Chemistry
Chemistry
4th Edition
ISBN: 9780393919370
Author: Thomas R. Gilbert
Publisher: NORTON
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Chapter 9, Problem 9.58QP

(a)

Interpretation Introduction

To determine: The hybridization of sulfur in SO molecule.

Interpretation: The hybridization of sulfur in SO molecule is to be predicted.

Concept introduction: The hybridization of molecule is calculated by the formula,

H=12(V+MC+A)

(a)

Expert Solution
Check Mark

Answer to Problem 9.58QP

The hybridization of sulfur in SO molecule is sp2.

Explanation of Solution

The electronic configuration of sulfur is [Ne]3s23p4.

The electronic configuration of oxygen is [He]2s22p4.

The hybridization of molecule is calculated by the formula,

H=12(V+MC+A)

Where,

  • V is the number of valance electrons in central metal atom.
  • M is the number of monovalent atoms attached with central metal atom.
  • C is the cationic charge.
  • A is the anionic charge.

The number of valance electron in sulfur is 6.

Oxygen is a divalent atom.

The cationic and anionic charge of SO molecule is zero.

Substitute the number of valance electrons of sulfur in above formula.

H=12(60+0)=3

The hybridization number 3 indicates that the hybridization of sulfur in SO molecule is sp2.

(b)

Interpretation Introduction

To determine: The hybridization of sulfur in SO2 molecule.

Interpretation: The hybridization of sulfur in SO2 molecule is to be predicted.

Concept introduction: The hybridization of molecule is calculated by the formula,

H=12(V+MC+A)

(b)

Expert Solution
Check Mark

Answer to Problem 9.58QP

The hybridization of sulfur in SO2 molecule is sp2.

Explanation of Solution

The electronic configuration of sulfur is [Ne]3s23p4.

The electronic configuration of oxygen is [He]2s22p4.

The hybridization of molecule is calculated by the formula,

H=12(V+MC+A)

Where,

  • V is the number of valance electrons in central metal atom.
  • M is the number of monovalent atoms attached with central metal atom.
  • C is the cationic charge.
  • A is the anionic charge.

The number of valance electron in sulfur is 6.

Oxygen is a divalent atom.

The cationic and anionic charge of SO2 molecule is zero.

Substitute the number of valance electrons of sulfur in above formula.

H=12(60+0)=3

The hybridization number 3 indicates that the hybridization of sulfur in SO2 molecule is sp2.

(c)

Interpretation Introduction

To determine: The hybridization of sulfur in S2O molecule.

Interpretation: The hybridization of sulfur in S2O molecule is to be predicted.

Concept introduction: The hybridization of molecule is calculated by the formula,

H=12(V+MC+A)

(c)

Expert Solution
Check Mark

Answer to Problem 9.58QP

The hybridization of sulfur in S2O molecule is sp2.

Explanation of Solution

The electronic configuration of sulfur is [Ne]3s23p4.

The electronic configuration of oxygen is [He]2s22p4.

The hybridization of molecule is calculated by the formula,

H=12(V+MC+A)

Where,

  • V is the number of valance electrons in central metal atom.
  • M is the number of monovalent atoms attached with central metal atom.
  • C is the cationic charge.
  • A is the anionic charge.

The number of valance electron in sulfur is 6.

Oxygen is a divalent atom.

The cationic and anionic charge of S2O molecule is zero.

Substitute the number of valance electrons of sulfur in above formula.

H=12(60+0)=3

The hybridization number 3 indicates that the hybridization of sulfur in S2O molecule is sp2.

(d)

Interpretation Introduction

To determine: The hybridization of sulfur in SO3 molecule.

Interpretation: The hybridization of sulfur in SO3 molecule is to be predicted.

Concept introduction: The hybridization of molecule is calculated by the formula,

H=12(V+MC+A)

(d)

Expert Solution
Check Mark

Answer to Problem 9.58QP

The hybridization of sulfur in SO3 molecule is sp2.

Explanation of Solution

The electronic configuration of sulfur is [Ne]3s23p4.

The electronic configuration of oxygen is [He]2s22p4.

The hybridization of molecule is calculated by the formula,

H=12(V+MC+A)

Where,

  • V is the number of valance electrons in central metal atom.
  • M is the number of monovalent atoms attached with central metal atom.
  • C is the cationic charge.
  • A is the anionic charge.

The number of valance electron in sulfur is 6.

Oxygen is a divalent atom.

The cationic and anionic charge of SO3 molecule is zero.

Substitute the number of valance electrons of sulfur in above formula.

H=12(60+0)=3

The hybridization number 3 indicates that the hybridization of sulfur in SO3 molecule is sp2.

Conclusion
  1. a. The hybridization of sulfur in SO molecule is sp2.
  2. b. The hybridization of sulfur in SO2 molecule is sp2.
  3. c. The hybridization of sulfur in S2O molecule is sp2.
  4. d. The hybridization of sulfur in SO3 molecule is sp2.

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Chapter 9 Solutions

Chemistry

Ch. 9 - Prob. 9.1VPCh. 9 - Prob. 9.2VPCh. 9 - Prob. 9.3VPCh. 9 - Prob. 9.4VPCh. 9 - Prob. 9.5VPCh. 9 - Prob. 9.6VPCh. 9 - Prob. 9.7VPCh. 9 - Prob. 9.8VPCh. 9 - Prob. 9.9QPCh. 9 - Prob. 9.10QPCh. 9 - Prob. 9.11QPCh. 9 - Prob. 9.12QPCh. 9 - Prob. 9.13QPCh. 9 - Prob. 9.14QPCh. 9 - Prob. 9.15QPCh. 9 - Prob. 9.16QPCh. 9 - Prob. 9.17QPCh. 9 - Prob. 9.18QPCh. 9 - Prob. 9.19QPCh. 9 - Prob. 9.20QPCh. 9 - Prob. 9.21QPCh. 9 - Prob. 9.22QPCh. 9 - Prob. 9.23QPCh. 9 - Prob. 9.24QPCh. 9 - Prob. 9.25QPCh. 9 - Prob. 9.26QPCh. 9 - Prob. 9.27QPCh. 9 - Prob. 9.28QPCh. 9 - Prob. 9.29QPCh. 9 - Prob. 9.30QPCh. 9 - Prob. 9.31QPCh. 9 - Prob. 9.32QPCh. 9 - Prob. 9.33QPCh. 9 - Prob. 9.34QPCh. 9 - Prob. 9.35QPCh. 9 - Prob. 9.36QPCh. 9 - Prob. 9.37QPCh. 9 - Prob. 9.38QPCh. 9 - Prob. 9.39QPCh. 9 - Prob. 9.40QPCh. 9 - Prob. 9.41QPCh. 9 - Prob. 9.42QPCh. 9 - Prob. 9.43QPCh. 9 - Prob. 9.44QPCh. 9 - Prob. 9.45QPCh. 9 - Prob. 9.46QPCh. 9 - Prob. 9.47QPCh. 9 - Prob. 9.48QPCh. 9 - Prob. 9.49QPCh. 9 - Prob. 9.50QPCh. 9 - Prob. 9.51QPCh. 9 - Prob. 9.52QPCh. 9 - Prob. 9.53QPCh. 9 - Prob. 9.54QPCh. 9 - Prob. 9.55QPCh. 9 - Prob. 9.56QPCh. 9 - Prob. 9.57QPCh. 9 - Prob. 9.58QPCh. 9 - Prob. 9.59QPCh. 9 - Prob. 9.60QPCh. 9 - Prob. 9.61QPCh. 9 - Prob. 9.62QPCh. 9 - Prob. 9.63QPCh. 9 - Prob. 9.64QPCh. 9 - Prob. 9.65QPCh. 9 - Prob. 9.66QPCh. 9 - Prob. 9.67QPCh. 9 - Prob. 9.68QPCh. 9 - Prob. 9.69QPCh. 9 - Prob. 9.70QPCh. 9 - Prob. 9.71QPCh. 9 - Prob. 9.72QPCh. 9 - Prob. 9.73QPCh. 9 - Prob. 9.74QPCh. 9 - Prob. 9.75QPCh. 9 - Prob. 9.76QPCh. 9 - Prob. 9.77QPCh. 9 - Prob. 9.78QPCh. 9 - Prob. 9.79QPCh. 9 - Prob. 9.80QPCh. 9 - Prob. 9.81QPCh. 9 - Prob. 9.82QPCh. 9 - Prob. 9.83QPCh. 9 - Prob. 9.84QPCh. 9 - Prob. 9.85QPCh. 9 - Prob. 9.86QPCh. 9 - Prob. 9.87QPCh. 9 - Prob. 9.88QPCh. 9 - Prob. 9.89QPCh. 9 - Prob. 9.90QPCh. 9 - Prob. 9.91QPCh. 9 - Prob. 9.92QPCh. 9 - Prob. 9.93QPCh. 9 - Prob. 9.94QPCh. 9 - Prob. 9.95QPCh. 9 - Prob. 9.96QPCh. 9 - Prob. 9.97QPCh. 9 - Prob. 9.98QPCh. 9 - Prob. 9.99QPCh. 9 - Prob. 9.100QPCh. 9 - Prob. 9.101APCh. 9 - Prob. 9.102APCh. 9 - Prob. 9.103APCh. 9 - Prob. 9.104APCh. 9 - Prob. 9.105APCh. 9 - Prob. 9.106APCh. 9 - Prob. 9.107APCh. 9 - Prob. 9.108APCh. 9 - Prob. 9.109APCh. 9 - Prob. 9.110APCh. 9 - Prob. 9.111APCh. 9 - Prob. 9.112APCh. 9 - Prob. 9.113APCh. 9 - Prob. 9.114APCh. 9 - Prob. 9.115APCh. 9 - Prob. 9.116APCh. 9 - Prob. 9.117APCh. 9 - Prob. 9.118APCh. 9 - Prob. 9.119APCh. 9 - Prob. 9.120APCh. 9 - Prob. 9.121APCh. 9 - Prob. 9.122APCh. 9 - Prob. 9.123APCh. 9 - Prob. 9.124APCh. 9 - Prob. 9.125APCh. 9 - Prob. 9.126APCh. 9 - Prob. 9.127APCh. 9 - Prob. 9.128AP
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