EBK PRECALCULUS W/LIMITS
4th Edition
ISBN: 9781337516853
Author: Larson
Publisher: CENGAGE CO
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Question
Chapter 9.4, Problem 76E
To determine
Use mathematical induction to prove this formula for a general n -sided
Expert Solution & Answer
Answer to Problem 76E
Proved
Explanation of Solution
Calculation:
Consider the given figures.
Consider triangle,
Sum of the angles, 180°=(3−2)180°
Now consider square,
Sum of the angles 360°=(4−2)180°
Sum of the angles of polygon,
540°=(5−2)180°
So that the formula for sum of the angle in regular polygon of n sides are,
(n−2)180°
Apply mathematical induction,
Let Sn: Sum of angles in a regular polygon of n sides is (n−2)180°
First prove the statement for triangle n=3
(3−2)180°=180°
Hence, formula is valid for triangle.
Now assume that formula is valid for some integer k that is,
Sk: Sum of angles in a regular polygon of k sides is (k−2)180°
Now let see Sk+1 is a valid statement,
That is you must prove sum of angles in a regular polygon of (k+1) sides is (k−1)180°
Consider the polygon of (k+1) sides
The polygon is divided in two patrs by diagonal as shown, in triangle
By induction method sum of angles in a polygon of k sides is (k−2)180°
And sum of angles in a triangle is 180°
So total sum is
(k−2)180°+180°=(k−1)180°
Hence, Proved .
Chapter 9 Solutions
EBK PRECALCULUS W/LIMITS
Ch. 9.1 - Prob. 1ECh. 9.1 - Prob. 2ECh. 9.1 - Prob. 3ECh. 9.1 - Prob. 4ECh. 9.1 - Prob. 5ECh. 9.1 - Prob. 6ECh. 9.1 - Prob. 7ECh. 9.1 - Prob. 8ECh. 9.1 - Prob. 9ECh. 9.1 - Prob. 10E
Ch. 9.1 - Prob. 11ECh. 9.1 - Prob. 12ECh. 9.1 - Prob. 13ECh. 9.1 - Prob. 14ECh. 9.1 - Prob. 15ECh. 9.1 - Prob. 16ECh. 9.1 - Prob. 17ECh. 9.1 - Prob. 18ECh. 9.1 - Prob. 19ECh. 9.1 - Prob. 20ECh. 9.1 - Prob. 21ECh. 9.1 - Prob. 22ECh. 9.1 - Prob. 23ECh. 9.1 - Prob. 24ECh. 9.1 - Prob. 25ECh. 9.1 - Prob. 26ECh. 9.1 - Prob. 27ECh. 9.1 - Prob. 28ECh. 9.1 - Prob. 29ECh. 9.1 - Prob. 30ECh. 9.1 - Prob. 31ECh. 9.1 - Prob. 32ECh. 9.1 - Prob. 33ECh. 9.1 - Prob. 34ECh. 9.1 - Prob. 35ECh. 9.1 - Prob. 36ECh. 9.1 - Prob. 37ECh. 9.1 - Prob. 38ECh. 9.1 - Prob. 39ECh. 9.1 - Prob. 40ECh. 9.1 - Prob. 41ECh. 9.1 - Prob. 42ECh. 9.1 - Prob. 43ECh. 9.1 - Prob. 44ECh. 9.1 - Prob. 45ECh. 9.1 - Prob. 46ECh. 9.1 - Prob. 47ECh. 9.1 - Prob. 48ECh. 9.1 - Prob. 49ECh. 9.1 - Prob. 50ECh. 9.1 - Prob. 51ECh. 9.1 - Prob. 52ECh. 9.1 - Prob. 53ECh. 9.1 - Prob. 54ECh. 9.1 - Prob. 55ECh. 9.1 - Prob. 56ECh. 9.1 - Prob. 57ECh. 9.1 - Prob. 58ECh. 9.1 - Prob. 59ECh. 9.1 - Prob. 60ECh. 9.1 - Prob. 61ECh. 9.1 - Prob. 62ECh. 9.1 - Prob. 63ECh. 9.1 - 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Prob. 15CLTCh. 9 - Prob. 16CLTCh. 9 - Prob. 17CLTCh. 9 - Prob. 18CLTCh. 9 - Prob. 19CLTCh. 9 - Prob. 20CLTCh. 9 - Prob. 21CLTCh. 9 - Prob. 22CLTCh. 9 - Prob. 23CLTCh. 9 - Prob. 24CLTCh. 9 - Prob. 25CLTCh. 9 - Prob. 26CLTCh. 9 - Prob. 27CLTCh. 9 - Prob. 28CLTCh. 9 - Prob. 29CLTCh. 9 - Prob. 30CLTCh. 9 - Prob. 31CLTCh. 9 - Prob. 32CLTCh. 9 - Prob. 33CLTCh. 9 - Prob. 34CLTCh. 9 - Prob. 35CLTCh. 9 - Prob. 36CLTCh. 9 - Prob. 37CLTCh. 9 - Prob. 38CLTCh. 9 - Prob. 39CLTCh. 9 - Prob. 40CLTCh. 9 - Prob. 41CLTCh. 9 - Prob. 1PSCh. 9 - Prob. 2PSCh. 9 - Prob. 3PSCh. 9 - Prob. 4PSCh. 9 - Prob. 5PSCh. 9 - Prob. 6PSCh. 9 - Prob. 7PSCh. 9 - Prob. 8PSCh. 9 - Prob. 9PSCh. 9 - Prob. 10PSCh. 9 - Prob. 11PSCh. 9 - Prob. 12PSCh. 9 - Prob. 13PSCh. 9 - Prob. 14PSCh. 9 - Prob. 15PSCh. 9 - Prob. 16PS
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