
To calculate: The quotient and remainder when the polynomial 0.1x3+0.2x is divided by x+1.1 with help of synthetic division.

Answer to Problem 13AYU
The quotient is 0.1x2−0.11x+0.321 and reminder is −0.3531 .
Explanation of Solution
Given information:
The polynomial 0.1x3+0.2x and a factor of it x+1.1 .
Formula used:
When a polynomial is divided by its factor then dividend is the product of divisor and quotient increased by remainder.
Calculation:
Consider the provided polynomial 0.1x3+0.2x and a factor of it x+1.1 .
To divide the polynomial 0.1x3+0.2x by x+1.1 follow the steps provided below,
Here dividend is 0.1x3+0⋅x2+0.2x+0 and divisor is x−(−1.1) .
Step 1: List down the coefficients of dividend in the descending powers of x, that are 0.1,0,0.2,0 .
Now, the divisor is of the form x−c , where c=−1.1 .
Step 2: To perform the synthetic division put the coefficients in the division sign along with −1.1 on the left side,
−1.10.100.20
Step 3: Bring down 0.1 to in third row,
−1.10.100.200.1
Step 4: Multiply −1.1 with the first entry of row 3 and place the result in row 2 column 2.
−1.10.100.20−0.110.1
Step 5: Now, add the elements of column 2 of row 1 and row 2.
−1.10.100.20−0.110.1−0.11
Step 6: Multiply −1.1 with the second entry of row 3 and place the result in row 2 column 3.
−1.10.100.20−0.110.1210.1−0.11
Step 7: Now, add the elements of column 3 of row 1 and row 2.
−1.10.100.20−0.110.1210.1−0.110.321
Step 8: Multiply −1.1 with the third entry of row 3 and place the result in row 2 column 4.
−1.10.100.20−0.110.121−0.35310.1−0.110.321
Step 9: Now, add the elements of column 4 of row 1 and row 2.
−1.10.100.20−0.110.121−0.35310.1−0.110.321−0.3531
Now, the first three elements of row 3 are coefficients of quotient in descending powers of x with degree one less than dividend and the last entry is remainder.
Therefore, quotient is 0.1x2−0.11x+0.321 and reminder is −0.3531 .
Now, when a polynomial is divided by its divisor then dividend is the product of divisor and quotient increased by remainder.
0.1x3+0.2x=(0.1x2−0.11x+0.321)(x+1.1)+(−0.3531)
To verify multiply the terms on the right hand side,
(0.1x2−0.11x+0.321)(x+1.1)−0.3531=0.1x3+0.2x
Thus, the quotient is 0.1x2−0.11x+0.321 and reminder is −0.3531 when the polynomial 0.1x3+0.2x is divided by x+1.1 .
Chapter A Solutions
Precalculus
Additional Math Textbook Solutions
Pre-Algebra Student Edition
Thinking Mathematically (6th Edition)
College Algebra with Modeling & Visualization (5th Edition)
Elementary Statistics (13th Edition)
A First Course in Probability (10th Edition)
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