Chemistry
Chemistry
4th Edition
ISBN: 9780393919370
Author: Thomas R. Gilbert
Publisher: NORTON
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Chapter 9, Problem 9.92QP

(a)

Interpretation Introduction

Interpretation: The electronic configuration and the stability of He2+andNe2+ as compared to He2andNe2 is to be predicted.

Concept introduction: When two atomic orbitals come close to each other they lose their identity and form new pair of orbitals knows as molecular orbitals. Among the two molecular orbitals formed one has energy lower than the atomic orbitals is known as bonding molecular orbital and the other has energy higher than the atomic orbitals and is known as antibonding molecular orbital.

To determine: The electronic configuration of He2andNe2 .

(a)

Expert Solution
Check Mark

Answer to Problem 9.92QP

The electronic configuration of He2andNe2 is,

He2=1s)2*1s)2

Ne2=2s)2*2s)22p)22p)4*2p)4*2p)2

Explanation of Solution

Explanation

Helium has two valence electrons.

The total number of valence electrons in He2 is calculated by formula,

Totalnumberofvalenceelectrons=NumberofHeatoms×Valenceelectrons ±Charge=2×20=4

According to the molecular orbital theory the electronic configuration of N2+ is

He2=1s)2*1s)2

Neon has eight valence electrons.

The total number of valence electrons in Ne2 is calculated by formula,

Totalnumberofvalenceelectrons=NumberofNeatoms×Valenceelectrons ±Charge=2×81=16

According to the molecular orbital theory the electronic configuration of Ne2 is

Ne2=2s)2*2s)22p)22p)4*2p)4*2p)2

(b)

Interpretation Introduction

To determine: The stability of the molecular ions formed by removing one electron from He2andNe2 .

(b)

Expert Solution
Check Mark

Answer to Problem 9.92QP

The molecular ions Ne2+ and He2+ are more stable than He2andNe2 .

Explanation of Solution

Explanation

On removing an electron from He2 , it becomes He2+ .

The total number of valence electrons in He2+ is calculated by formula,

Totalnumberofvalenceelectrons=NumberofHeatoms×Valenceelectrons ±Charge=2×21=3

According to the molecular orbital theory the electronic configuration of He2+ is

He2+=1s)2*1s)1

The bond order of He2+ is calculated by formula,

Bondorder=12(NumberofelectronsinbondingmolecularorbitalsNumberofelectroninantibondingmolecularorbitals)=12(21)=0.5

The bond order of He2+ is 0.5 .

On removing an electron from Ne2 it becomes Ne2+ ion.

The total number of valence electrons in Ne2+ is calculated by the formula,

Totalnumberofvalenceelectrons=NumberofNeatoms×Valenceelectrons±Charge=2×81=15

According to the molecular orbital theory the electronic configuration of Ne2+ is,

Ne2+=2s)2*2s)24p)22p)4*2p)4*2p)2

The bond order of Ne2+ is calculated by formula,

Bondorder=12(NumberofelectronsinbondingmolecularorbitalsNumberofelectroninantibondingmolecularorbitals)=12(87)=0.5

The bond order of Ne2+ is 0.5

The stability of an ion or a molecule is directly proportional to its bond order.

Both Ne2+ and He2+ ions have non-zero bond order values.

The molecules He2andNe2 have bond order equal to zero.

Therefore, the molecular ions Ne2+ and He2+ are more stable than He2andNe2 .

The stability of an ion or a molecule is directly proportional to its bond order.

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Chapter 9 Solutions

Chemistry

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