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(a)
Interpretation:
E or Z configuration is to be assigned to each double bond wherever appropriate in the given molecule.
Concept introduction:
When assigning priorities to substituents, the atom having the greater
(b)
Interpretation:
E or Z configuration is to be assigned to each double bond wherever appropriate in the given molecule.
Concept introduction:
When assigning priorities to substituents, the atom having the greater atomic number has a higher priority. In the case of comparison between isotopes, the one having the greater atomic mass gets the higher priority. If the substituents are attached by the same atom, then the set of atoms one bond away from the point of attachment is compared. In each set, the highest priority atoms are compared. If the sets of atoms one bond away from the point of attachment are identical, then the sets of atoms one additional bond away from the point of attachment are compared. If the higher priority groups attached to the double bonded carbon atoms are on the same side of the double bond, the alkene is assigned Z configuration. If the higher priority groups attached to the double bonded carbon atoms are on the opposite side of the double bond, the alkene is assigned E configuration. When more than one double bond is present, each is assigned E or Z configuration, and the location of each double bond appears immediately before the E or Z designation.
(c)
Interpretation:
E or Z configuration is to be assigned to each double bond wherever appropriate in the given molecule.
Concept introduction:
When assigning priorities to substituents, the atom having the greater atomic number has a higher priority. In the case of comparison between isotopes, the one having the greater atomic mass gets the higher priority. If the substituents are attached by the same atom, then the set of atoms one bond away from the point of attachment is compared. In each set, the highest priority atoms are compared. If the sets of atoms one bond away from the point of attachment are identical, then the sets of atoms one additional bond away from the point of attachment are compared. If the higher priority groups attached to the double bonded carbon atoms are on the same side of the double bond, the alkene is assigned Z configuration. If the higher priority groups attached to the double bonded carbon atoms are on the opposite side of the double bond, the alkene is assigned E configuration. When more than one double bond is present, each is assigned E or Z configuration, and the location of each double bond appears immediately before the E or Z designation.
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Chapter C Solutions
Organic Chemistry: Principles and Mechanisms (Second Edition)
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- this is an inorganic chemistry question please answer accordindly!! its just one question with parts till (g) JUST ONE QUESTION with its parts spread out in the form of different images attached 2 IMAGES ATTACHED PLEASE SEE ALL, please answer EACH part till the end and dont just provide wordy explanations wherever asked for structures or diagrams, please DRAW DRAW them on a paper and post clearly!! answer the full question with all details EACH PART CLEARLY please thanks!! im reposting this please solve all parts and drawit not just word explanations!!arrow_forwardThe complex anion in Ba₂[Cr(CN)6] is a tetragonally distorted octahedral complex (Dan). Baz[Cr(CN)6] is paramagnetic at room temperature with S = 1. Assume that the complex is a low-spin complex. a) Identify if the [Cr(CN)6] anionic complex has 4 long and 2 short bonds (left side of figure) or if the complex has 4 short and 2 long bonds (right side of figure) with respect to Oh symmetry. Use crystal field theory to answer this question. Explain/rationalize your decision. Can the provided information decide on the order of orbital energies? Dah Tetragonal Distortion ய Dab z-compression z-elongation x and y elongation O symmetry x and y compression E eg d² dx²-y² t2g dxy dxz dyz Question 4 a) continued: Provide your explanations in the space below. b) At low temperatures Ba₂[Cr(CN)6] is ferromagnetically ordered with a phase transition to a paramagnetic phase at Tc = 150K. Sketch the magnetic susceptibility vs. temperature in the diagram below. Indicate Tc as well as the paramagnetic and…arrow_forwarda) Draw the octahedral mer-[FeCl3(CN)3] complex and determine its point group. Use proper wedges and dashes in order to illustrate 3 dimensional details. Use the point group to determine if the complex has a resulting net dipole moment and describe its allowed direction with respect to its symmetry elements (if applicable). ード M 4- b) Substitute one chlorido ligand in mer-[FeCl3(CN)3] 4 with one fluorido ligand. Determine all possible isomers and their corresponding point groups. Use the point groups to determine if the complexes have resulting net dipole moments and describe their allowed direction with respect to its symmetry elements (if applicable). The number of complex sketches below is not necessarily indicative of the number of isomers. 4- 4- ☐☐☐ c) Substitute two chlorido ligands in mer-[FeCl3 (CN)3] 4 with two fluorido ligands. Determine all possible isomers and their corresponding point groups.. Use the point groups to determine if the complexes have resulting net dipole…arrow_forward
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Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning