only 20.% water?arrow_forwardYou take 1.00 g of an aspirin tablet (a compound consisting solely of carbon, hydrogen, and oxygen), burn it in air, and collect 2.20 g CO2 and 0.400 g H2O. You know that the molar mass of aspirin is between 170 and 190 g/mol. Reacting 1 mole of salicylic acid with I mole of acetic anhydride (C4H6O3) gives you 1 mole of aspirin and 1 mole of acetic acid (C2H4O2). Use this information to determine the molecular formula of salicylic acid.arrow_forwardWrite a balanced equation for the reaction of hydroiodic acid, HI, with calcium hydroxide, Ca(OH)2. Then, write the balanced complete ionic equation and the net ionic equation for this neutralization reaction.arrow_forward
arrow_back_ios
arrow_forward_ios
Recommended textbooks for you
- Chemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage LearningChemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
- Chemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning
Chemistry for Engineering Students
Chemistry
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Cengage Learning
Chemistry: Principles and Practice
Chemistry
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Chemistry: An Atoms First Approach
Chemistry
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Cengage Learning
Step by Step Stoichiometry Practice Problems | How to Pass ChemistryMole Conversions Made Easy: How to Convert Between Grams and Moles; Author: Ketzbook;https://www.youtube.com/watch?v=b2raanVWU6c;License: Standard YouTube License, CC-BY