Machine Tool Practices (11th Edition)
11th Edition
ISBN: 9780134893501
Author: Richard R. Kibbe, Roland O. Meyer, Jon Stenerson, Kelly Curran
Publisher: PEARSON
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Chapter B.3, Problem 7ST
Give two reasons why hacksaw blades break.
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1- Determine the following: 1- RSHF? 2- C.C.C in tons-ref. 3- Mass
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How do I solve this task
A weight for a lift is suspended using an adapter. The counterweight is held up with 4 screws. The weight F is 3200kg.
The screws have a strength class of 8.8. Safety factor 3
Which is the smallest bunch size that can be used?+_Sr/Fm =0,16Gr=0,71ơ=800·0.8=640 MPaAs=?Fmax= As·ơ·GrFs=ơs·AsFFm= Fs· GFSF =SF / FFm · FFm Fpreload =Fload / SF → Fload /3Fpreload per screw =Fload / SF → Fload /4As=Fpreload per screw /ơ·Gr → As= Fpreload per screw / 640· 0.71
The correct answer should be M12 with As=84.3mm²
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Dr. Abduljabbo
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27/12/2024
Chapter B Solutions
Machine Tool Practices (11th Edition)
Ch. B.1 - List several uses of the arbor press.Ch. B.1 - A newly machined steel shaft with an interference...Ch. B.1 - The ram of an arbor press is loose in its guide...Ch. B.1 - When a bushing is pushed into a bore that is...Ch. B.1 - Prob. 5STCh. B.1 - What difference is there in the way a press fit is...Ch. B.1 - Prior to installing a bushing with the arbor...Ch. B.1 - Name five ways to avoid tool breakage and other...Ch. B.2 - Name two types of bench visesCh. B.2 - Prob. 2ST
Ch. B.2 - How can the finished surface of a part be...Ch. B.2 - Name three things that should never be done to a...Ch. B.2 - How should a vise be Lubricated?Ch. B.2 - Prob. 6STCh. B.2 - What advantage does the lever-jawed wrench offer...Ch. B.2 - Some objects should never be struck with a hard...Ch. B.2 - Why should pipe wrenches never be used on bolts,...Ch. B.2 - What are the two important things to remember...Ch. B.3 - What is the kerf?Ch. B.3 - What is the set on a saw blade?Ch. B.3 - What is the pitch of the hacksaw blade?Ch. B.3 - What determines the selection of a saw blade for a...Ch. B.3 - Hand hacksaw blades fall into two basic...Ch. B.3 - Give four causes that make saw blades dull.Ch. B.3 - Give two reasons why hacksaw blades break.Ch. B.3 - A new hacksaw blade should not be used in a cut...Ch. B.4 - What are the four different cuts found on files?Ch. B.4 - Name four coarseness designations for files.Ch. B.4 - Which of the two kinds of files-single cut or...Ch. B.4 - What are the coarseness designations for needle...Ch. B.4 - Prob. 5STCh. B.4 - What causes a file to get dull?Ch. B.4 - Why should a handle be used on a file?Ch. B.4 - How does the hardness of a workpiece affect the...Ch. B.4 - Should pressure be applied to a file on the return...Ch. B.4 - Why is a round file rotated while it is being...Ch. B.5 - Prob. 1STCh. B.5 - What is the purpose of a starting taper on a...Ch. B.5 - What is the advantage of a spiral flute reamer...Ch. B.5 - How does the shank diameter of a hand reamer...Ch. B.5 - Prob. 5STCh. B.5 - Prob. 6STCh. B.5 - What is the purpose of cutting fluid in reaming?Ch. B.5 - Prob. 8STCh. B.5 - How much reaming allowance is left for hand...Ch. B.5 - If you were repairing the lathe tailstock taper,...Ch. B.6 - What type of tap is used to produce threads that...Ch. B.6 - Prob. 2STCh. B.6 - Prob. 3STCh. B.6 - When is a spiral fluted tap used?Ch. B.6 - How are thread-forming taps different from...Ch. B.6 - How are taper pipe taps identified?Ch. B.6 - Why are finishing and roughing Acme taps used?Ch. B.6 - Why are rake angles varied on taps for different...Ch. B.7 - What kind of tools are used to drive taps when...Ch. B.7 - What is a hand tapper?Ch. B.7 - What is a tapping attachment?Ch. B.7 - Which three factors affect the strength of a...Ch. B.7 - How deep should the usable threads be in a tapped...Ch. B.7 - What causes taps to break while tapping?Ch. B.7 - What causes rough and tom threads?Ch. B.7 - Give three methods of removing broken taps from...Ch. B.8 - What is a die?Ch. B.8 - What tool is used to drive a die?Ch. B.8 - How much adjustment is possible with a round split...Ch. B.8 - What are important points to watch when assembling...Ch. B.8 - Why do dies have a chamfer on the cutting end?Ch. B.8 - Why are cutting fluids used?Ch. B.8 - What diameter should a rod be before being...Ch. B.8 - Why should a rod be chamfered before being...Ch. B.9 - Prob. 1STCh. B.9 - Why should a tool grinder never be used for rough...Ch. B.9 - Prob. 3STCh. B.9 - Prob. 4STCh. B.9 - Prob. 5STCh. B.9 - Prob. 6STCh. B.9 - Prob. 7STCh. B.9 - What is the purpose of the wheel blotter?Ch. B.9 - Prob. 9STCh. B.9 - What does the wheel ring test do?
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- P₂ 7+1 * P₁ ART 2 P (P₁ - P₂- Zgp) 21 / Prove that :- m² a cda A₂ == * Cde actual mip Solutionarrow_forwardQ1/ Show that (actual 02/ A simple iet == Cda Cdf х Af 2/Y - Y+1/Y 2P(P1-P2-zxgxpr)arrow_forward5. Determine the transfer function of G(s) = 01(s)/T₁(s) and 02(s)/T₁ for the mechanical system shown in Figure Q5. (Hints: assume zero initial condition) T₁(t) 01(t) 102(1) Ол N1 D1 D2 No. 1790220000 N2 Figure Q5 K2arrow_forward
- A spring package with two springs and an external force, 200N. The short spring has a loin of 35 mm. Constantly looking for spring for short spring so that total compression is 35 mm (d). Known values: Long spring: Short spring:C=3.98 N/mm Lo=65mmLo=87.4mmF=c·fTotal compression is same for both spring. 200 = (3.98(c1) × 35) + (c₂ × 35) 200 = 139.3 + 35c₂ 200 - 139.3 = 35c₂ 60.7 = 35c₂ c₂ = 60.7/35 Short spring (c₂) = 1.73 N/mm According to my study book, the correct answer is 4.82N/mm What is wrong with the calculating?arrow_forwardWhat is the reason for this composition?arrow_forwardHomework: ANOVA Table for followed design B AB Dr -1 -1 1 (15.18,12) 1 -1 -1 (45.48.51) -1 1 -1 (25,28,19) 1 1 (75.75,81)arrow_forward
- 20. [Ans. 9; 71.8 mm] A semi-elliptical laminated spring is made of 50 mm wide and 3 mm thick plates. The length between the supports is 650 mm and the width of the band is 60 mm. The spring has two full length leaves and five graduated leaves. If the spring carries a central load of 1600 N, find: 1. Maximum stress in full length and graduated leaves for an initial condition of no stress in the leaves. 2. The maximum stress if the initial stress is provided to cause equal stress when loaded. [Ans. 590 MPa ; 390 MPa ; 450 MPa ; 54 mm] 3. The deflection in parts (1) and (2).arrow_forwardQ6/ A helical square section spring is set inside another, the outer spring having a free length of 35 mm greater than the inner spring. The dimensions of each spring are as follows: Mean diameter (mm) Side of square section (mm) Active turns Outer Inner Spring Spring 120 70 8 7 20 15 Determine the (1) Maximum deflection of the two springs and (2) Equivalent spring rate of the two springs after sufficient load has been applied to deflect the outer spring 60 mm. Use G = 83 GN/m².arrow_forwardQ2/ The bumper springs of a railway carriage are to be made of rectangular section wire. The ratio of the longer side of the wire to its shorter side is 1.5, and the ratio of mean diameter of spring to the longer side of wire is nearly equal to 6. Three such springs are required to bring to rest a carriage weighing 25 kN moving with a velocity of 75 m/min with a maximum deflection of 200 mm. Determine the sides of the rectangular section of the wire and the mean diameter of coils when the shorter side is parallel to the axis of the spring. The allowable shear stress is not to exceed 300 MPa and G = 84 kN/mm². Q6/ A belicalarrow_forward
- 11. A load of 2 kN is dropped axially on a close coiled helical spring, from a height of 250 mm. The spring has 20 effective turns, and it is made of 25 mm diameter wire. The spring index is 8. Find the maximum shear stress induced in the spring and the amount of compression produced. The modulus of rigidity for the material of the spring wire is 84 kN/mm². [Ans. 287 MPa; 290 mm]arrow_forwardWhat is the reason for this composition?arrow_forwardHomework: ANOVA Table for followed design B AB Dr -1 -1 1 (15.18,12) 1 -1 -1 (45.48.51) -1 1 -1 (25,28,19) 1 1 (75.75,81)arrow_forward
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