Chapter 9.7, Problem 9.20P

(a)

Interpretation Introduction

Interpretation:

The gas which diffuse more rapidly and their relative rates of diffusion has to be calculated.

Concept Introduction:

Graham law of effusion:

At constant pressure, constant temperature the rate of effusion of the gas is inversely proportional to square root of the molar mass of the gas.

$\frac{\text{Rate}{}_{\text{1}}}{\text{Rate}{}_{\text{2}}}\text{=}\sqrt{\frac{\text{Molar}{\text{mass}}_{\text{1}}}{\text{Molar}{\text{mass}}_{\text{2}}}}$

(b)

Interpretation Introduction

Interpretation:

The gas which diffuse more rapidly and their relative rates of diffusion has to be calculated.

Concept Introduction:

Graham law of effusion:

At constant pressure, constant temperature the rate of effusion of the gas is inversely proportional to square root of the molar mass of the gas.

$\frac{\text{Rate}{}_{\text{1}}}{\text{Rate}{}_{\text{2}}}\text{=}\sqrt{\frac{\text{Molar}{\text{mass}}_{\text{1}}}{\text{Molar}{\text{mass}}_{\text{2}}}}$