Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN: 9781305632134
Author: J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher: Cengage Learning
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Chapter 9, Problem 9.57P
To determine
To explain: The reason for the phase angle on one phase is always zeroduring the line to ground fault.
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7.In a line-to-ground fault we can expect that
A) There are no currents to ground.
B) The voltages at the fault point with respect to ground are zero in all three phases.
C) The current in the faulted phase flows to ground.
D) There are short circuit currents in all three phases.
E) N. A.
Q.3
When a line-to-ground fault occurs, the
current in faulted phase 'a' is 100A. The
zero-sequence current in phase 'c' is
A line-to-ground fault occurs, and the current in faulted
phase 'a' is 100A. Find the zero-sequence current in
phase 'c'.
Chapter 9 Solutions
Power System Analysis and Design (MindTap Course List)
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- In a short circuit test on 132 kV, 3-phase system, the breaker gives the following results: Power factor of the fault = 0.45. Recovery voltage 0.9 time of full line voltage. The breaking current is symmetrical. The restriking transient has a natural frequency of 15 kHz. Calculate the rate of rise of restriking voltage (RRRV) in the following types of faults: (1) Grounded fault (2) Undergrounded fault.arrow_forwardThree 6.6 kV altemators of ratings 8 MVA, 2 MVA and 5 MVA have per unit reactances of 0.16, 0.08 and 0.12 respectively and are connected to a common bus bar. A 3-phase fault occurs on a feeder which takes off from the bus. The reactance of the feeder from the bus to the fault point is 0.125 ohm. Find the fault MVA. [87.2 MVA]arrow_forwardcomplet The equivalent reactance of the double circuit line under post fault condition is................than fault condition.arrow_forward
- In the figure below, all impedances are in per unit on a common MVA base. The generators are operating on no load at their rated voltage. A three-phase fault occurs at bus 1 through a fault impedance of Zf = jo.o8 per unit. Find Vi during the fault in per unit. X, = 0.1 Ooto X 0.1 X =0.2 X-0.1 O a. vi(n=0.4 p.u O b. vif)=0.5 p.u OC V1(0=0.6 pu VI=0.7 p.uarrow_forward4.In a double line-to-ground fault we can expect thatImmersive reader A) There are currents in the ground connections. B) The current values in the ground connections are zero. C) Short-circuit currents exist in all three phases. D) The currents in the faulted phases are equal. E) N. A.arrow_forwardPlease answer. Thank you! Discuss the fault analysis in series-parallel circuits.arrow_forward
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