An Introduction to Physical Science
14th Edition
ISBN: 9781305079137
Author: James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres
Publisher: Cengage Learning
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Chapter 9, Problem 9SA
To determine
The difference between photon of red light and of violet light in terms of energy, frequency and wavelength.
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If the wavelength of a photon is doubled, describe what happens to its energy.
How would you describe the frequency of such light?
Photons of a certain ultraviolet light have an energy of 6.08 x 1019 J.
(a) What is the frequency of this UV light?
Hz
(b) Use 1 = c/f to calculate its wavelength in nanometers (nm).
nm
1a) Light that has a frequency of about 5.55 * 1014 Hz (a wavelength of about 543 nm) appears green to our eyes. What is the energy in joules of the photons associated with this light?=__________ J
1b) The human eye is sensitive to yellow-green light having a frequency of about 5.5 * 1014 Hz (a wavelength of about 550 nm). What is the energy in joules of the photons associated with this light?
=_____________J
Chapter 9 Solutions
An Introduction to Physical Science
Ch. 9.1 - Prob. 1PQCh. 9.1 - Prob. 2PQCh. 9.2 - Prob. 1PQCh. 9.2 - Prob. 2PQCh. 9.2 - Prob. 9.1CECh. 9.3 - Prob. 1PQCh. 9.3 - When does a hydrogen atom emit or absorb radiant...Ch. 9.3 - Prob. 9.2CECh. 9.3 - Prob. 9.3CECh. 9.3 - Prob. 9.4CE
Ch. 9.4 - Prob. 1PQCh. 9.4 - Prob. 2PQCh. 9.5 - Prob. 1PQCh. 9.5 - Prob. 2PQCh. 9.6 - Prob. 1PQCh. 9.6 - Prob. 2PQCh. 9.6 - Prob. 9.5CECh. 9.7 - Prob. 1PQCh. 9.7 - Prob. 2PQCh. 9 - Prob. AMCh. 9 - Prob. BMCh. 9 - Prob. CMCh. 9 - Prob. DMCh. 9 - Prob. EMCh. 9 - Prob. FMCh. 9 - Prob. GMCh. 9 - Prob. HMCh. 9 - Prob. IMCh. 9 - Prob. JMCh. 9 - Prob. KMCh. 9 - Prob. LMCh. 9 - Prob. MMCh. 9 - Prob. NMCh. 9 - Prob. OMCh. 9 - Prob. PMCh. 9 - Prob. QMCh. 9 - Prob. 1MCCh. 9 - Prob. 2MCCh. 9 - Prob. 3MCCh. 9 - Prob. 4MCCh. 9 - Prob. 5MCCh. 9 - Prob. 6MCCh. 9 - Prob. 7MCCh. 9 - Prob. 8MCCh. 9 - Prob. 9MCCh. 9 - Prob. 10MCCh. 9 - Prob. 11MCCh. 9 - Prob. 12MCCh. 9 - Prob. 13MCCh. 9 - Prob. 14MCCh. 9 - Prob. 1FIBCh. 9 - Prob. 2FIBCh. 9 - Prob. 3FIBCh. 9 - Prob. 4FIBCh. 9 - Prob. 5FIBCh. 9 - Prob. 6FIBCh. 9 - Prob. 7FIBCh. 9 - Prob. 8FIBCh. 9 - Prob. 9FIBCh. 9 - Prob. 10FIBCh. 9 - Prob. 11FIBCh. 9 - Prob. 12FIBCh. 9 - Prob. 1SACh. 9 - Prob. 2SACh. 9 - Prob. 3SACh. 9 - Prob. 4SACh. 9 - Prob. 5SACh. 9 - Prob. 6SACh. 9 - Prob. 7SACh. 9 - Prob. 8SACh. 9 - Prob. 9SACh. 9 - Prob. 10SACh. 9 - Prob. 11SACh. 9 - Prob. 12SACh. 9 - Prob. 13SACh. 9 - Prob. 14SACh. 9 - Prob. 15SACh. 9 - Prob. 16SACh. 9 - Prob. 17SACh. 9 - Prob. 18SACh. 9 - Prob. 19SACh. 9 - Prob. 20SACh. 9 - Prob. 21SACh. 9 - Prob. 22SACh. 9 - Prob. 23SACh. 9 - Prob. 24SACh. 9 - Prob. 25SACh. 9 - Prob. 26SACh. 9 - Prob. 27SACh. 9 - Prob. 28SACh. 9 - Prob. 29SACh. 9 - Prob. 30SACh. 9 - Prob. 31SACh. 9 - Prob. 32SACh. 9 - Prob. 33SACh. 9 - Prob. 34SACh. 9 - Visualize the connection for the descriptions of...Ch. 9 - Prob. 1AYKCh. 9 - Prob. 2AYKCh. 9 - Prob. 3AYKCh. 9 - Prob. 4AYKCh. 9 - Prob. 5AYKCh. 9 - Prob. 1ECh. 9 - Prob. 2ECh. 9 - Prob. 3ECh. 9 - Prob. 4ECh. 9 - Prob. 5ECh. 9 - Prob. 6ECh. 9 - Prob. 7ECh. 9 - Prob. 8ECh. 9 - Prob. 9ECh. 9 - Prob. 10ECh. 9 - Prob. 11ECh. 9 - Prob. 12E
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- Photons of a certain ultraviolet light have an energy of 6.70 ✕ 10−19 J. (a) What is the frequency of this UV light? Hz(b) Use ? = c/f to calculate its wavelength in nanometers (nm). nmarrow_forward1. An incoming light beam has frequency 9.7 x 1014 Hz. (Use h=6.626 x 10-34 J.s) a.) How much energy in Joules does it have? b.) If the photons of this light beam are absorbed by a free electron, how much kinetic energy and speed will the free electron have?arrow_forwardWhat will be the energy associated with a red photon, if the wavelength of the red light is 650 nm? [Hint: Find the frequency of red light first to calculate the energy. Recall: c = .f] A. 650x10° J B. 6.5x10 J C. 4.6x1014 J D. 3.0x10-19 J E. 3.0x1019 Jarrow_forward
- Example: An electron in a hydrogen atom drops from energy level E4 to energy level E2. What is the frequency of the emitted photon, and which line in the emission spectrum corresponds to this event? E6 E = -0.378 eV Step 1: Es E = -0.544 eV - E= -0.850 eV Find the energy of the photon. E E = Einitial - Efinal E3 E=-1.51 eV = (-0.850 eV) - (-3.40 eV) = 2.55 eV Step 2: Use Plank's equation for frequency. E₂ E= -3.40 eV 12 E E = hf; f = h (2.55 eV) (1.60 x 10-191 6.63 x 10-34 Js f= 6.15 x 10¹4 Hz Line 3 is in the visible part of the electromagnetic spectrum and appears to be blue. The frequency f = 6.15 x 10¹4 Hz lies within the range of the visible spectrum and is toward the violet end, so it is reasonable that light of this frequency would be visible blue light. Step 3: Find the corresponding line in the emission spectrum. Examination of the diagram shows that the electron's jump from energy level E4 to energy level E2 corresponds to Line 3 in the emission spectrum. 3 Incoming photon…arrow_forward1. A cube of iron (atomic number 26), whose side measures 1 ft (30.48cm), is floating in a dark space. It is observed to emit blackbody radiation at the power of 200oW. (a) Would you dare to touch it for $20? Find the temperature of the cube before you answer. (b) Find the peak frequency of the spectrum, and compute the energy of photon at the frequency. Give the energy in units of electron-volt (eV). (c) What would be the temperature for the radiation if the cube were made of alu- minum (atomic number 13)?arrow_forwardThe attached image shows current-versus-voltage curves for the photoelectric effect using light with a mix of three frequencies f₁, f2, and f3. Explain the graph and the shape of the curves in a few sentences. Include the meaning of the voltage-intercepts (-V) and which frequency is highest and lowest. Responses Photoelectric current J2 Ju √3 f₁ -V01 - V02-V03 Photon intensity & constant = Applied voltagearrow_forward
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