
To calculate: To plot the point in rectangular coordinates and find two setsof polar representations of the point, using 0<θ<2π

Answer to Problem 36E
The rectangular coordinates of point on the graph is plotted and two sets of polar points are (3√2,5π4),(−3√2,π4)
Explanation of Solution
Given information: Rectangularis (−3,−3)
Formula Used:
Polar coordinate of a point (x,y) is given as
(r,θ)
Where,
r=√x2+y2
θ=arctan(|yx|)
If both x,y>0 , then θ=α
If x<0,y>0 , then θ=π−α
If x,y<0 , then θ=π+α
If x>0,y<0 , then θ=−α
Point (r,θ) can be represented as
(r,θ)=(r,θ±2nπ)
Or
(r,θ)=(−r,θ±(2n+1)π)
Calculation:
Rectangular point is given as
(−3,−3)
Plotting the rectangular coordinates on the graph
Converting rectangular coordinates into polar coordinates:
Polar coordinate of a point (x,y) is given as
(r,θ)
Calculating the value of r :
r=√(−3)2+(−3)2r=√9+9r=√18r=3√2
Calculating the value of θ :
Since x,y<0 , then θ=π+α
θ=πarctan(|−3−3|)θ=π+π4θ=5π4
Thus, polar coordinate of point is (3√2,5π4)
Now, let’s find another set polar representations of the point, where 0<θ<2π
Point (r,θ) can be represented as
(r,θ)=(−r,θ±(2n+1)π)
Here,
r=3√2θ=5π4
Substituting the values in above representations, another representation of given point are:
(−3√2,5π4−π)=(−3√2,π4)
Conclusion:
Hence, rectangular coordinates of point on the graph is plotted and twosets of polar points are (3√2,5π4),(−3√2,π4)
Chapter 9 Solutions
Precalculus with Limits: A Graphing Approach
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