(a)
Interpretation:
The name of
Concept Introduction:
Binary molecular compounds are named by using the elements present in it and the number of atoms present in a molecule.
Rules for naming molecular compounds:
- First element name is written as such that is followed by the name of the second element in which the suffix is changed to –ide.
- Greek prefixes are used to indicate the number of atoms of each element that is present. Generally prefix mono- is ignored.
If the binary compound is present in aqueous solution and it contains hydrogen atom means, then it is named by adding hydro as prefix and ic acid as suffix to the root of the element name.
If the compound is an oxoacid, then the name of the acid is derived from its name of polyatomic ion from which it is produced or obtained. The name for the oxoacid formed from the ion that has suffix –ate ion is replaced by –ic acid and the oxoacaid formed form the ion that has suffix –ite ion is replaced by –ous acid.
(b)
Interpretation:
The name of
Concept Introduction:
Refer part (a).
(c)
Interpretation:
The name of
Concept Introduction:
Refer part (a).
(d)
Interpretation:
The name of
Concept Introduction:
Refer part (a).
(e)
Interpretation:
The name of
Concept Introduction:
Refer part (a).
(f)
Interpretation:
The name of
Concept Introduction:
Refer part (a).
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CHEM PRINCIPLES LL W/ACHIEVE ONE-SEM
- Sodium hydrogen carbonate (NaHCO3), also known as sodium bicarbonate or "baking soda", can be used to relieve acid indigestion. Acid indigestion is the burning sensation you get in your stomach when it contains too much hydrochloric acid (HC1) , which the stomach secretes to help digest food. Drinking a glass of water containing dissolved NaHCO3, neutralizes excess HCl through this reaction; HCl(aq) + NaHCO3(aq) -> NaCl(aq) + H2O(l) + CO2(g) The CO2 gas produced is what makes you burp after drinking the solution, Suppose the fluid in the stomach of a woman suffering from indigestion can be considered to be 50 mL. of a 0.093 M HCI solution. What mass of NaHCO3 would she need to ingest to neutralize this much HC1 ? Round your answer to 2 significant digits.arrow_forwardGive the answers that should be filled in the blanks below: Acetic acid solution: pH = 5.80; (a) [H*] = Ammonia solution: [H] = 5.90 x 10-9 M; (c) pH = M; (b) [OH-] = ; (d) pOH = M.arrow_forwardWhat are the most likely products of the reaction between aqueous lithium carbonate and aqueous nitric acid? O CO(e), LINO,(aq) and H20() HCO,(aq) and LINO,(aq) O CO,(g), H,(g) and LINO (aq) O LiHCO;(aq) and NO,(g) D There is no reactionarrow_forward
- What is the total ionic reaction and net ionic reaction of Na2CO3 (aq)+ 2HCl(aq) -> 2NaCl (aq)+ CO2(g) + H2O(l)?arrow_forwardH9SO4. H,SO4(aq)arrow_forwardComplete and balance the following equations: (a) NaOCH3(8) + H2O(I) (b) CuO(s) + HNO;(aq) (c) WO;(s) + H2(8) (d) NH,OH(I) + O,(8) (e) Al,C3(s) + H,0(1)arrow_forward
- 5. Balance the following equations and write the corresponding ionic and net ionicequations (if appropriate): (а) CH-COОН (аq) + коН(ад) (b) Н-СОз(аq) + NaOH(aq) (c) HNO;(aq) + Ba(ОН),(аq) —arrow_forward31. 10.0 mL. of concentrated of H3PO4(aq) is diluted to the final volume of 250.0 mL. Then 15.0 mL. of the diluted H3PO4(aq) is titrated with 0.0455 M NaOH(aq) that one of the product is Na2HPO4(aq). It takes 24.35 mL. NaOH(aq) to complete the reaction. Calculate molarity of H3PO4(aq) in the concentrated solution. Group of answer choices a.0.923 M b.1.85 M c.3.00 M d.0.132 Marrow_forward31. 10.0 mL. of concentrated of H3PO4(aq) is diluted to the final volume of 250.0 mL. Then 15.0 mL. of the diluted H3PO4(aq) is titrated with 0.0455 M NaOH(aq) that one of the product is Na2HPO4(aq). It takes 24.35 mL. NaOH(aq) to complete the reaction. Calculate molarity of H3PO4(aq) in the concentrated solution. a.0.132 Mb.3.00 Mc.0.923 Md.1.85 Marrow_forward
- 6. (i) Define pH in words. The strong acid HCl has a pH value of 1, use the following equation for a strong acid: aq HC1 aq à pH = -logo [H*] 10 Ht pH = aq + Cl and convert the following expression to deduce the hydrogen ion concentration: aq (ii) Use the above expression to deduce the pH of HCl (aq) given the concentration of the acid to be 4.5 mol/dm³arrow_forwardA student is given an antacid tablet that weighs 5.9200 g. The tablet is crushed and 4.8270 g of the antacid is added to 200. mL of simulated stomach acid. It is allowed to react and then filtered. It is found that 25.00 mL of this partially neutralized stomach acid required 11.7 mL of a NaOH solution to titrate it to a methyl red end point. It takes 27.8 mL of this NaOH solution to neutralize 25.00 mL of the original stomach acid. How much of the stomach acid (in mL) is neutralized by the 4.8270 g crushed sample of the tablet?arrow_forward(b) Na2CO3(aq) and Mgso (aq) complete ionic equation: (aq) + co32-(aq) + Mg2+(aq) + so,2-(aq) - (s) + Nat(aq) + (aq) net ionic equation: Mg2+(aq) + (aq) → (s) (c) Pb(NO3)2,(ag) and Al,(so)3(ag)arrow_forward
- Principles of Modern ChemistryChemistryISBN:9781305079113Author:David W. Oxtoby, H. Pat Gillis, Laurie J. ButlerPublisher:Cengage Learning