Chapter A.10, Problem 2AYU

To determine

To find: the solution for $\sqrt{16}$ and $\sqrt{{\left(-4\right)}^2}$ .

Answer to Problem 2AYU

The solution for $\sqrt{16}$ is $4$ and $\sqrt{{\left(-4\right)}^2}$ is $4$ .

Explanation of Solution

Given information:

The given terms are $\sqrt{16}$ and $\sqrt{{\left(-4\right)}^2}$

Calculation:

Consider the term $\sqrt{16}$ .

Calculate the square root of $\sqrt{16}$ .

  $\sqrt{16}=4$

Consider the term $\sqrt{{\left(-4\right)}^2}$ .

Solve the term $\sqrt{{\left(-4\right)}^2}$ .

  $\begin{array}{c}\sqrt{{\left(-4\right)}^2}=\sqrt{16}\\ =4\end{array}$

Therefore, the solution for $\sqrt{16}$ is $4$ and $\sqrt{{\left(-4\right)}^2}$ is $4$ .