Understanding Our Universe
3rd Edition
ISBN: 9780393614428
Author: PALEN, Stacy, Kay, Laura, Blumenthal, George (george Ray)
Publisher: W.w. Norton & Company,
expand_more
expand_more
format_list_bulleted
Videos
Question
Chapter 9, Problem 45QAP
To determine
The amount of material falls on the Earth from meteorite each day; the amount of material falls on the Earth from meteorite each year; the time taken by material to double the mass of Earth.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
The Mars Robotic Lander for which we are making these calculations is designed to return samples of rock from Mars after a long time of collecting samples, exploring the area around the landing site, and making chemical analyses of rocks and dust in the landing area. One synodic period is required for Earth to be in the same place relative to mars as when it landed.
Calculate the synodic period (in years) using the following formula:
1/Psyn = (1/PEarth) - (1/PMars)
where PEarth is the sidereal period of the Earth (1 year) and PMars is the sidereal period of Mars.
If 3/4 of a Martian year was spent collecting samples and exploring the terrain around the landing site, calculate how long the Mars Robotic Lander expedition took!
If the satellite was placed in an orbit three times farther away, about how long would it take to orbit the Earth once? Answer in days, rounding to one significant figure.days
Mars rotates on its axis once every 1.02 days (almost the same as Earth does).
(a) Find the distance from Mars at which a satellite would remain in one spot over the Martian surface. (Use 6.42 1023 kg for the mass of Mars.)m(b) Find the speed of the satellite.m/s
The chart shows the length of time for each planet, in Earth days, to make one complete
revolution around the Sun.
Orbital Period of Planets iY
the Solar System
Orbital Period
(Earth days)
88
225
365
687
4333
10 759
30 685
60 189
Planet
Mercury
Venus
Earth
Mars
Jupiter
Satum
Uranus
Neptune
Source: NASA
Use the data table above to compare the length of a year on Mars and Neptune. (HS-ESS1-4)
a. One year on Neptune is almost 100 times longer than a year on Mars.
b. One year on these two planets is nearly equal.
c. One year on Mars is almost 100 times longer than a year on Neptune.
d. One year these two planets is roughly equal to a year on Earth.
Use the data table above to determine which of the following statements is TRUE. (HS-ESS1-4)
a. There is no relationship between a planet's distance from the Sun and its length of
year.
b. The closer a planet is to the Sun, the longer the planet's year.
c. One year on all planets is about 365 days long.
d. The farther away a planet is from the…
Chapter 9 Solutions
Understanding Our Universe
Ch. 9.1 - Prob. 9.1CYUCh. 9.2 - Prob. 9.2CYUCh. 9.3 - Prob. 9.3CYUCh. 9.4 - Prob. 9.4CYUCh. 9.5 - Prob. 9.5CYUCh. 9.6 - Prob. 9.6CYUCh. 9 - Prob. 1QAPCh. 9 - Prob. 2QAPCh. 9 - Prob. 3QAPCh. 9 - Prob. 4QAP
Ch. 9 - Prob. 5QAPCh. 9 - Prob. 6QAPCh. 9 - Prob. 7QAPCh. 9 - Prob. 8QAPCh. 9 - Prob. 9QAPCh. 9 - Prob. 10QAPCh. 9 - Prob. 11QAPCh. 9 - Prob. 12QAPCh. 9 - Prob. 13QAPCh. 9 - Prob. 14QAPCh. 9 - Prob. 15QAPCh. 9 - Prob. 16QAPCh. 9 - Prob. 17QAPCh. 9 - Prob. 18QAPCh. 9 - Prob. 19QAPCh. 9 - Prob. 20QAPCh. 9 - Prob. 21QAPCh. 9 - Prob. 22QAPCh. 9 - Prob. 23QAPCh. 9 - Prob. 24QAPCh. 9 - Prob. 25QAPCh. 9 - Prob. 26QAPCh. 9 - Prob. 27QAPCh. 9 - Prob. 28QAPCh. 9 - Prob. 29QAPCh. 9 - Prob. 30QAPCh. 9 - Prob. 31QAPCh. 9 - Prob. 32QAPCh. 9 - Prob. 33QAPCh. 9 - Prob. 34QAPCh. 9 - Prob. 35QAPCh. 9 - Prob. 36QAPCh. 9 - Prob. 37QAPCh. 9 - Prob. 38QAPCh. 9 - Prob. 39QAPCh. 9 - Prob. 40QAPCh. 9 - Prob. 41QAPCh. 9 - Prob. 42QAPCh. 9 - Prob. 43QAPCh. 9 - Prob. 44QAPCh. 9 - Prob. 45QAP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- During a retrograde loop of Mars, would you expect Mars to be brighter than usual in the sky, about average in brightness, or fainter than usual in the sky? Explain.arrow_forwardThe gravity on Mars is about 38% that of Earth's gravity. Let's say some cargo has a mass of 15 kg here on Earth. First, what would be the weight of that cargo in kilograms on Mars? Explain your answer. Second, what would be the mass of that cargo in kilograms on Mars? Explain your answer.arrow_forwardThe Msbar Alamal on its journey to Mars took a 7-month period, during which it traveled an estimated distance of 493 million kilometers. What was the distance covered during a 7-day period?arrow_forward
- The value we have just calculated is the combined masses of Jupiter and Callisto! Their mass is in units of the Sun's Mass (MS) - we can convert this to units which are more familiar to us like kilograms by multiplying this answer by the scale factor (1.99x1030 kg/1 MS): (MJupiter + MCallisto) = ( MS) (1.99x1030 kg/1 Solar Mass) = _______x_10___ kg (I have already written the x 10 so you are reminded to write the exponenet of 10 in the scientific notation expression of your answer). Since you know from looking at pictures of Jupiter with its Galilean Satellites (look in your book at a picture if you have not already), that Callisto is much smaller than Jupiter - in fact it is less than 0.001 of Jupiter's size or mass, so the number we have just calculated for (MJupiter + MCallisto) is almost the same as MJupiter . How much more massive is Jupiter than the Earth? (The mass of Earth is about 5.98 x 1024 kg)arrow_forwardA lot of asteroid and comet dust collides with Earth's atmosphere everyday. Assume that 500 tons of mass is added to Earth daily from the millions of meteors that enter our atmosphere. Estimate the time it would take for the Earth's mass to increase 0.2% with this impact rate. Is this mass accumulation significant to Earth as a planet.arrow_forwardIf we treat the mass of Earth as 1, and the radius of Earth as 1, the escape velocity of a planet with 4 times the mass of Earth and the same radius will be: 1) 1. 4 times greater 2) 2 times greater 3) 4 times greater 4) 0.5 times greaterarrow_forward
- Ex/13: The mean radius of earth is 6400 km. The acceleration due to gravity at its surface is 9.8 m/s². Estimate the mass of earth. "" 11 › (G = 6.67 × 10-¹¹ Nm²/kg²)arrow_forwardGive me the solution for the problem. The correct answers are: A: -1.4 x 10-6 km/h. The comet's speed has been decreased by this amount. Hence, the effect is negligble. B: -6.7 x 10-8 km/h. The Earth's speed has been decreased by this amount. Also, the effect is negligble.arrow_forwardhow many seconds are in a mars year that has approx 678 earth days ?arrow_forward
- A 1200-kilogram car is cruising at a constant speed of 22 meters/second (50 miles/hour). What is the net force on the car? In the previous problem if the car begins losing speed at a rate of 1 meter/second per second. What is the size of the net force on the car?arrow_forwardPlease answer the question and subquestions completely! This is one whole question which has subquestions! According to the official Bartleby guidelines, each question can have up to two subquestions! Thank you! 1) A missile is launched upward with a speed that is half the escape speed. What height (in radii of Earth) will it reach? R/4 R/3 R/2 R 2R A) The weight of a 0.60 kg object at the surface of Planet V is 20 N. The radius of the planet is 4 x 10 6 m. Find the gravitational acceleration at a distance of 2 x 10 6 m from the surface of this planet. 8.9 m/s2 11 m/s2 13 m/s2 18 m/s2 B) Two masses are precisely 1 m apart from each other. The gravitational force each exerts on the other is exactly 1 N. If the masses are identical, what is each mass? 1.22 x 105 kg 1.34 x 1010 kg 2.50 x 105 kg 1.58 x 1010 kgarrow_forwardFor the planet Saturn,What is its diameter in Earth diameters (what multiple of Earth's diameter)?What is its mass in Earth masses (what multiple of Earth's mass)?What is its average density (kg/m3)arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Kepler's Three Laws Explained; Author: PhysicsHigh;https://www.youtube.com/watch?v=kyR6EO_RMKE;License: Standard YouTube License, CC-BY