Principles of Foundation Engineering (MindTap Course List)
9th Edition
ISBN: 9781337705028
Author: Braja M. Das, Nagaratnam Sivakugan
Publisher: Cengage Learning
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Question
Chapter 9, Problem 9.6P
To determine
Find the elastic settlement below the middle of the given foundation.
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IV. A soil element is shown in Figure 3. (use equations)
130 kN/m²
+35kN/m²
30⁰
60 kN/m²
10
11.
12
+
+
B
SITY
FICAT
35 kN/m²
Figure 3
What is the value of the maximum stress in kPa?
What is the value of the normal stress acting at the plane AB in kPa?
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Q1
A 25 m thick layer of clay is underlain by a layer of
silt, as shown in the Figure.
1. Determine the effective stress at point A when Z=3 m.
2. Determine the effective stress at point B when h=3 m.
3. By changing h and Z, would you expect that the
effective stresses at A and B can have the same value?
WIZ 1²
W.T
12 m
B
Clay e=0.6, G.-2.69
Clay w=30%
Silt w=50%, G, 2.70
10.19 Refer to Figure 10.46. A flexible rectangular area is subjected to a uniformly dis-
tributed load of q = 225 kN/m². Determine the increase in vertical stress, Ao, at a
depth of z = 3 m under points A, B, and C.
6 m
-2.4 m-
3m
1.2 m
q- 225 kN/m2
E1.8 m→
Figure 10.46
U--
Cangage Leaming 2014
Chapter 9 Solutions
Principles of Foundation Engineering (MindTap Course List)
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- Determine the average stress increase below the center of the loaded area, between z = 3 m and z = 5 m. 5 m 3 m q=100 kN/m² L 1.5 m 1.5 m A J SECTION 3 m B L A 3 m PLAN VIEWarrow_forwardFrom the given soil formation of the soil with the following properties is shown in the figure. (see picture below) Compute the total stress at the mid-layer of the clay. (Answer: 260.745 kPa) Compute the effective stress at the mid layer of the clay. (Answer: 147.93 kPa) If a load of 1800 kN is acting on the footing 2m x 2m is placed on the ground, find the stress increase at the mid layer of the clay assuming a stress distribution of 1 horizontal to 2 vertical. (Answer: 11.64 kPa) *unit weight of dry sand = 14.72 kN/m3*arrow_forwardA 25 m thick layer of clay is underlain by a layer of silt, as shown in the Figure. 1. Determine the effective stress at point A when Z = 3 m. 2. Determine the effective stress at point B when h=3 m. 3. By changing h and Z, would you expect that the effective stresses at A and B can have the same value? wy Z 12 m B Clay e=0.6, G₁-2.69 Clay w=30% Silt w=50%, G,=2.70arrow_forward
- A uniform loading of 150kPa is applied at a 28 m Χ 28 m area. Please calculate the consolidation settlement of the clay layer used the middle of the clay layer to estimate the stress increment with the influence factor method). Cc = 0.4, Cs = 0.04, preconsolidation stress is 150 kPa and unit weight of water is 10 kN/m3. What is the settlement at the corner and center of the loading? What is the differential settlement between the corner and the center?arrow_forward3. The uniformly distributed vertical loads on the surface of a clay layer as shown in Figure below. Determine the vertical stress increase at A and B due to the loaded area. A and B are located at a depth of 5 m below the ground surface. y 2m q=200 kN/m² +—— 5—+— 2m q2 =150 kN/m² 8 3 Xarrow_forwardFrom the given Figure, determine the following: a. Effective stress at the bottom of the clay b. if the water table rises to the level of the soil surface, what is the effective stress at the bottom of the clay. c. if the water is 3m above the soil surface, what is the effective stress at the bottom of the clay. 4m 5m 156 kN/m² 16.6 kN/m² Water table Y = 17,8 kN/marrow_forward
- 2 m e = 0.53 Gs = 2.65 A 4 m Dry Sand e = 0.47 6 m Saturated Sand Gs = 2.67 a. Determine the effective stress at point A in kPa. b. Determine the effective stress at point B in kPa. b. Determine the effective stress at point C in kPa. c. Determine how high (m) from point B will the water table rise up so that the effective stress at C is 125 kpa.arrow_forwardA. Compute the effective stress at the bottom of the clay. B. If the water table rises to the level of the soil surface, what is the effective stress at the bottom of the clay? Fground surface Y-15.6 kN/m Yrar-16.6 KN/m3 4 m water table Clay 5 m:arrow_forwardThe vertical surface stress is 100 kPa. The stress increase (kPa) at A is 2m 100 kPa 2m 2m A B 1m 7.3 O 12.0 19.3 Use the approximate method to estimate the stress (kPa) under the center of a rectangular loaded area 2 m X 3 m at a .depth of 2 m, if the vertical load is 20 kN 1.67 O 1 O 2 Oarrow_forward
- Refer to the figure below. Given: q1 = 100kN/m, q2 = 200 kN/m X1 = 3m, x2 = 3m, z = 3m Determine the vertical stress increase at point A. (11.46) Line load = 4, Line load = q, x1 Aarrow_forward8.13 Refer to Figure P8.13. Determine the average stress increase in the clay layer below the center of the foundation due to the net foundation load of 900 kN. 900 kN (net load) 1.52 m 1.83 mx 1.83 m Sand y= 15.7 kN/m³ Water table 1.22 m 3.05 m Sand Ysat 19.24 kN/m³ = Ysat 19.24 kN/m³ = eo= 0.68 - C=0.25 C₁ = 0.06 Preconsolidation pressure = 100 kN/m² Figure P8.13arrow_forwardA flexible rectangular area is subjected to a uniformly distributed load of q = 225 kN/m. Determine the increase in vertical stress, Ao, at a depth of z= 2 m at Point A. 0.5 m 1m 0.5 m 1m Point Aarrow_forward
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